j
, PROBLEMj10.1
Determinej thej verticalj forcej Pj thatj mustj bej appliedj atj Cj toj maint
ainjthejequilibriumjofjthejlinkage.
SOLUTION
Assumej jyA
jyCj =j2jyA
jyDj =jjyA
1j 1j
jyjEj =j jyj jD=j jy A
2 2
1j
jyjGj =jjyj jE=j jy A
2
jyA
Also j =j aj=j0.3jm
a
VirtualjWork:jWejapplyjbothjPjandjMjtojmemberjABC.
Uj =j80jyAj −jPjyCj −jMj +j60jyDj +j20jyEj −j40jyGj =j0
jjy j1j j j1j j
80jy A −jP(2 jyjA)j−jM A +j60 jyjAj +j20 j jy Aj− j40 j jy Aj=j0
a 2 2
Mj
80j−j2Pj−j +j60j+j10j−j20j=j0
a
Mj
2Pj+j =j130jN (1)
a
NowjfromjEq.j(1)jforj Mj =j0 2Pj=j130jN Pj=j65.0jNj j ◀
Copyrightj©jMcGraw-HilljEducation.jPermissionjrequiredjforjreproductionjorjdisplay.
, PROBLEMj10.2
DeterminejthejhorizontaljforcejPjwhichjmustjbejappliedjatjAjsojtha
tjthejlinkagejisjinjequilibriumjforjthejpositionjshown.
SOLUTION
Assumej
jxAj =j10j in.
j yCj =j 4j in.
j yDj =j j yCj =j 4j in.
jyDj 2j
j =j =j
6 3
j2j j
jxjGj =j15j =j15 j j = j10j in.
3
VirtualjWork: AssumejthatjforcejPjisjappliedjatjA.
Uj =j 0: Uj =j −jPjxAj +j 30j yCj +j 60j yDj +j 240j +j 80jxGj =j 0
j2j
−jPj(10jjin.)j+j(30jlb)(4j in.)j+j(60jlb)(4jj)j+j(240jlbin.)
j3j
+(80jlb)(10jjin.)j=j0
−10Pj +j120j +j 240j +j160j +j800j =j 0
10Pj =j1320 Pj =j132.0j lb
Copyrightj©jMcGraw-HilljEducation.jPermissionjrequiredjforjreproductionjorjdisplay.
, PROBLEMj10.3
DeterminejthejcouplejMjthatjmustjbejappliedjtojmemberjABCjtojmaint
ainjthejequilibriumjofjthejlinkage.
SOLUTION
Assumej jyA
jyDj =jjyA
1j 1j
jyjEj =j jyj jD=j jy A
2 2
1j
jyjGj =jjyj jE=j jy A
2
jyA
Also j =j
0.3
VirtualjWork:jWejapplyjbothjPjandjMjtojmemberjABC.
Uj =j80jyAj −jPjyCj −jMj +j60jyDj +j20jyEj −j40jyGj =j0
j jy A j1j j j1j j
80jy A −jP(2 jyjA)j−jM j +j60 jyjAj +j20 j jy Aj− j40 j jy Aj=j0
0.3jmj 2 2
M
80j−j2Pj− +j60j+j10j−j20j=j0
0.3jm
M
2Pj+ =j130jN (1)
0.3jm
M
NowjfromjEq.j(1)jforj Pj=j0 =j130jN Mj=j39.0jNjjm ◀
0.3jm
Copyrightj©jMcGraw-HilljEducation.jPermissionjrequiredjforjreproductionjorjdisplay.