D
Pg. 2tt
MoTION
Kest8 A body is Aald to in rext when its pesitich does
not chande with sespect to a reterehce point
Motion 8 A body is_Said to be in State of motion when
Lts position change Continuo&Y with respect to
a
e-erente point
Types of Monol
( i ) Ciaculato Motion Citular
Motion
i)
LiR Linear motionIn a slsnight Line path
iR) OscillatorY motionloand so path Wert origin
A Scalar quanlity 8 Quandity which baa magntude_burt
Ono dimctidn i Called Scatar quantity
istance peed
Vector quantih Quandit uhich bas magnitude aswel
as diectidnis Called Vettor quantity
e9 displarenent Velocity
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DELTA Notebook
, Dt.:
Pg.
DisHance lhe _actual path or Length tave fed tz Called
distahce
Distance iz a ScalarquantY,its baz ho dliection
Displocement Te Ahortest length beluen initial poin and
ina point trauelled by an obiecd is called
displacement
Displatement is a Vectorquandty it s bdth
magnitude & diection
Displacement can be zero when initial ard ina paint
0e3amee9 Ciulax moion
Distance Displacement
1Lengihof acdual Paih 1 Shor-esi lenq-lh_betuseeninitia
Lyavelled by an obfect poirst and finalgbind olan obbe
is Scalar quarslitya is Vector quantdy
3 Hermains pnsiiivecan| Hcan be positivenegai
be ZeD 0 negative 0 Ze0
) Distance can be equal5 Dixplacemeri Cabe equa
Drlaxqeyhan diolatemeil to disdane or H letgex ihan
digiante
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DELTA Notebook
, Example 1. A body travels in a semicircular path of radius 10 m starting its motion from
point A 'topoini 'B'. Calculate the distance and displacement.
Solution: Total distance travelled by body, S=?
Given, T=3.14, R =10m
S=nR
5.14
O
=3.14x 10m
=31.4m AnS.
Total displacement of body, D=?
Given, R 10m
D=2*R
=2x 10m-20m Ans.
115
Example 2.A body travels 4 km towards North then he turn to his right and travels another
4 km before coming to rest. Calculate (i) total distance travelled. (i) total displacement.
Solution:
4kmB
displacement
W E
Total distance travelled -OA++AB
4 km+4km
8 km Ans.
Total displacement = OB
OB OB
4y4
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5.65 km Ans
Pg. 2tt
MoTION
Kest8 A body is Aald to in rext when its pesitich does
not chande with sespect to a reterehce point
Motion 8 A body is_Said to be in State of motion when
Lts position change Continuo&Y with respect to
a
e-erente point
Types of Monol
( i ) Ciaculato Motion Citular
Motion
i)
LiR Linear motionIn a slsnight Line path
iR) OscillatorY motionloand so path Wert origin
A Scalar quanlity 8 Quandity which baa magntude_burt
Ono dimctidn i Called Scatar quantity
istance peed
Vector quantih Quandit uhich bas magnitude aswel
as diectidnis Called Vettor quantity
e9 displarenent Velocity
www.notesdrive.com
DELTA Notebook
, Dt.:
Pg.
DisHance lhe _actual path or Length tave fed tz Called
distahce
Distance iz a ScalarquantY,its baz ho dliection
Displocement Te Ahortest length beluen initial poin and
ina point trauelled by an obiecd is called
displacement
Displatement is a Vectorquandty it s bdth
magnitude & diection
Displacement can be zero when initial ard ina paint
0e3amee9 Ciulax moion
Distance Displacement
1Lengihof acdual Paih 1 Shor-esi lenq-lh_betuseeninitia
Lyavelled by an obfect poirst and finalgbind olan obbe
is Scalar quarslitya is Vector quantdy
3 Hermains pnsiiivecan| Hcan be positivenegai
be ZeD 0 negative 0 Ze0
) Distance can be equal5 Dixplacemeri Cabe equa
Drlaxqeyhan diolatemeil to disdane or H letgex ihan
digiante
www.notesdrive.com
DELTA Notebook
, Example 1. A body travels in a semicircular path of radius 10 m starting its motion from
point A 'topoini 'B'. Calculate the distance and displacement.
Solution: Total distance travelled by body, S=?
Given, T=3.14, R =10m
S=nR
5.14
O
=3.14x 10m
=31.4m AnS.
Total displacement of body, D=?
Given, R 10m
D=2*R
=2x 10m-20m Ans.
115
Example 2.A body travels 4 km towards North then he turn to his right and travels another
4 km before coming to rest. Calculate (i) total distance travelled. (i) total displacement.
Solution:
4kmB
displacement
W E
Total distance travelled -OA++AB
4 km+4km
8 km Ans.
Total displacement = OB
OB OB
4y4
www.notesdrive.com
5.65 km Ans
