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PHY250L Lab 3: Newton's Laws - Complete Lab Report (2026/2027)

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View a complete PHY250L Lab 3 report on Newton's Laws of Motion. Includes experiments on inertia, force pairs (Third Law), and Atwood machines (Second Law) with free-body diagrams, data tables, and acceleration calculations.

Institution
PHY250L
Course
PHY250L

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PHY250L
LAB 3 EXAM

NEWTON’S LAWS

ACTUAL QUESTIONS & VERIFIED ANSWERS


STRAIGHTERLINE

(2026/2027)

,Student Name: GIOVANA COSTARELLI
Access Code (located on the underside of the lid of your lab kit): AC-
KW8OU6

Lab Report Format Expectations
Utilize college-level grammar and formatting when answering text-based
questions.
Report all equations in a proper mathematical format, with the correct signs
and symbols.
Submissions with incomplete or improperly formatted responses may be
rejected.

Pre-Lab Questions
1. State Newton’s Laws in words.

Three fundamental principles of Newton's Laws describe the

movement of bodies. The First Law, or Law of Inertia, states that an

object at rest remains at rest and in motion continues in a straight,

uniform motion unless an external force acts on it. The Second Law, or

Law of Acceleration, establishes that the force acting on an object is

equal to the mass of the object multiplied by the acceleration (F =

m*a). The Third Law, or Law of Action and Reaction, determines that

for every action there is an equal and opposite reaction. These laws

form the basis of classical mechanics and are essential for

understanding motion.




2. Consider the masses in Figure 4 to the right.

Draw a Free Body Diagram for:

, a. Mass 1




Figure 4: Free Body Diagram: 2 objects with mass
hanging on a pulley by string.

b. and Mass 2.




3. Apply Newton’s 2nd Law, F=ma, to write the force equations for M1 and
M2. This will yield two equations that detail the sum of forces in your
free-body diagram. You should get two force equations that describe
the Tension in the string (force in the up direction), weight for each
mass (force in the down direction), and accelerations for each mass (a1
and a2).
The forces equations would be f1=(m1) (a) f2=m=(m2) (a). For F1 the
tension is equal to 39.24N. The tension for m2 is 19.62 N. Now the
weight for each mass equals 2kg for f1, and 4kg for f2. A1 would be
9.82m/s^2 and A2 would be A2=4.895 m/s^2

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Institution
PHY250L
Course
PHY250L

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Uploaded on
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