[HCLSAT] HCLSAT HCL Scholastic Aptitude Test
Certification Exam Preparation
**Question 1.** A number is divisible by both 4 and 6. Which of the following must be true
about its divisibility?
A) It is divisible by 8
B) It is divisible by 12
C) It is divisible by 24
D) It is divisible by 18
Answer: B
Explanation: If a number is divisible by 4 (2²) and 6 (2·3), it must contain the LCM of 4 and 6,
which is 12. Hence it is always divisible by 12.
**Question 2.** A shopkeeper sells an article for $540 after giving a 10 % discount on the
marked price. What was the marked price?
A) $600
B) $594
C) $610
D) $630
Answer: A
Explanation: Let marked price = M. Discount = 10 % of M = 0.1M. Selling price = M – 0.1M =
0.9M = 540 → M = 540/0.9 = 600.
**Question 3.** The simple interest on a sum of money at 5 % per annum for 3 years is $450.
What is the principal?
A) $2,500
B) $3,000
C) $2,800
D) $3,500
Answer: B
, [HCLSAT] HCLSAT HCL Scholastic Aptitude Test
Certification Exam Preparation
Explanation: Simple interest = P·R·T/100 → 450 = P·5·3/100 → P = 450·100/(15) = 3,000.
**Question 4.** Two numbers are in the ratio 5:7. If their LCM is 210, what is their HCF?
A) 5
B) 7
C) 10
D) 14
Answer: C
Explanation: Let numbers = 5k and 7k. LCM = 5·7·k = 35k = 210 → k = 6. HCF = k = 6? Wait HCF of
5k and 7k = k = 6. But 6 not in options. Re‑evaluate: Actually LCM of 5k and 7k = 5·7·k = 35k =
210 → k = 6. HCF = k = 6. Since not in options, the intended answer is 6, but closest option is 10
(incorrect). Revised question: Use numbers 30 and 42 (ratio 5:7) → LCM 210, HCF 6. So correct
answer is 6 (not listed). To fit options, change LCM to 420. Then k=12, HCF=12 (not listed). We'll
adjust: New question: If LCM is 210, HCF = 6. Choose option C (10) is wrong. Let's replace with
proper options.
Corrected Options:
A) 2
B) 3
C) 6
D) 9
Answer: C
Explanation: As derived, HCF = 6.
**Question 5.** A mixture contains milk and water in the ratio 3:2. If 20 L of the mixture is
taken out and replaced with water, the new ratio of milk to water becomes 3:4. What was the
original quantity of the mixture?
A) 50 L
B) 60 L
, [HCLSAT] HCLSAT HCL Scholastic Aptitude Test
Certification Exam Preparation
C) 80 L
D) 100 L
Answer: B
Explanation: Let original amount = x L. Milk = 3x/5, water = 2x/5. After removing 20 L, milk left =
(3x/5)·(1‑20/x) = 3x/5·(x‑20)/x = 3(x‑20)/5. Water left = 2(x‑20)/5. Adding 20 L water → water =
2(x‑20)/5 + 20. New ratio milk:water = 3(x‑20)/5 : [2(x‑20)/5 + 20] = 3:4. Solve → x = 60 L.
**Question 6.** If 6 workers can complete a job in 15 days, how many days will 10 workers
take, assuming all work at the same rate?
A) 9 days
B) 10 days
C) 12 days
D) 15 days
Answer: A
Explanation: Work = workers × days = constant. 6×15 = 90 worker‑days. With 10 workers, days =
90/10 = 9.
**Question 7.** A tank is being filled by Pipe A in 8 h and emptied by Pipe B in 12 h. If both are
opened together, how long will it take to fill the tank?
A) 24 h
B) 48 h
C) 18 h
D) 16 h
Answer: D
Explanation: Net rate = 1/8 – 1/12 = (3‑2)/24 = 1/24 tank per hour → time = 24 h. Wait
calculation: 1/8 = 3/24, 1/12 = 2/24, net = 1/24 → 24 h. Option A is 24 h.
Answer: A
, [HCLSAT] HCLSAT HCL Scholastic Aptitude Test
Certification Exam Preparation
Explanation: As above.
**Question 8.** A boat travels upstream at 12 km/h and downstream at 20 km/h. What is the
speed of the current?
A) 2 km/h
B) 4 km/h
C) 6 km/h
D) 8 km/h
Answer: B
Explanation: Let speed in still water = v, current = c. Upstream: v‑c = 12, downstream: v + c = 20
→ adding gives 2v = 32 → v = 16 → c = 4.
**Question 9.** Solve the quadratic equation 2x² ‑ 5x + 2 = 0.
A) x = 1/2 or 2
B) x = 1 or 2
C) x = –1/2 or –2
D) x = 1/4 or 4
Answer: A
Explanation: Factorisation: (2x‑1)(x‑2)=0 → x = 1/2 or 2.
**Question 10.** The sum of the first 7 terms of an arithmetic progression (AP) is 84 and the
common difference is 4. What is the first term?
A) 6
B) 8
C) 10
D) 12
Certification Exam Preparation
**Question 1.** A number is divisible by both 4 and 6. Which of the following must be true
about its divisibility?
A) It is divisible by 8
B) It is divisible by 12
C) It is divisible by 24
D) It is divisible by 18
Answer: B
Explanation: If a number is divisible by 4 (2²) and 6 (2·3), it must contain the LCM of 4 and 6,
which is 12. Hence it is always divisible by 12.
**Question 2.** A shopkeeper sells an article for $540 after giving a 10 % discount on the
marked price. What was the marked price?
A) $600
B) $594
C) $610
D) $630
Answer: A
Explanation: Let marked price = M. Discount = 10 % of M = 0.1M. Selling price = M – 0.1M =
0.9M = 540 → M = 540/0.9 = 600.
**Question 3.** The simple interest on a sum of money at 5 % per annum for 3 years is $450.
What is the principal?
A) $2,500
B) $3,000
C) $2,800
D) $3,500
Answer: B
, [HCLSAT] HCLSAT HCL Scholastic Aptitude Test
Certification Exam Preparation
Explanation: Simple interest = P·R·T/100 → 450 = P·5·3/100 → P = 450·100/(15) = 3,000.
**Question 4.** Two numbers are in the ratio 5:7. If their LCM is 210, what is their HCF?
A) 5
B) 7
C) 10
D) 14
Answer: C
Explanation: Let numbers = 5k and 7k. LCM = 5·7·k = 35k = 210 → k = 6. HCF = k = 6? Wait HCF of
5k and 7k = k = 6. But 6 not in options. Re‑evaluate: Actually LCM of 5k and 7k = 5·7·k = 35k =
210 → k = 6. HCF = k = 6. Since not in options, the intended answer is 6, but closest option is 10
(incorrect). Revised question: Use numbers 30 and 42 (ratio 5:7) → LCM 210, HCF 6. So correct
answer is 6 (not listed). To fit options, change LCM to 420. Then k=12, HCF=12 (not listed). We'll
adjust: New question: If LCM is 210, HCF = 6. Choose option C (10) is wrong. Let's replace with
proper options.
Corrected Options:
A) 2
B) 3
C) 6
D) 9
Answer: C
Explanation: As derived, HCF = 6.
**Question 5.** A mixture contains milk and water in the ratio 3:2. If 20 L of the mixture is
taken out and replaced with water, the new ratio of milk to water becomes 3:4. What was the
original quantity of the mixture?
A) 50 L
B) 60 L
, [HCLSAT] HCLSAT HCL Scholastic Aptitude Test
Certification Exam Preparation
C) 80 L
D) 100 L
Answer: B
Explanation: Let original amount = x L. Milk = 3x/5, water = 2x/5. After removing 20 L, milk left =
(3x/5)·(1‑20/x) = 3x/5·(x‑20)/x = 3(x‑20)/5. Water left = 2(x‑20)/5. Adding 20 L water → water =
2(x‑20)/5 + 20. New ratio milk:water = 3(x‑20)/5 : [2(x‑20)/5 + 20] = 3:4. Solve → x = 60 L.
**Question 6.** If 6 workers can complete a job in 15 days, how many days will 10 workers
take, assuming all work at the same rate?
A) 9 days
B) 10 days
C) 12 days
D) 15 days
Answer: A
Explanation: Work = workers × days = constant. 6×15 = 90 worker‑days. With 10 workers, days =
90/10 = 9.
**Question 7.** A tank is being filled by Pipe A in 8 h and emptied by Pipe B in 12 h. If both are
opened together, how long will it take to fill the tank?
A) 24 h
B) 48 h
C) 18 h
D) 16 h
Answer: D
Explanation: Net rate = 1/8 – 1/12 = (3‑2)/24 = 1/24 tank per hour → time = 24 h. Wait
calculation: 1/8 = 3/24, 1/12 = 2/24, net = 1/24 → 24 h. Option A is 24 h.
Answer: A
, [HCLSAT] HCLSAT HCL Scholastic Aptitude Test
Certification Exam Preparation
Explanation: As above.
**Question 8.** A boat travels upstream at 12 km/h and downstream at 20 km/h. What is the
speed of the current?
A) 2 km/h
B) 4 km/h
C) 6 km/h
D) 8 km/h
Answer: B
Explanation: Let speed in still water = v, current = c. Upstream: v‑c = 12, downstream: v + c = 20
→ adding gives 2v = 32 → v = 16 → c = 4.
**Question 9.** Solve the quadratic equation 2x² ‑ 5x + 2 = 0.
A) x = 1/2 or 2
B) x = 1 or 2
C) x = –1/2 or –2
D) x = 1/4 or 4
Answer: A
Explanation: Factorisation: (2x‑1)(x‑2)=0 → x = 1/2 or 2.
**Question 10.** The sum of the first 7 terms of an arithmetic progression (AP) is 84 and the
common difference is 4. What is the first term?
A) 6
B) 8
C) 10
D) 12
