ESTUDYR
IME 144 MIDTERM REVIEW UPDATED EXAM WITH MOST
TESTED QUESTIONS AND ANSWERS | GRADED A+ | ASSURED
SUCCESS WITH DETAILED RATIONALES
1.
After making one turning cut, the cross-slide handwheel is fed one full revolution clockwise,
and another cut is taken. If the cross-slide is calibrated at 0.125 in per revolution (diameter),
what will be the resulting change in the workpiece diameter?
A. 0.0625 in
B. 0.125 in
C. 0.250 in
D. 0.500 in
✅Correct Answer: C. 0.250 in
Rationale:
The cross slide moves the tool radially, but diameter change is twice the radial movement.
Radial movement = 0.125 in → Diameter change = 2 × 0.125 = 0.250 in
2.
After making one turning cut, the cross-slide handwheel is fed one full revolution clockwise.
What was the depth of cut (actual radial movement of the tool)?
A. 0.250 in
B. 0.125 in
C. 0.0625 in
D. 0.500 in
✅Correct Answer: B. 0.125 in
Rationale:
Depth of cut is measured radially, not diametrically. One full revolution equals 0.125 in radial
movement.
,ESTUDYR
3.
The cross-slide wheel is turned one graduation clockwise, and a cut is made. If one graduation
equals 0.0005 in radially, what is the resulting change in workpiece diameter?
A. 0.0005 in
B. 0.001 in
C. 0.002 in
D. 0.005 in
✅Correct Answer: B. 0.001 in
Rationale:
Diameter change = 2 × radial movement
2 × 0.0005 = 0.001 in
4.
How many graduations must the cross-slide handwheel be rotated to reduce the workpiece
diameter by 0.025 in?
A. 12.5
B. 25
C. 50
D. 125
✅Correct Answer: B. 25
Rationale:
Each graduation = 0.001 in diameter reduction
0.025 ÷ 0.001 = 25 graduations
5.
In the previous question, what was the depth of cut (radial movement)?
A. 0.025 in
B. 0.0125 in
C. 0.00625 in
D. 0.050 in
✅Correct Answer: B. 0.0125 in
, ESTUDYR
Rationale:
Depth of cut = Diameter reduction ÷ 2
0.025 ÷ 2 = 0.0125 in
6.
A workpiece diameter is 1.157 in after rough turning. The final desired diameter is 1.150 in.
How many graduations must the cross-slide be turned?
A. 3
B. 5
C. 7
D. 14
✅Correct Answer: C. 7
Rationale:
Diameter reduction = 1.157 − 1.150 = 0.007 in
Each graduation = 0.001 in diameter
0.007 ÷ 0.001 = 7 graduations
7.
What are the correct units for spindle speed on a lathe?
A. inches per minute
B. inches per revolution
C. revolutions per minute (rev/min)
D. feet per minute
✅Correct Answer: C. rev/min
Rationale:
Spindle speed describes how fast the spindle rotates, measured in RPM.
8.
What are the correct units for spindle speed on a milling machine?
A. inches per minute
B. inches per revolution
IME 144 MIDTERM REVIEW UPDATED EXAM WITH MOST
TESTED QUESTIONS AND ANSWERS | GRADED A+ | ASSURED
SUCCESS WITH DETAILED RATIONALES
1.
After making one turning cut, the cross-slide handwheel is fed one full revolution clockwise,
and another cut is taken. If the cross-slide is calibrated at 0.125 in per revolution (diameter),
what will be the resulting change in the workpiece diameter?
A. 0.0625 in
B. 0.125 in
C. 0.250 in
D. 0.500 in
✅Correct Answer: C. 0.250 in
Rationale:
The cross slide moves the tool radially, but diameter change is twice the radial movement.
Radial movement = 0.125 in → Diameter change = 2 × 0.125 = 0.250 in
2.
After making one turning cut, the cross-slide handwheel is fed one full revolution clockwise.
What was the depth of cut (actual radial movement of the tool)?
A. 0.250 in
B. 0.125 in
C. 0.0625 in
D. 0.500 in
✅Correct Answer: B. 0.125 in
Rationale:
Depth of cut is measured radially, not diametrically. One full revolution equals 0.125 in radial
movement.
,ESTUDYR
3.
The cross-slide wheel is turned one graduation clockwise, and a cut is made. If one graduation
equals 0.0005 in radially, what is the resulting change in workpiece diameter?
A. 0.0005 in
B. 0.001 in
C. 0.002 in
D. 0.005 in
✅Correct Answer: B. 0.001 in
Rationale:
Diameter change = 2 × radial movement
2 × 0.0005 = 0.001 in
4.
How many graduations must the cross-slide handwheel be rotated to reduce the workpiece
diameter by 0.025 in?
A. 12.5
B. 25
C. 50
D. 125
✅Correct Answer: B. 25
Rationale:
Each graduation = 0.001 in diameter reduction
0.025 ÷ 0.001 = 25 graduations
5.
In the previous question, what was the depth of cut (radial movement)?
A. 0.025 in
B. 0.0125 in
C. 0.00625 in
D. 0.050 in
✅Correct Answer: B. 0.0125 in
, ESTUDYR
Rationale:
Depth of cut = Diameter reduction ÷ 2
0.025 ÷ 2 = 0.0125 in
6.
A workpiece diameter is 1.157 in after rough turning. The final desired diameter is 1.150 in.
How many graduations must the cross-slide be turned?
A. 3
B. 5
C. 7
D. 14
✅Correct Answer: C. 7
Rationale:
Diameter reduction = 1.157 − 1.150 = 0.007 in
Each graduation = 0.001 in diameter
0.007 ÷ 0.001 = 7 graduations
7.
What are the correct units for spindle speed on a lathe?
A. inches per minute
B. inches per revolution
C. revolutions per minute (rev/min)
D. feet per minute
✅Correct Answer: C. rev/min
Rationale:
Spindle speed describes how fast the spindle rotates, measured in RPM.
8.
What are the correct units for spindle speed on a milling machine?
A. inches per minute
B. inches per revolution
