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CEM 141 MSU 2026/2027 FINAL EXAM
COMPLETE CURRENT TESTING QUESTIONS
AND CORRECT VERIFIED ANSWERS FOR
GUARANTEED PASS/TOP-RATED A+.
CEM 141 MSU
Pass with confidence using the CEM 141 MSU Final Exam study
resource. It focuses on key topics such as stoichiometry, atomic
structure, chemical bonding, thermochemistry, and reaction
kinetics, commonly tested on the final. The exam-style
questions help reinforce problem-solving skills and conceptual
clarity. This resource is ideal for Michigan State University CEM
141 students and other introductory college chemistry learners
preparing for final exams.
How many core and valence electrons does one atom of
Iodine (I) have?
a. 36 core and 17 valence
b. 7 core and 36 valence
c. 36 core and 7 valence
d. 46 core and 7 valence ...... ANSWER ....... 46 core and 7
valence✓✓
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Nuclear reactions can release large amounts of energy
because:
a. Covalent bonds form during a nuclear reaction so energy
is released.
b. Part of the mass of the reactants is converted into energy.
c. Collisions between the reactants transfer energy into the
surroundings.
d. The strong nuclear force squeezes energy out of the
nuclei. ...... ANSWER ....... Part of the mass of the
reactants is converted into energy✓✓
At room temperature, substance A is a solid and substance
B is a gas. A and B react according to the following equation:
A +3B --> C
At room temperature, what state of matter do you predict for
substance C?
a. Solid, because C is heavier than A or B
b. Gas, because C is three parts B (which is a gas) and one
part A (which is a solid).
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c. Liquid, because C will be intermediate between a solid
and a gas.
d. We cannot predict the state of matter because we don't
know about the bonding/interactions present within C. ......
ANSWER ....... We cannot predict the state of matter
because we don't know about the bonding/interactions
present within C. ✓✓
Carbon can exist in many forms known as allotropes. Two
such allotropes are diamond and graphite. Unlike diamond,
graphite conducts electricity. This is because:
a. In graphite, there are hybrid orbitals used for bonding that
contain electrons.
b. In diamond, all of the electrons are in sigma bonds, which
allows conductivity of electricity.
c. In graphite, there are unhybridized p-orbitals that extend
over the entire sheet forming a delocalized pi bonding
network where electrons are free to move.
d. In diamond, the bonding electrons have enough energy
and can therefore conduct electricity. ...... ANSWER .......
In graphite, there are unhybridized p-orbitals that extend
over the entire sheet forming a delocalized pi bonding
network where electrons are free to move. ✓✓
CEM 141 MSU 2026/2027 FINAL EXAM
COMPLETE CURRENT TESTING QUESTIONS
AND CORRECT VERIFIED ANSWERS FOR
GUARANTEED PASS/TOP-RATED A+.
CEM 141 MSU
Pass with confidence using the CEM 141 MSU Final Exam study
resource. It focuses on key topics such as stoichiometry, atomic
structure, chemical bonding, thermochemistry, and reaction
kinetics, commonly tested on the final. The exam-style
questions help reinforce problem-solving skills and conceptual
clarity. This resource is ideal for Michigan State University CEM
141 students and other introductory college chemistry learners
preparing for final exams.
How many core and valence electrons does one atom of
Iodine (I) have?
a. 36 core and 17 valence
b. 7 core and 36 valence
c. 36 core and 7 valence
d. 46 core and 7 valence ...... ANSWER ....... 46 core and 7
valence✓✓
, Page 2 of 22
Nuclear reactions can release large amounts of energy
because:
a. Covalent bonds form during a nuclear reaction so energy
is released.
b. Part of the mass of the reactants is converted into energy.
c. Collisions between the reactants transfer energy into the
surroundings.
d. The strong nuclear force squeezes energy out of the
nuclei. ...... ANSWER ....... Part of the mass of the
reactants is converted into energy✓✓
At room temperature, substance A is a solid and substance
B is a gas. A and B react according to the following equation:
A +3B --> C
At room temperature, what state of matter do you predict for
substance C?
a. Solid, because C is heavier than A or B
b. Gas, because C is three parts B (which is a gas) and one
part A (which is a solid).
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c. Liquid, because C will be intermediate between a solid
and a gas.
d. We cannot predict the state of matter because we don't
know about the bonding/interactions present within C. ......
ANSWER ....... We cannot predict the state of matter
because we don't know about the bonding/interactions
present within C. ✓✓
Carbon can exist in many forms known as allotropes. Two
such allotropes are diamond and graphite. Unlike diamond,
graphite conducts electricity. This is because:
a. In graphite, there are hybrid orbitals used for bonding that
contain electrons.
b. In diamond, all of the electrons are in sigma bonds, which
allows conductivity of electricity.
c. In graphite, there are unhybridized p-orbitals that extend
over the entire sheet forming a delocalized pi bonding
network where electrons are free to move.
d. In diamond, the bonding electrons have enough energy
and can therefore conduct electricity. ...... ANSWER .......
In graphite, there are unhybridized p-orbitals that extend
over the entire sheet forming a delocalized pi bonding
network where electrons are free to move. ✓✓
