Portage Learning CHEM 103 Module 1-6 Exam Questions and VERIFIED ANSWERS (GUARANTEED PASS

Portage Learning CHEM 103 Module 1-6 Exam
Questions and VERIFIED ANSWERS
(GUARANTEED PASS)

MODULE 1 EXAM
Question 1
Click this link to access the Periodic Table. This may be helpful
throughout the exam.
1. Convert 845.3 to exponential form and explain your answer.
2. Convert 3.21 × 10⁻⁵ to ordinary form and explain your answer.
A) 845.3 = 8.453 × 10²; 3.21 × 10⁻⁵ = 0.0000321 ✓
B) 845.3 = 84.53 × 10¹; 3.21 × 10⁻⁵ = 321000
C) 845.3 = 0.8453 × 10³; 3.21 × 10⁻⁵ = 0.000321
D) 845.3 = 8.453 × 10³; 3.21 × 10⁻⁵ = 3210000
Rationale: 845.3 = larger than 1 = positive exponent, move decimal 2
places = 8.453 × 10². 3.21 × 10⁻⁵ = negative exponent = smaller than 1,
move decimal 5 places = 0.0000321.


Question 2
Click this link to access the Periodic Table. This may be helpful
throughout the exam.

,Using the following information, do the conversions shown below,
showing all work:
1 ft = 12 inches
1 pound = 16 oz
1 gallon = 4 quarts
1 mile = 5280 feet
1 ton = 2000 pounds
1 quart = 2 pints
kilo = 1000
milli = 1/1000
centi = 1/100
deci = 1/10
1. 24.6 grams = ? kg
2. 6.3 ft = ? inches
A) 24.6 grams = 0.0246 kg; 6.3 ft = 75.6 inches ✓
B) 24.6 grams = 24600 kg; 6.3 ft = 0.525 inches
C) 24.6 grams = 2.46 kg; 6.3 ft = 756 inches
D) 24.6 grams = 0.246 kg; 6.3 ft = 75.6 inches
Rationale: 24.6 grams × 1 kg / 1000 g = 0.0246 kg. 6.3 ft × 12 in / 1 ft =
75.6 inches. Please always use the correct units in your final answer.


Question 3
Click this link to access the Periodic Table. This may be helpful
throughout the exam.

,1. 28°C = ?°K
2. 158°F = ?°C
3. 343°K = ?°F
A) 28°C = 301°K; 158°F = 70°C; 343°K = 158°F ✓
B) 28°C = 301°K; 158°F = 126°C; 343°K = 70°F
C) 28°C = 245°K; 158°F = 70°C; 343°K = 617°F
D) 28°C = 301°K; 158°F = 343°C; 343°K = 158°F
Rationale: 28°C + 273 = 301°K (°C → °K make larger, +273). 158°F -
32 ÷ 1.8 = 70°C (°F → °C make smaller, -32 ÷ 1.8). 343°K - 273 = 70°C
× 1.8 + 32 = 158°F (°K → °C → °F).


Question 4
Click this link to access the Periodic Table. This may be helpful
throughout the exam.
Be sure to show the correct number of significant figures in each
calculation.
1. Show the calculation of the mass of a 18.6 ml sample of freon
with density of 1.49 g/ml
2. Show the calculation of the density of crude oil if 26.3 g
occupies 30.5 ml
A) Mass = 27.7 g; Density = 0.862 g/ml ✓
B) Mass = 27.7 g; Density = 1.16 g/ml

, C) Mass = 12.5 g; Density = 0.862 g/ml
D) Mass = 27.7 g; Density = 0.86 g/ml
Rationale: Mass = D × V = 1.49 × 18.6 = 27.7 g. Density = M / V = 26.3 /
30.5 = 0.862 g/ml.


Question 5
Click this link to access the Periodic Table. This may be helpful
throughout the exam.
1. 3.0600 contains ? significant figures.
2. 0.0151 contains ? significant figures.
3. 3.0600 ÷ 0.0151 = ? (give answer to correct number of
significant figures)
A) 3.0600 contains 5 significant figures; 0.0151 contains 3
significant figures; 3.0600 ÷ 0.0151 = 203 ✓
B) 3.0600 contains 4 significant figures; 0.0151 contains 4 significant
figures; 3.0600 ÷ 0.0151 = 202.6
C) 3.0600 contains 5 significant figures; 0.0151 contains 3 significant
figures; 3.0600 ÷ 0.0151 = 202.649
D) 3.0600 contains 3 significant figures; 0.0151 contains 3 significant
figures; 3.0600 ÷ 0.0151 = 203
Rationale: 3.0600 contains 5 significant figures. 0.0151 contains 3
significant figures. 3.0600 ÷ 0.0151 = 202.649 = 203 (to 3 significant
figures for 0.0151).