Finite Mathematics & Its Applications
13th Edition by Larry J. Goldstein,
Chapters 1 - 12, Complete
, Contents
Chapter 1: Linear Equations and Straight Lines 1–1
Chapter 2: Matrices 2–1
Chapter 3: Linear Programming, A Geometric Approach 3–1
Chapter 4: The Simplex Method 4–1
Chapter 5: Sets and Counting 5–1
Chapter 6: Probability 6–1
Chapter 7: Probability and Statistics 7–1
Chapter 8: Markov Processes 8–1
Chapter 9: The Theory of Games 9–1
Chapter 10: The Mathematics of Finance 10–1
Chapter 11: Logic 11–1
Chapter 12: Difference Equations and Mathematical Models 12–1
, Chapter 1
Exercises 1.1 5
6. Left 1, down
2
1. Right 2, up 3 y
Y
(2, 3)
X
X
( )
–1, – 52
7. Left 20, up 40
2. Left 1, up 4 Y
Y
(–20, 40)
(–1, 4)
X
X
8. Right 25, up 30
3. Down 2 Y
Y
(25, 30)
X
X
(0, –2)
9. Point Q is 2 units to the left and 2 units up or
4. Right 2
Y (—2, 2).
10. Point P is 3 units to the right and 2 units down or
(3,—2).
X
(2, 0)
1
11. —2(1) + (3) = — 2 +1 = —1so yes the point is
3
On the line.
5. Left 2, up 1 1
y 12. —2(2) + (6) = — 1 is false, so no the point is not
3
On the line
(–2, 1)
X
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, Chapter 1: Linear Equations and Straight Lines ISM: Finite Math
1 24. 0 = 5
13 — 2x + y = — 1 Substitute the x and y No solution
3
. X-intercept: none
Coordinates of the point into the equation:
h f h when x = 0, y = 5
‘f1,3I→ —2' 1 I + 1 (3) = —1 → —1+1 = —1 is y-intercept: (0, 5)
Y' ı 'y ıJ
2 J 2 3
A false statement. So no the point is not on 25. When y = 0, x = 7
theline. x-intercept: (7, 0)
f 1h 0=7
14 —2' I + ’f1Ih(—1) = —1 is true so yes the point is No solution
.
'y 3IJ 'y 3IJ y-intercept: none
On the line. 26. 0 = –8x
15. M = 5, b = 8 x=0
X-intercept: (0, 0)
16. M = –2 and b = –6 y = –8(0)
y=0
17. Y = 0x + 3; m = 0, b = 3 Y-intercept: (0, 0)
2 2, 1
y = x + 0; m = b = 0 27 0 = x –1
18 3
3 3 .
. x=3
19. 14x +7 y = 21 X-intercept: (3, 0)
1
7 y = —14x + 21 y = (0) – 1
3
y = —2x + 3
y = –1
Y-intercept: (0, –1)
20 X— y =3 Y
. —y = —x + 3
y = x —3
(3, 0)
21. 3x = 5 X
5 (0, –1)
x=
3
1 2
28. When x = 0, y = 0.
22 – x+ y = 10
. 2 3 When x = 1, y = 2.
2 1 Y
y = x +10
3 2
3
y = x +15 (1, 2)
4 X
(0, 0)
23. 0 = —4x + 8
4x = 8
x=2
X-intercept: (2, 0)
y = –4(0) + 8
y=8
Y-intercept: (0, 8)
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