CHEM 123 Post_Lab_5_Calculations

Part calculations
All concentration =
LHC)
MACI


Trial 1-gimal, 5.04
=
x 10
-



*MHC)

Trial2& 0-5 moltel=S.OUx10-4M
0.02500L HC1 Hely
Trial 3 - 1.30 x 10-5 malHel ~Average
4MHC1(50410-4)
-



- s.10x10 =




0.02500L Hel

5.12x10
4
-




(x-u)
=




Party calculations moles of kHP
Trial1-> maIHP= make 0.011(NaOHX NaOH
0.1094M Nuol, 1.206x 10



Trial 2 0.0086LNaOH xoM NaOH malIt:9.424x10Ymal KA
-



09bM Naximal= malk
Trial?UUrq4LNas
1.030 x 10 e



Trial 1 1.704x10-malkHP
0.24 gKHP (204.22g(mal) =




0.192 gkHP
Trial 2 - 9.426x10-malkHP (284.27g/mol) =




KAP (204.27g(mal)
Trial3 - 1030 x10mal 0.210g KHP
=




Purity KAP (%)
of

Trial 1 -0.244g(HP/0.343gKHP)
E #100%-71.7%

(0.0.210gkH/0.332g kHP)180%-43.2%jA
1929kHP/0.304gkHP)
Trialze *


Trial - 100% - 43.3%
*


63.2 13.3
43.25% 2
+


= - - -


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