CHEM 103 MODULE 1 TO 6 EXAM ANSWERS PORTAGE LEARNING LATEST UPDATED APRIL 2026

CHEM 103 MODULE 1 TO 6 EXAM
ANSWERS PORTAGE LEARNING LATEST
UPDATED APRIL 2026

MODULE 1 EXAM
Question 1
Click this link to access the Periodic Table. This may be helpful throughout the
exam.
1. Convert 845.3 to exponential form and explain your answer.
2. Convert 3.21 x 10-5 to ordinary form and explain your answer.


Convert 845.3 = larger than 1 = positive exponent, move decimal 2 places
= 8.453 x 102
Convert 3.21 x 10-5 = negative exponent = smaller than 1, move decimal 5 places =
0.0000321

Question 2
Click this link to access the Periodic Table. This may be helpful throughout the
exam.


Using the following information, do the conversions shown below, showing allwork:
1 ft = 12 inches 1 pound = 16 oz 1 gallon = 4 quarts
1 mile = 5280 feet 1 ton = 2000 pounds 1 quart = 2 pints
kilo (= 1000)1/100) milli (= 1/1000) centi (=
deci (= 1/10)


1. 24.6 grams = ? kg

2. 6.3 ft = ? inches


1. 24.6 grams x 1 kg / 1000 g = 0.0246 kg
2. 6.3 ft x 12 in / 1 ft = 75.6 inches
1

,please always use the correct units in your final answer

Question 3




2

,Click this link to access the Periodic Table. This may be helpful throughoutthe exam.


Do the conversions shown below, showing all work:
1. 28oC = ? oK
2. 158oF = ? oC
3. 343oK = ?
o
F

1. 28oC + 273 = 301 oK o
C → oK (make larger)
+273
2. 158oF - 32 ÷ 1.8 = 70 oC o
F → oC (make smaller)
-32 ÷1.8
3. 343oK - 273 = 70 oC x 1.8 + 32 = 158 oF o
K → o C → oF

Question 4
Click this link to access the Periodic Table. This may be helpful throughout the
exam.


Be sure to show the correct number of significant figures in each calculation.


1. Show the calculation of the mass of a 18.6 ml sample of freon withdensity
of 1.49 g/ml


2. Show the calculation of the density of crude oil if 26.3 g occupies 30.5ml.

1. M = D x V = 1.49 x 18.6 = 27.7 g
2. D = M / V = 26..5 = 0.862 g/ml


Question 5
Click this link to access the Periodic Table. This may be helpful throughout the
exam.


1. 3.0600 contains ? significant figures.
2. 0.0151 contains ? significant figures.

3

, 3. 3.0600 ÷ 0.0151 = ? (give answer to correct number of significant
figures)

1. 3.0600 contains 5 significant figures.
2. 0.0151 contains 3 significant figures.
3. 3.0600 ÷ 0.0151 = 202.649 = 203 (to 3 significant figures for 0.0151)
Click this link to access the Periodic Table. This may be helpful throughout
the exam.


Show the full Nuclear symbol including any + or - charge (n), the atomicnumber
(y), the mass number (x) and the correct element symbol (Z) foreach element for
which the protons, neutrons and electrons are shown - symbol should appear as
follows: xZy+/- n


31 protons, 39 neutrons, 28 electrons

31 protons = Ga31, 39 neutrons = 70Ga31, 28 electrons = (+31 - 28 = +3)
= 70Ga 31+3

Question 9
Click this link to access the Periodic Table. This may be helpful throughout the
exam.


Name each of the following chemical compounds. Be sure to name all acidsas acids
(NOT for instance as binary compounds)


1. PF5
2. Al2(CO3)3
3. H2CrO4

1. PF5 - binary molecular = phosphorus pentafluoride
2. Al2(CO3)3 - nonbinary ionic = aluminum carbonate




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