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CHEM 219 Module 1 Exam Questions with Answers Already Graded A+

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CHEM 219 Module 1 Exam Questions with Answers Already Graded A+ 1. What is organic chemistry? - ANSWER Branch of chemistry that studies the structure, properties, composition, reaction and synthesis of organic compounds which contain carbon atoms. 2. Catenation - ANSWER Ability of ab element to form bonds with itself, resulting in formation of chains, rings or complex structures. Allows for vats diversity of organic compounds in terms of reactivity and properties 3. The properties & reactivity of an organic molecule are controlled by its - ANSWER composition & shape 4. Why do atoms form bonds to other atoms? - ANSWER Energetic stability 5. To say an atom is energetically stable means that the overall energy of the atom is - ANSWER lower when in the bonded state than in a non bonded state 6. How does electronegativity (X) increase - ANSWER increases moving towards the right and going up the PTOTE 7. Covalent Bonds - ANSWER share electrons bt elements with little or no difference in their electronegativity - Heat is released when covalent bonds are formed 8. What do you look at to figure out how many bonds an element will form - ANSWER LDD Comes from group number 9. Unpaired electrons - ANSWER # of bonds the atom will form 10.# of pairs of electrons - ANSWER LONE pairs or nonbonding, these do not participate in bonding 11.On a piece of scratch paper, write out the Lewis Dot Diagram for each of the indicated elements and determine the following for each: a) The number of Lone Pairs the atom possesses in its valence shell. b) b) The number of Unpaired Electrons the atom possesses in its valence shell. c) The number of bonds the atom will form. Oxygen Carbon Hydrogen Nitrogen - ANSWER Oxygen - a) 2 b) 2 c) 2 Carbon - a) 0 b) 4 c) 4 Hydrogen- a) 0 b) 1 c) 1 Nitrogen - a) 1 b) 3 c) 3 12.Classify the bonding between the given pairs of atoms as ionic, covalent, or polar covalent. Use the table of electronegativities shown below to help with the classification. a. Br and Br b. K and Cl c. P and Cl d. C and O e. Na and Br - ANSWER a. Br-Br: Electronegativity difference () = 0 = COVALENT (or pure covalent) b. K-Cl: () = 2.2 = IONIC c. P-Cl: ()= 0.9 = POLAR COVALENT d. C-O: ()= 1.0 = POLAR COVALENT e. Na-Br: () = 1.8 = POLAR COVALENT 13.Define the term constitutional isomer. - ANSWER Two (or more) different chemical compounds with the same molecular formula but different connectivity between the atoms in their structural formulae. 14.Explain (using specific evidence) what makes the following two compounds constitutional isomers of one another: - ANSWER Both compounds have a MF of C3H6O - same MF. Compound "a" has a 3-carbon chain with a C=O in the middle. No H atom connected to C of C=O. Compound "b" has a 3-carbon chain with a C=O at the end. There is an H attached to the C of the C=O. 15.What is the relationship between the compounds shown? Are they the same compound, constitutional isomers, or two different compounds that are not related to one another? Explain. - ANSWER Different compounds that are not related. They have different MF - (a) C3H8O, (b) C3H6O. 16.Formal charge formula - ANSWER FC = group # of element - (dots + dashes) - dots = non-binding electrons (lone pair or single unpaired electrons) - dashes = bonding electrons 17.Resonance structure - ANSWER Two or more structural formula of a molecule with identical arrangements of atoms BUT different arrangements of electrons 18.Major contributor - ANSWER Ideal arrangement/structure 19.Minor contributor - ANSWER Less ideal arrangement/structure 20.Non-contributor - ANSWER Arrangement/structure does not match or correlate with correct atoms/electrons in an element. 21.End-on overlap molecules - ANSWER The binding/combination of either S or P orbitals, or both 22.Sideways orbital overlap - ANSWER - associated with P orbitals only - Pi orbital 23.Valence shell electron pair repulsion (VSEPR) theory - ANSWER A tool for determining the shape around atoms in molecules based on analysis of the patterns of electrons around them. - electrons repel (want to be far apart from each other) 24.Molecular geometry - ANSWER - wedge bond: project out of plane of paper (towards us) - dash bond: project behind plane of paper (away from us) - line bond: rep atoms/groups that remain in plane of paper 25.Cation - ANSWER Becomes positively charged when it loses an electron 26.Anion - ANSWER Becomes negatively charged when it receives an electron 27.The compound carbon monoxide has the following structural formula: What is the formal charge on the carbon and the oxygen? Show your calculation. What is the overall charge on the molecule? - ANSWER Carbon = 4-(2+3) = -1 Oxygen = 6-(2+3) = +1 Overall = FC Carbon + FC Oxygen = [-1 + (+1)] = 0 28.For the following example of resonance: Which structure (a or b) represents a "major" resonance contributor to the hybrid? Briefly explain why. - ANSWER Structure "a" is a major contributor. All of the atoms have complete valences and in addition, all of the atoms have a formal charge of zero (All of the atoms are meeting their LDD bonding pattern). 29.Describe how individual resonance structures impact the true structure of a molecule or polyatomic ion. - ANSWER Each contributing individual resonance structure contributes characteristics to the overall hybrid structure of the compound. The hybrid "averages" bond lengths and formal charges by delocalizing them among atoms that share them in each contributing individual resonance structure. 30.On a piece of scrap paper, draw the resonance structure "b" that would result from redistributing the electrons as shown on structure "a" in the diagram below: For your structure "b", complete the table with the information requested: - ANSWER Oxygen: 1 lone pair, 1 single bond, 1 double bond, +1 formal charge. Carbon (1): 0 lone pair, 2 single bond, 1 double bond, 0 formal charge. Carbon (II): 1 lone pair, 3 single bond, 0 double bond, -1 formal charge. 31.Identify each of the following carbon skeletons as linear (continuous), branched, or cyclic. - ANSWER a) Branched b) Linear (continuous) c) Cyclic

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Institution
CHEM 219
Course
CHEM 219

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CHEM 219 Module 1 Exam Questions with
Answers Already Graded A+

1. What is organic chemistry? - ANSWER Branch of chemistry that studies
the structure, properties, composition, reaction and synthesis of organic
compounds which contain carbon atoms.


2. Catenation - ANSWER Ability of ab element to form bonds with itself,
resulting in formation of chains, rings or complex structures.
Allows for vats diversity of organic compounds in terms of reactivity and
properties


3. The properties & reactivity of an organic molecule are controlled by its -
ANSWER composition & shape


4. Why do atoms form bonds to other atoms? - ANSWER Energetic stability


5. To say an atom is energetically stable means that the overall energy of the
atom is - ANSWER lower when in the bonded state than in a non bonded
state


6. How does electronegativity (X) increase - ANSWER increases moving
towards the right and going up the PTOTE


7. Covalent Bonds - ANSWER share electrons bt elements with little or no
difference in their electronegativity
- Heat is released when covalent bonds are formed

, 8. What do you look at to figure out how many bonds an element will form -
ANSWER LDD
Comes from group number


9. Unpaired electrons - ANSWER # of bonds the atom will form


10.# of pairs of electrons - ANSWER LONE pairs or nonbonding, these do not
participate in bonding


11.On a piece of scratch paper, write out the Lewis Dot Diagram for each of the
indicated elements and determine the following for each:
a) The number of Lone Pairs the atom possesses in its valence
shell.
b) b) The number of Unpaired Electrons the atom possesses in its
valence shell.
c) The number of bonds the atom will form.
Oxygen
Carbon
Hydrogen
Nitrogen - ANSWER Oxygen - a) 2 b) 2 c) 2
Carbon - a) 0 b) 4 c) 4
Hydrogen- a) 0 b) 1 c) 1
Nitrogen - a) 1 b) 3 c) 3


12.Classify the bonding between the given pairs of atoms as ionic, covalent, or
polar covalent. Use the table of electronegativities shown below to help with
the classification.

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