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Nur 3890 Final Exam Questions And Answers

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Nur 3890 Final Exam Questions And Answers /.A nurse researcher reports a 95% confidence interval (CI) of 58.34 and 60.50. How would a nurse reading this research report interpret these results? - Answer- The researcher can be 95% confident that if the study were repeated with another sample of the same size, the average or mean score would fall between 58.34 and 60.50 in the sample. /.The researcher has preset the level of significance at =0.05 and the probability of the statistical analysis is calculated to be p=0.09. What decision would the reader of this research expect of the researcher? - Answer- Fail to reject the null hypothesis /.A researcher fails to reject the null hypothesis in a study. The study was repeated multiple times and that analysis revealed that the null hypothesis should have been rejected. What occurred in the original research? - Answer- A type II error /.A researcher randomly assigns volunteers into two groups: group 1 (control group) takes an exam after sleeping less than 8 hours the night before the exam, whereas group 2 (experimental group) gets 8 or more hours of sleep the night before the exam. All students took the exam. The researcher uses a computer statistical software package to compare the mean score of subjects in group 1 and group 2. This results in statistics of t=2.84, degree f freedom (50+50=100-2)=98, and p=0.03. Which statistical test, if any, was conducted in this study? - Answer- An independent sample t test /.A researcher wants to see if sleep can affect test scores. A part is thrown the night before an exam, and all students are required to attend. No one is allowed to get more than 4 hours of sleep prior to the exam. A month later, the researcher does a posttest, and all the students get at least 8 hours of sleep the night before the exam. This results in statistics of t=2.84, degree of freedom (100-1)=99, and p=0.03. Which statistical test, if any, was conducted in this study? - Answer- A dependent sample t test /.How does an ANOVA differ from a t test of independent samples? - Answer- An ANOVA allows the comparison of mean scores between and among two or more groups. This test notes that a difference is found, if there is one, but not where the difference lies /.Why is it most appropriate to compute a chi-square when comparing frequency of gender (male/female) and smoking status (smoker/nonsmoker)? - Answer-Gender and smoking status are both nominal-level variables in this example, and chi-square requires nominal-level data /.A research reports r=0.60, p=0.02 when correlating the relationship between anxiety level and pulse rate in a study with an alpha of 0.05. How should the nurse who is reading this report interpret these results? - Answer- As anxiety increased, so did pulse rates in this study; this was a statistically significant although moderate, positive correlation /.In what way is multiple regression an advanced statistical test that differs from the more common inferential statistics of t test and ANOVA? - Answer- A multiple regression has multiple independent variables and one dependent or outcome variable /.Which type of analysis combines the results of several similar studies? - Answer-A meta-analysis is used to statistically combine the outcomes of several studies /.Which statement, made by a research student, would the faculty analyze as indicating the student understands the concept of sampling distribution of the mean? - Answer- The smaller the standard error of the mean, the more confidence the researcher can have that the mean from the sample is an accurate reflection of the population mean /.The nurse manager of a hospital unit has read a research study and recommends that the nurses on the unit change a standard intervention based upon the results of the study. Later, the nurse manager discovers a second research study that indicates the original study contained a type I error. What is the significance of this finding? - Answer- The change instituted by the nurse manager was unnecessary /.The researcher has reported a one-tailed analysis of variance to test the hypothesis, "Nurse intervention plus group sessions is more effective than nurse intervention alone, or community intervention in improving Framingham coronary risk scores among rural dwelling women in the Promoting Heart Healthy in Rural Women study." Why is the choice of a one-tailed test versus a two-tailed test appropriate? - Answer- the researcher has stated a directional research hypothesis /.Select the statement that is accurate about the power of a statistical test - Answer- A one-tailed test is more powerful than a two-tailed test /.A researcher describes the characteristics of three groups of subjects in a study. What statistics should the researcher use to analyze this demographic data? - Answer-Descriptive statistics /.Which statement is true of a set of scores that is negatively skewed? - Answer-More scores are located at the upper end of the distribution /.A study was conducted to evaluate a new method of teaching medication dose calculation to nursing students. The mean score on the exam was x=82.3 with a

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Nur 3890 Final Exam Questions And
Answers

/.A nurse researcher reports a 95% confidence interval (CI) of 58.34 and 60.50. How
would a nurse reading this research report interpret these results? - Answer-✅ The
researcher can be 95% confident that if the study were repeated with another sample of
the same size, the average or mean score would fall between 58.34 and 60.50 in the
sample.

/.The researcher has preset the level of significance at =0.05 and the probability of the
statistical analysis is calculated to be p=0.09. What decision would the reader of this
research expect of the researcher? - Answer-✅ Fail to reject the null hypothesis

/.A researcher fails to reject the null hypothesis in a study. The study was repeated
multiple times and that analysis revealed that the null hypothesis should have been
rejected. What occurred in the original research? - Answer-✅ A type II error

/.A researcher randomly assigns volunteers into two groups: group 1 (control group)
takes an exam after sleeping less than 8 hours the night before the exam, whereas
group 2 (experimental group) gets 8 or more hours of sleep the night before the exam.
All students took the exam. The researcher uses a computer statistical software
package to compare the mean score of subjects in group 1 and group 2. This results in
statistics of t=2.84, degree f freedom (50+50=100-2)=98, and p=0.03. Which statistical
test, if any, was conducted in this study? - Answer-✅ An independent sample t test

/.A researcher wants to see if sleep can affect test scores. A part is thrown the night
before an exam, and all students are required to attend. No one is allowed to get more
than 4 hours of sleep prior to the exam. A month later, the researcher does a posttest,
and all the students get at least 8 hours of sleep the night before the exam. This results
in statistics of t=2.84, degree of freedom (100-1)=99, and p=0.03. Which statistical test,
if any, was conducted in this study? - Answer-✅ A dependent sample t test

/.How does an ANOVA differ from a t test of independent samples? - Answer-✅ An
ANOVA allows the comparison of mean scores between and among two or more
groups. This test notes that a difference is found, if there is one, but not where the
difference lies

/.Why is it most appropriate to compute a chi-square when comparing frequency of
gender (male/female) and smoking status (smoker/nonsmoker)? - Answer-✅Gender
and smoking status are both nominal-level variables in this example, and chi-square
requires nominal-level data

, /.A research reports r=0.60, p=0.02 when correlating the relationship between anxiety
level and pulse rate in a study with an alpha of 0.05. How should the nurse who is
reading this report interpret these results? - Answer-✅ As anxiety increased, so did
pulse rates in this study; this was a statistically significant although moderate, positive
correlation

/.In what way is multiple regression an advanced statistical test that differs from the
more common inferential statistics of t test and ANOVA? - Answer-✅ A multiple
regression has multiple independent variables and one dependent or outcome variable

/.Which type of analysis combines the results of several similar studies? - Answer-✅A
meta-analysis is used to statistically combine the outcomes of several studies

/.Which statement, made by a research student, would the faculty analyze as indicating
the student understands the concept of sampling distribution of the mean? - Answer-✅
The smaller the standard error of the mean, the more confidence the researcher can
have that the mean from the sample is an accurate reflection of the population mean

/.The nurse manager of a hospital unit has read a research study and recommends that
the nurses on the unit change a standard intervention based upon the results of the
study. Later, the nurse manager discovers a second research study that indicates the
original study contained a type I error. What is the significance of this finding? - Answer-
✅ The change instituted by the nurse manager was unnecessary

/.The researcher has reported a one-tailed analysis of variance to test the hypothesis,
"Nurse intervention plus group sessions is more effective than nurse intervention alone,
or community intervention in improving Framingham coronary risk scores among rural
dwelling women in the Promoting Heart Healthy in Rural Women study." Why is the
choice of a one-tailed test versus a two-tailed test appropriate? - Answer-✅ the
researcher has stated a directional research hypothesis

/.Select the statement that is accurate about the power of a statistical test - Answer-✅ A
one-tailed test is more powerful than a two-tailed test

/.A researcher describes the characteristics of three groups of subjects in a study. What
statistics should the researcher use to analyze this demographic data? - Answer-
✅Descriptive statistics

/.Which statement is true of a set of scores that is negatively skewed? - Answer-✅More
scores are located at the upper end of the distribution

/.A study was conducted to evaluate a new method of teaching medication dose
calculation to nursing students. The mean score on the exam was x=82.3 with a

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