WGU C992 Task 2 Passed (2026) – Midpoint & Triangle Analysis | College Geometry

C992
College Geometry
TASK 2 – Passed
Midpoint & Triangle Analysis
Western Governors University

, College Geometry C992
Task 2: Midpoint & Triangle Analysis
A1)
According to the key provided, Point M is the midpoint of the line
segment KN. The coordinates for point K are (1,1), and the
coordinates for point N are (2,1).
Using the midpoint formula and the coordinates given for points K
and N, we can find the coordinates for point M.


( x +2 x , y +2 y )→( 1+22 , 1+12 )→( 32 , 22 )→ ( 1.5 , 1)
1 2 1 2




The coordinates for point M are (1.5, 1)

A2a)

An isosceles triangle is a triangle with 2 sides of equal length. To
prove an isosceles triangle, you will use the distance formula.

∆SKP consists of point S (1,0), point K (1,1), and point P (1.5,0.5).
Using the distance formula, we can calculate the length of each line
segment (SK, KP, and SP) connecting the points.

√ 2
d= ( x 2−x 1 ) + ( y 2− y 1 )
2




SK = √ ( 1−1 ) + ( 1−0 ) → SK = √ ( 0 ) + ( 1 ) → SK = √ 1
2 2 2 2




SK = 1

KP= √ ( 1.5−1 ) + ( 0.5−1 ) → KP= √ ( 0.5 ) + (−0.5 ) → KP= √ 0.5
2 2 2 2




KP = 0.71

SP= √ ( 1.5−1 ) + ( 0.5−0 ) → SP= √ ( 0.5 ) + ( 0.5 ) → SP= √ 0.5
2 2 2 2




SP = 0.71

The three side lengths of the triangle are 1, 0.71, and 0.71. Lines KP
and SP are the same measure. Therefore, ∆SKP is an isosceles
triangle.


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