Exam 3: Chapters 12-15
Question 1 (2.5 points)
Why is working with linked genes not simple?
Question 1 options:
potential of crossing over in meiosis I
potential of independent assortment in meiosis I
they reside on different chromosomes
one gene often masks the other gene
Question 2 (2.5 points)
Prokaryotes are able to perform transcription and translation at the same
time because they lack
Question 2 options:
ribosomes
a nucleus
a plasma membrane
plasmids
transcription bubbles
Question 3 (2.5 points)
The allele for widows peak (H) is dominant for the allele for no widows peak
(h). At a different gene locus, the allele for hitchhikers thumb (D) is
dominant to the allele for non-hitchhikers thumb (d). A man is heterozygote
for the traits and marries a woman who has no widows peak and is
heterozygote for hitchhikers thumb. What is the man's genotype?
Question 3 options:
, BIOL133 Fall 2025
Exam 3: Chapters 12-15
HHDD
HhDd
HHdd
hhDD
hhdd
Question 4 (2.5 points)
In a monohybrid cross, the offspring would be what genotypes? Select all
that apply.
Question 4 options:
Homozygous recessive
Homozygous dominant
Heterozygotes
None of the above
Question 5 (2.5 points)
A child contains what proportion of their parent's genetic makeup?
Question 5 options:
33:67
25:75
50:50
40:60
Question 6 (2.5 points)
, BIOL133 Fall 2025
Exam 3: Chapters 12-15
An organism with nonfunctioning telomerase
Question 6 options:
would be unaffected
cannot replicate DNA and RNA
would have shorten chromosomes earlier than normal cells
would be unable to synthesize proteins
would be unable to go through mitosis
Question 7 (2.5 points)
What does a spliceosome remove from pre-mRNA during the process of
splicing?
Question 7 options:
introns
exons
spliceons
7-methlyguanosine
poly-A tail
Question 8 (2.5 points)
The part of the gene that is designated as +1 is also known as
Question 8 options:
the start codon
the initiation site