Finite Mathematics
TASK 2 – Passed
Number Theory
Western Governors University
, Part 1: Order of Operations
Figure 1:
Expression A:
2 3 The order of operation states that we must first
(−3) +14 ÷2*[(6−8) −(−4)]
3 2 solve all operations inside groupings. These will
−[|−2| −1+5 ] include parentheses, brackets, braces, and absolute
values. A fraction bar can also be considered a
grouping.
3
Looking at the grouping [(6 − 8) − (− 4)] in the
numerator, I would start by subtracting the 6 from 8
to get -2. Next, I would need to change the -4 to a
positive 4 and change the sign to addition. This is
due to the fact when you subtract a negative number
it becomes a positive. This would leave us with
3
[(− 2) + 4]. This grouping is not completely
solved as there are groupings inside the other
groupings. We would now need to solve the
exponent, which would give us − 8 + 4. To finish
out the grouping, we would solve − 8 + 4 to get
− 4.
The grouping |− 2| in the denominator, we would
solve is the absolute value. This would give us 2
2 The order of operation states that we would solve all
(−3) +14÷2*(−4)
3 2 exponents next.
−[(2 )−1+5 ] 2
In the numerator, we would solve (− 3) . Since the
-3 is in parentheses this will mean that we multiple
-3 by -3 to give us 9. If the negative was not in
parentheses it would not have been included in the
exponent.
In the denominator, we have two different
3 2
exponents to solve, (2 ) 𝑎𝑛𝑑 5 . These would equal
8 and 25, respectively.
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