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WGU D335 Introduction to Programming in Python – D335, Western Governors University (2026) – OA objective assessment questions with verified answers

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This document contains the newest 2026 Objective Assessment (OA) exam questions for WGU D335 Introduction to Programming in Python, including 15 fully answered questions with correct and detailed verified explanations. It is designed as a focused exam preparation resource, helping students review key concepts and understand how to approach OA-style questions effectively.

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D335/ WGU D335 EXAM/ D335 INTRODUCTION TO
PROGRAMMING IN PYTHON: OA OBJECTIVE
ASSESSMENT NEWEST 2026 ACTUAL EXAM
QUESTIONS AND CORRECT DETAILED ANSWERS
(VERIFIED ANSWERS) ALL ANSWERED {15 Q & A}
ALREADY GRADED A+ | BRAND NEW! | 100%
GUARANTEED PASS | WGU




Create a solution that accepts three integer inputs representing
the number of times an employee travels to a job site. Output the
total distance traveled to two decimal places given the following
miles per employee commute to the job site. Output the total
distance traveled to two decimal places given the following miles
per employee commute to the job site:
Employee A: 15.62 miles
Employee B: 41.85 miles
Employee C: 32.67 miles
The solution output should be in the format
Distance: total_miles_traveled miles - ✔✔✔ Correct Answer > travels =
D
"A": int(input()),
"B": int(input()),
"C": int(input())

, 2|Page


}
miles_per_employee = D"A": 15.62, "B":41.85, "C": 32.67}
total_miles_traveled = sum(travels[employee] *
miles_per_employee[employee] for employee in travels)
print(f"Distance: Dtotal_miles_traveled:.2f} miles")


Create a solution that accepts an integer input representing any
number of ounces. Output the converted total number of tons,
pounds, and remaining ounces based on the input ounces value.
There are 16 ounces in a pound and 2,000 pounds in a ton.
The solution output should be in the format
Tons: value_1 Pounds: value_2 Ounces: value_3 - ✔✔✔ Correct Answer >
ounces = int(input())
value_1 = ounces // (16 * 2000)
value_2 = (ounces % (16 * 2000)) // 16
value_3 = ounces % 16
print(f"Tons: Dvalue_1}")
print(f"Pounds: Dvalue_2}")
print(f"Ounces: Dvalue_3}")


Create a solution that accepts an integer input representing the
index value for any any of the five elements in the following list:

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