UBC MATH 101 EXAM QUESTIONS AND
ANSWERS GRADED A+ 2026
For a function to be differentiable, it must... - ANS -it has to be continuous
- the limit from the left has to equal the limit from the right
-
cscθ - ANS 1/sinθ
secθ - ANS 1/cosθ
cotθ - ANS cosθ/sinθ
sin²θ + cos²θ = 1 - ANS x² + y² = (radius of unit circle)
tan²θ + 1 = sec²θ - ANS (sin²θ/cos²θ) + (cos²θ/cos²θ) = (1/cos²θ)
1 + cot²θ = csc²θ - ANS (sin²θ/sin²θ) + (cos²θ/sin²θ) = (1/sin²θ)
sin(x ± y) - ANS sin(x)cos(y) ± cos(x)sin(y)
@COPYRIGHT 2026/2027 ALL RIGHTS RESERVED
1
, cos(x ± y) - ANS cos(x)cos(y) ∓ sin(x)sin(y)
tan(x ± y) - ANS [tan(x) ± tan(y)] ÷ [1 ∓ tan(x)tan(y)]
sin(2x) - ANS 2 sin(x) cos(x)
equivalent to sin(x ± x)
cos(2x) - ANS cos²(x) - sin²(x)
equivalent to cos(x ± x)
cos(2x) - ANS 2 cos²(x) - 1
equivalent to cos²(x) - [sin²(x) = 1 - cos²(x)]
cos(2x) - ANS 1 - 2 sin²(x)
equivalent to [cos²(x) = 1 - sin²(x)] - sin²(x)
tan(2x) - ANS 2 tan(x) ÷ [1 - tan²(x)]
equivalent to tan(x ± x)
@COPYRIGHT 2026/2027 ALL RIGHTS RESERVED
2
ANSWERS GRADED A+ 2026
For a function to be differentiable, it must... - ANS -it has to be continuous
- the limit from the left has to equal the limit from the right
-
cscθ - ANS 1/sinθ
secθ - ANS 1/cosθ
cotθ - ANS cosθ/sinθ
sin²θ + cos²θ = 1 - ANS x² + y² = (radius of unit circle)
tan²θ + 1 = sec²θ - ANS (sin²θ/cos²θ) + (cos²θ/cos²θ) = (1/cos²θ)
1 + cot²θ = csc²θ - ANS (sin²θ/sin²θ) + (cos²θ/sin²θ) = (1/sin²θ)
sin(x ± y) - ANS sin(x)cos(y) ± cos(x)sin(y)
@COPYRIGHT 2026/2027 ALL RIGHTS RESERVED
1
, cos(x ± y) - ANS cos(x)cos(y) ∓ sin(x)sin(y)
tan(x ± y) - ANS [tan(x) ± tan(y)] ÷ [1 ∓ tan(x)tan(y)]
sin(2x) - ANS 2 sin(x) cos(x)
equivalent to sin(x ± x)
cos(2x) - ANS cos²(x) - sin²(x)
equivalent to cos(x ± x)
cos(2x) - ANS 2 cos²(x) - 1
equivalent to cos²(x) - [sin²(x) = 1 - cos²(x)]
cos(2x) - ANS 1 - 2 sin²(x)
equivalent to [cos²(x) = 1 - sin²(x)] - sin²(x)
tan(2x) - ANS 2 tan(x) ÷ [1 - tan²(x)]
equivalent to tan(x ± x)
@COPYRIGHT 2026/2027 ALL RIGHTS RESERVED
2