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Numerical Methods for Engineers 7th Edition Solution Manual | Steven Chapra

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Complete solution manual for Numerical Methods for Engineers, 7th Edition by Steven Chapra. Step-by-step answers to textbook problems covering numerical analysis, MATLAB applications, and engineering computations.

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1


CHAPTERj1
1.1 Wejwilljillustratejtwojdifferentjmethodsjforjsolvingjthisjproblem:j(1)jseparationjofjvariables,jandj(2)jL
aplacejtransform.

dvj cj
=jgj−j vj
dt m

Separationjofjvariables:jSeparationjofjvariablesjgives



1
j
j c

jv

dvj=j dt
j
jgj−j

m

Thejintegralsjcanjbejevaluatedjas
j cj 
lnj gj−j vj
 mj 


j
=jtj+jCj
cj/jm

wherejCj=jajconstantjofjintegration,jwhichjcanjbejevaluatedjbyjapplyingjthejinitialjconditionjtojyield
j cj 
lnj gj−j v(0)j
 m 
Cj = − j  
cj/jm

whichjcanjbejsubstitutedjbackjintojthejsolution
j cj  j cj 
lnj gj−j vj lnj gj−j v(0)j
 mj   m 
−   j
=jtj−  
cj/jm cj/jm

Thisjresultjcanjbejrearrangedjalgebraicallyjtojsolvejforjv,


vj=jv(0)e−(c/jm)tj +j
jmgj
c
(
1−je−(cj/jm)tj )
wherejthejfirstjpartjisjthejgeneraljsolutionjandjthejsecondjpartjisjthejparticularjsolutionjforjthejconstantjforcin
gjfunctionjduejtojgravity.jForjthejcasejwhere,jv(0)j=j0,jthejsolutionjreducesjtojEq.j(1.10)


vj = j
jmgj

c
(1− e j
−(c/m)tj
)
Laplacejtransformjsolution:jAnjalternativejsolutionjisjprovidedjbyjapplyingjLaplacejtransformjtojthejdiffe
rentialjequationjtojgive

g j cj
sVj(s)j−jv(0)j=j −j Vj(s)
s m

PROPRIETARYjMATERIAL.j ©jThejMcGraw-
HilljCompanies,jInc.j Alljrightsjreserved.j NojpartjofjthisjManualjmayjbejdisplayed,jreproducedjorjdistributedjinjanyjfor
mjorjbyjanyjmeans,jwithoutjthejpriorjwrittenjpermissionjofjthejpublisher,jorjusedjbeyondjthejlimitedjdistributionjtojteach
ersjandjeducatorsjpermittedjbyjMcGraw-
Hilljforjtheirjindividualjcoursejpreparation.j IfjyoujarejajstudentjusingjthisjManual,jyoujarejusingjitjwithoutjpermission.

, 2

Solvejalgebraicallyjforjthejtransformedjvelocity




PROPRIETARYjMATERIAL.j ©jThejMcGraw-
HilljCompanies,jInc.j Alljrightsjreserved.j NojpartjofjthisjManualjmayjbejdisplayed,jreproducedjorjdistributedjinjanyjfor
mjorjbyjanyjmeans,jwithoutjthejpriorjwrittenjpermissionjofjthejpublisher,jorjusedjbeyondjthejlimitedjdistributionjtojteach
ersjandjeducatorsjpermittedjbyjMcGraw-
Hilljforjtheirjindividualjcoursejpreparation.j IfjyoujarejajstudentjusingjthisjManual,jyoujarejusingjitjwithoutjpermission.

, 3




Vj(s)j = v(0) j
+
g (1)
sj+jcj/jm s(sj+jcj/jm)

Thejsecondjtermjonjthejrightjofjthejequaljsignjcanjbejexpandedjwithjpartialjfractions

g Aj B A(sj+jcj/jm)j+jBs
=j + =j (2)
s(sj+jcj/jm) s sj+jcj/jm s(sj+jcj/jm)

Byjequatingjlikejtermsjinjthejnumerator,jthejfollowingjmustjhold

c
g j = j Aj 0j=j Asj+jBs
m

ThejfirstjequationjcanjbejsolvedjforjAj=jmg/c.jAccordingjtojthejsecondjequation,jBj=j–A,jsojBj=j–
mg/c.jSubstitutingjthesejbackjintoj(2)jgives

g j =j
mgj/jcj j mgj/jc
−j
s(sj+jcj/jm) s sj+jcj/jm

ThisjcanjbejsubstitutedjintojEq.j1jtojgive

v(0) mgj/jcj mgj/jc
Vj(s)j = +j −j
sj+jcj/jm s sj+jcj/jm

TakingjinversejLaplacejtransformsjyields

mgj mgj −(cj/jm)t
v(t)j =jv(0)e−(c/jm)tj +j +j e
c c

orjcollectingjterms


v(t)j =jv(0)e−(c/m)tj +j
jmgj
c
(
1−je−(c/jm)tj )
1.2 Atjtj=j8js,jthejanalyticaljsolutionjisj41.137j(Examplej1.1).jThejrelativejerrorjcanjbejcalculatedjwith

analyticalj−jnumerical
absolutejrelativejerror = 100%
analytical

Thejnumericaljresultsjare:

absolute
j j jstep
j j j j j j j vj(8)
j j j j relativej error
2 44.8700 9.074%
1 42.8931 4.268%
0.5 41.9901 2.073%

Thejerrorjversusjstepjsizejcanjthenjbejplottedjas



PROPRIETARYjMATERIAL.j ©jThejMcGraw-
HilljCompanies,jInc.j Alljrightsjreserved.j NojpartjofjthisjManualjmayjbejdisplayed,jreproducedjorjdistributedjinjanyjfor
mjorjbyjanyjmeans,jwithoutjthejpriorjwrittenjpermissionjofjthejpublisher,jorjusedjbeyondjthejlimitedjdistributionjtojteach
ersjandjeducatorsjpermittedjbyjMcGraw-
Hilljforjtheirjindividualjcoursejpreparation.j IfjyoujarejajstudentjusingjthisjManual,jyoujarejusingjitjwithoutjpermission.

, 4



10%

8%

6%

4%

2%

0%
0 0.5 1 1.5 2 2.5


Thus,jhalvingjthejstepjsizejapproximatelyjhalvesjthejerror.

1.3 (a)jYoujarejgivenjthejfollowingjdifferentialjequationjwithjthejinitialjcondition,jv(tj=j0)j=j0,

dvj cj'j
=jgj−j v2j
dt m

Multiplyjbothjsidesjbyjm/c′jgives

mj dvj mj
=j gj−jv2
cj'j dt cj'

Definej aj= mgj/jcj'

mj dvj
=ja2j −jv2
cj'j dt

Integratejbyjseparationjofjvariables,

dv cj'
a j −jv
2 2
=
m 
dt

Ajtablejofjintegralsjcanjbejconsultedjtojfindjthat



dxj a 1j xj
=j tanh−1j
j−jx
2 2 a a

Therefore,jthejintegrationjyields

1j vj cj'j
tanh−1j =j tj+jCja
a m

Ifjvj=j0jatjtj=j0,jthenjbecausejtanh–1(0)j=j0,jthejconstantjofjintegrationjCj=j0jandjthejsolutionjis

1j vj cj'j
tanh−1j =j tj
a a m

Thisjresultjcanjthenjbejrearrangedjtojyield

PROPRIETARYjMATERIAL.j ©jThejMcGraw-
HilljCompanies,jInc.j Alljrightsjreserved.j NojpartjofjthisjManualjmayjbejdisplayed,jreproducedjorjdistributedjinjanyjfor
mjorjbyjanyjmeans,jwithoutjthejpriorjwrittenjpermissionjofjthejpublisher,jorjusedjbeyondjthejlimitedjdistributionjtojteach
ersjandjeducatorsjpermittedjbyjMcGraw-
Hilljforjtheirjindividualjcoursejpreparation.j IfjyoujarejajstudentjusingjthisjManual,jyoujarejusingjitjwithoutjpermission.

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