G150 PHA1500 MODULE 02 QUIZ PRACTICE
QUESTIONS WITH DETAILED SOLUTIONS 2026
◉ Lead I: Right arm --> left arm
Lead II: Right arm --> left leg
Lead III: left arm --> left leg. Answer: Match the ECG Lead with the
proper limb combination that makes up that lead.
Lead I, Lead II, Lead III
Right arm --> left leg
Right arm --> left arm
right arm --> right leg
left arm --> right leg
left arm --> left leg
◉ a. down and toward the patient's left.. Answer: Under normal
circumstances, atrial and ventricular activity mainly travel:
a. down and toward the patient's left.
,b. mainly towards the anterior chest wall.
c. in a circular pattern.
d. toward the vector defined by aVL.
e. down and toward the patient's right.
◉ b. The ECG vector is traveling perpendicular to aVL.. Answer: A
patient is connected to a cardiac monitor and Lead aVL is selected.
The monitor is not picking up a large signal. What is the reason for
this?
a. The monitor unit is faulty. Call Biomed.
b. The ECG vector is traveling perpendicular to aVL.
c. The ECG vector is traveling perpendicular to Lead II.
d. The patient is in atrial fibrillation.
e. One of the electrodes has come loose.
◉ a. the transition point.. Answer: The point on the chest wall where
the normal R-wave progression of the precordial QRS complex
results in an R-wave that is larger than the S-wave is called...
a. the transition point.
b. the point of maximal impulse.
c. the equilateral point.
,d. Erb's point.
e. Eintoven's point.
◉ a. direction.. Answer: A vector is a scientific term used to define a
force having both amplitude and...
a. direction.
b. velocity.
c. positivity.
d. mass.
e. magnitude
◉ a. 358 msec
Bazett's formula is:
QTc = QT x 1 / SquareRoot of RR in seconds
QTc = 320 x 1 / SquareRoot of 0.8
QTc = 320 x .8944
, Another way of doing it is by DIVIDING the QT by the SquareRoot of
the RR....
So then QTc = .8944 ---> it gives the same answer.
The correct answer is: 358 msec. Answer: An ECG shows a heart rate
of 75 beats per minute and a QT interval of 320 msec. Using Bazett's
formula, the calculated QTc would be:
a. 358 msec
b. 380 msec
c. 342 msec
d. 304 msec
e. 320 msec
◉ c. PR = 120 ms; QRS = 100 ms. Answer: Measure the PR interval
and the QRS duration in the following tracing and select the correct
values from the list below:
a. PR = 160 ms; QRS = 100 ms
b. PR = 200 ms; QRS = 110 ms
c. PR = 120 ms; QRS = 100 ms
d. PR = 160 ms; QRS = 120 ms
QUESTIONS WITH DETAILED SOLUTIONS 2026
◉ Lead I: Right arm --> left arm
Lead II: Right arm --> left leg
Lead III: left arm --> left leg. Answer: Match the ECG Lead with the
proper limb combination that makes up that lead.
Lead I, Lead II, Lead III
Right arm --> left leg
Right arm --> left arm
right arm --> right leg
left arm --> right leg
left arm --> left leg
◉ a. down and toward the patient's left.. Answer: Under normal
circumstances, atrial and ventricular activity mainly travel:
a. down and toward the patient's left.
,b. mainly towards the anterior chest wall.
c. in a circular pattern.
d. toward the vector defined by aVL.
e. down and toward the patient's right.
◉ b. The ECG vector is traveling perpendicular to aVL.. Answer: A
patient is connected to a cardiac monitor and Lead aVL is selected.
The monitor is not picking up a large signal. What is the reason for
this?
a. The monitor unit is faulty. Call Biomed.
b. The ECG vector is traveling perpendicular to aVL.
c. The ECG vector is traveling perpendicular to Lead II.
d. The patient is in atrial fibrillation.
e. One of the electrodes has come loose.
◉ a. the transition point.. Answer: The point on the chest wall where
the normal R-wave progression of the precordial QRS complex
results in an R-wave that is larger than the S-wave is called...
a. the transition point.
b. the point of maximal impulse.
c. the equilateral point.
,d. Erb's point.
e. Eintoven's point.
◉ a. direction.. Answer: A vector is a scientific term used to define a
force having both amplitude and...
a. direction.
b. velocity.
c. positivity.
d. mass.
e. magnitude
◉ a. 358 msec
Bazett's formula is:
QTc = QT x 1 / SquareRoot of RR in seconds
QTc = 320 x 1 / SquareRoot of 0.8
QTc = 320 x .8944
, Another way of doing it is by DIVIDING the QT by the SquareRoot of
the RR....
So then QTc = .8944 ---> it gives the same answer.
The correct answer is: 358 msec. Answer: An ECG shows a heart rate
of 75 beats per minute and a QT interval of 320 msec. Using Bazett's
formula, the calculated QTc would be:
a. 358 msec
b. 380 msec
c. 342 msec
d. 304 msec
e. 320 msec
◉ c. PR = 120 ms; QRS = 100 ms. Answer: Measure the PR interval
and the QRS duration in the following tracing and select the correct
values from the list below:
a. PR = 160 ms; QRS = 100 ms
b. PR = 200 ms; QRS = 110 ms
c. PR = 120 ms; QRS = 100 ms
d. PR = 160 ms; QRS = 120 ms
