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Part 1 of 4 - Chi Square Test for Homogeneity 8.0/ 8.0 Points
Question 1 of 20
1.0/ 1.0 Points
A company manager believes that a person’s ability to be a leader is directly correlated to their
zodiac sign. He never selects someone to chair a committee without first evaluating their zodiac
sign. An irate employee sets out to prove her manager wrong. She claims that if zodiac sign truly
makes a difference in leadership, then a random sample of 210 CEO’s in our country would
reveal a difference in zodiac sign distribution. She finds the following zodiac signs for her
random sample of 210 CEO’s:
Births Signs
25 Aries
13 Taurus
17 Gemini
21 Cancer
16 Leo
18 Virgo
15 Libra
16 Scorpio
20 Sagittarius
11 Capricorn
23 Aquarius
15 Pisces
Can she conclude that zodiac sign makes a difference in whether or not a person makes a good
leader? Alpha = .10.
A.
yes because the p-value = 0.5523
, B.
no because the p-value = 0.5523
C.
yes because the p-value = 0.4798
D.
no because the p-value = 0.4798
Answer Key:D
Feedback:
The Expected Count is all the same value. 210*(1/12) = 17.5
Expected
Births Signs
Count
25 Aries 17.5
13 Taurus 17.5
17 Gemini 17.5
21 Cancer 17.5
16 Leo 17.5
18 Virgo 17.5
15 Libra 17.5
16 Scorpio 17.5
Sagittariu
20 17.5
s
11 Capricorn 17.5
23 Aquarius 17.5
15 Pisces 17.5
Use Excel to find the p-value
,=CHISQ.TEST(Highlight Observed, Highlight Expected)
p-value > .05, Do Not Reject Ho. No this is not significant.
Question 2 of 20
1.0/ 1.0 Points
Click to see additional instructions
Students at a high school are asked to evaluate their experience in the class at the end of each
school year. The courses are evaluated on a 1-4 scale – with 4 being the best experience
possible. In the History Department, the courses typically are evaluated at 10% 1’s, 15% 2’s,
34% 3’s, and 41% 4’s.
Mr. Goodman sets a goal to outscore these numbers. At the end of the year he takes a random
sample of his evaluations and finds 10 1’s, 13 2’s, 48 3’s, and 52 4’s. At the 0.05 level of
significance, can Mr. Goodman claim that his evaluations are significantly different than the
History Department’s?
Enter the p-value - round to 4 decimal places. Make sure you put a 0 in front of the decimal.
p-value= 0.3913
Answer Key:0.3913
Feedback:
1's 2's 3's 4's
Observed
10 13 48 52
Counts
Expected 123 *.10 = 123*.15 = 123*.34 = 123*.41 =
Counts 12.3 18.45 41.82 50.43
Use Excel to find the p-value
=CHISQ.TEST(Highlight Observed, Highlight Expected)
Question 3 of 20
1.0/ 1.0 Points
Click to see additional instructions
A large department store is curious about what sections of the store make the most sales. The
manager has data from ten years prior that show 30% of sales come from Clothing, 25% Home
Appliances, 18% Housewares, 13% Cosmetics, 12% Jewelry, and 2% Other.
In a random sample of 550 current sales, 188 came from Clothing, 153 Home Appliances,
83 Housewares, 54 Cosmetics, 61 Jewelry, and 11 Other. At α=0.10, can the manager conclude
that the distribution of sales among the departments has changed?
Enter the p-value - round to 4 decimal places. Make sure you put a 0 in front of the decimal.
p-value= 0.0321
,Answer Key:0.0321
Feedback:
Clothing Home App. Housewares Cosmetics Jewelry Other
Observed
188 153 83 54 61 11
Counts
Expected 550*.30 = 550*.25 = 550*.18 = 99 550*.13 = 550*.12 = 550*.02=
Counts 165 137.5 71.5 66 11
Use Excel to find the p-value
=CHISQ.TEST(Highlight Observed, Highlight Expected)
Question 4 of 20
1.0/ 1.0 Points
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The permanent residence of adults aged 18-25 in the U.S. was examined in a survey from the
year 2000. The survey revealed that 27% of these adults lived alone, 32% lived with a
roommate(s), and 41% lived with their parents/guardians. In 2008, during an economic recession
in the country, another such survey of 1600 people revealed that 398 lived alone, 488 lived with
a roommate(s), and 714 lived with their parents. Is there a significant difference in where young
adults lived in 2000 versus 2008? Test with a Goodness of Fit test at α=0.05.
Enter the observed and expected counts for each category in the table below. Round to whole
numbers.
Alone Roommates Parents/Guardians
Observed Counts 398 488 714
Expected Counts 432 512 656
Answer Key:398, 488, 714, 432, 512, 656
Feedback:
The observed counts are given to you, 398, 488, and 714
Calculate expected counts 1600*.27, 1600*.32 and 1600*.41
Question 5 of 20
1.0/ 1.0 Points
An urban economist is curious if the distribution in where Oregon residents live is different
today than it was in 1990. She observes that today there are approximately 3,109 thousand
residents in NW Oregon, 902 thousand residents in SW Oregon, 244 thousand in Central
Oregon, and 102 thousand in Eastern Oregon. She knows that in 1990 the breakdown was as
follows: 72.7% NW Oregon, 20.7% SW Oregon, 4.8% Central Oregon, and 2.8% Eastern
,Oregon.
Can she conclude that the distribution in residence is different today at a 0.05 level of
significance?
Hypotheses:
H0: There is ________ in the distribution of Oregon residents today.
H1: There is ________ in the distribution of Oregon residents today.
A.
no difference, a difference
B.
a difference, no difference
C.
no difference, no difference
D.
a difference, a difference
Answer Key:A
Question 6 of 20
1.0/ 1.0 Points
A college prep school advertises that their students are more prepared to succeed in college than
other schools. To verify this, they categorize GPA’s into 4 groups and look up the proportion of
students at a state college in each category. They find that 7% have a 0-0.99, 21% have a 1-1.99,
37% have a 2-2.99, and 35% have a 3-4.00 in GPA.
, They then take a random sample of 200 of their graduates at the state college and find that 19 has
a 0-0.99, 28 have a 1-1.99, 82 have a 2-2.99, and 71 have a 3-4.00.
Can they conclude that the grades of their graduates are distributed differently than the general
population at the school? Test at the 0.05 level of significance.
Hypotheses:
H0: There is ______ between the general population and the college prep students in GPA.
H1: There is ______ between the general population and the college prep students in GPA.
Select the best fit choices that fit in the two blank spaces above.
A.
no difference, a difference
B.
a difference, no difference
C.
no difference, no difference
D.
a difference, a difference
Answer Key:A
Question 7 of 20
1.0/ 1.0 Points
A Driver’s Ed program is curious if the time of year has an impact on number of car accidents in
the U.S. They assume that weather may have a significant impact on the ability of drivers to
control their vehicles. They take a random sample of 150 car accidents and record the season