QTT2
Finite Mathematics
TASK 3 – Passed
Discrete Mathematics
Western Governors University
, Part 1: Set Theory
Figure 1:
Part A:
A = 2,001 Students to complete Philosophy
B = 1,064 Students to complete Chemistry
C = 2,538 Total Students
Part B:
Group 1 is the group that has completed philosophy, group A.
Group 2 is the group that has completed chemistry, group B.
In Group 1 and Group 2: A ∩ B
In Group 2 but not Group 1: B ∩ A’
In Group 1 or Group 2: A ∪ B
In neither Group 1 nor Group 2: A’ ∪ B’
Correction: In neither Group 1 nor Group 2: 𝐶 − (𝐴 ∪ 𝐵)
Part C:
In both Group 1 and Group 2: To find the number of students who took both philosophy and
chemistry, I would start by subtracting the number of philosophy students who did not take chemistry
from the total number of philosophy students. 2, 001 − 1, 333 = 668. This means that 668 students
took both Chemistry and Philosophy.
In Group 2 but not Group 1: To find the number of students that took chemistry but not philosophy, I
would need to subtract the number of students who took both from the number of students that only
took chemistry. 1, 064 − 668 = 396. This would mean that 396 students took only chemistry.
This study source was downloaded by 100000901969919 from CourseHero.com on 11-01-2025 18:30:17 GMT -05:00
https://www.coursehero.com/file/240890605/QTT2-Task-3-Brittney-Alimpdf/
Finite Mathematics
TASK 3 – Passed
Discrete Mathematics
Western Governors University
, Part 1: Set Theory
Figure 1:
Part A:
A = 2,001 Students to complete Philosophy
B = 1,064 Students to complete Chemistry
C = 2,538 Total Students
Part B:
Group 1 is the group that has completed philosophy, group A.
Group 2 is the group that has completed chemistry, group B.
In Group 1 and Group 2: A ∩ B
In Group 2 but not Group 1: B ∩ A’
In Group 1 or Group 2: A ∪ B
In neither Group 1 nor Group 2: A’ ∪ B’
Correction: In neither Group 1 nor Group 2: 𝐶 − (𝐴 ∪ 𝐵)
Part C:
In both Group 1 and Group 2: To find the number of students who took both philosophy and
chemistry, I would start by subtracting the number of philosophy students who did not take chemistry
from the total number of philosophy students. 2, 001 − 1, 333 = 668. This means that 668 students
took both Chemistry and Philosophy.
In Group 2 but not Group 1: To find the number of students that took chemistry but not philosophy, I
would need to subtract the number of students who took both from the number of students that only
took chemistry. 1, 064 − 668 = 396. This would mean that 396 students took only chemistry.
This study source was downloaded by 100000901969919 from CourseHero.com on 11-01-2025 18:30:17 GMT -05:00
https://www.coursehero.com/file/240890605/QTT2-Task-3-Brittney-Alimpdf/
