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FDOT FINAL ESTIMATES LEVEL 2 EXAM PREP 2026/2027 COMPLETE QUESTIONS AND CORRECT DETAILED ANSWERS || 100% GUARANTEED PASS RECENT VERSION

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FDOT FINAL ESTIMATES LEVEL 2 EXAM PREP 2026/2027 COMPLETE QUESTIONS AND CORRECT DETAILED ANSWERS || 100% GUARANTEED PASS RECENT VERSION 1. On design build Contracts, the contractor will receive monthly progress payments based on? - ANSWER Monthly Estimates 2. On Conventional jobs, concrete class IV (superstructure) methos of measurement is? - ANSWER Plan Quantities 3. Using the Current Specifications and the attached Summary Tables what is the pay quantity for the concrete production pile? (80' authorized pile length) - ANSWER 80 ft 4. Determine the adjusted plan quantity tonnage and the maximum tonnage that can be paid for Miscllaneous Asphalt based on the current Specifications, which allows a maximum pay of 105% of the adjusted plan quantity tons. ( pay to the appropriate accuracy) Plan Quantity Area (SY) =700 SY ( no revisions) Plan Quantity Tons: 70.0 Tons based on 2" thick per specs Adjusted PQ Tonnage Placed =75.2 Tons from report Gmm fromSpecs = 2.540 and Target Spread Rate =220 Lbs/SY Gmm from Mix 1: 2.522 and tonnage- weighted Gmm=2.55 Lbs/SY - ANSWER 69.5 Tons and max pay 73.0 Tons 5. Find the total thickness on a composite base which includes 4 inches of Limerock Base and 4 inches of type B (12.5) Asphalt Base given the following information: Limerock Base Thickness from Core Out Report =4.19" Asphalt (12.5) Base: Gmm =2.365 from the design mix Average Spread Rate from the roadway report= 429 Lbs/SY - ANSWER Gmm x 43.3 =102.9 429 / 102.4 = 4.19" 4.19" + 4.19" = Total 8.38 inches 6. On an open graded Friction Course (FC-5) Pavement, a straightedge deficiency was left in place at no pay. Calculate the equivalent tonnage at no pay. ( Pay to the appropriate accuracy) Lane Width =12 ft Location of Deficiency= STA 1+56 to STA 1+67 ( 167-156=11) - ANSWER Lx Wx .0044 L=50'+11'+50' = 111' 111' X 12' X 0.0044 = 5.9 TNS 7. Lot 3 has a Tonnage of 2529.0 tons with a Composite Pay Factor of 1.04. What would the calculated Composite Pay Factor adjustment amount be if the unit price is $100.00 per ton? - ANSWER (CPF-1) = Unit price (1.04-1) $100= 4 $4/ton x 2529 tn= $10,116 8. As items in the feild are completed,within 30 days, you will need to have the supporting documentation available to support the pay item in the? - ANSWER Plan Summary Boxes 9. Using the current Specifications and the attached Summary Tables, what is the pay quantity for this steel test pile? ( 60' Authorized pipe length) - ANSWER 60' 10. On the plan quantity item, what describes the criteria of a plan error? - ANSWER B)A difference between the original plan quantity and the final quantity or more than 5% C) Any change in quantity which causes a change in the amount payable of more than $5000 11. For Limerock base the pay area shall not exceed 105% of the surface area. What is the total square yards that will be paid for given the following information? Surface area = 30,000 SY Design thickness=8 in Core out report= 7.65 in - ANSWER 7.65/8=.95625 x30000 = 28688 SY 12. Determine the Total Volumes of original and final Subsoils: - ANSWER 497+353=850 353+312=665 =1515 x100=151,500/54=2805 445+259=704 259+446=705=1409x100+140,900/54=2609.25 13. Final Plans that have no changes are? - ANSWER Required to be signed by the Resident Engineer using appropriate statements. 14. How is extra depth subsoil (5'-15' below plan elevation) paid? - ANSWER Extra depth subsoil excavation at Contract unit price plus 25% 15. How is extra depth subsoil (greater than 15' below plan elevation) paid? - ANSWER Extra depth subsoil excavation paid for as extra work 16. What are the limits to paying for extra depth subsoil? - ANSWER No pay for extra depth subsoils outside the 1:2 slope 17. The submittal of the "Contractors Compliance with Specifications & Plans" form must? - ANSWER A)Note all material exceptions B)Be signed by the contractor C)Be submitted monthly with the partial estimates ALL OF THE ABOVE 18. Determine the final pay quantity for each project under one contract for the following plan Quantity ietms, based on the current Specifications. Project 1) Planned Quantity 3,000 LF, Planned errors = +98LF, Authorized change amount =+25LF Project 2)Planned Quantity 2000 LF, Planned errors = +300LF, Authorized change amount = -45LF - ANSWER Project 1) 3123 LF Project 2) 2255 LF 19. Conduit could be? - ANSWER A) Open trench or Jack and Bore B) Above ground and Bridge Mount C) Bore under railroad ALL OF THE ABOVE 20. Borrow Excavation is paid for as a? - ANSWER Final Measurement 21. When should Liquidated Damages be reflected on a progress estimate? - ANSWER (**Begins after Contract time runs out up to the estimate cut off date. Liquidated Damages are withheld monthly.) ON SUBSEQUENT PROGRESS REPORTS

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Voorbeeld van de inhoud

FDOT FINAL ESTIMATES LEVEL 2 EXAM
PREP 2026/2027 COMPLETE QUESTIONS
AND CORRECT DETAILED ANSWERS ||
100% GUARANTEED PASS RECENT
VERSION


1. On design build Contracts, the Contractor will receive monthly progress
payments based on? - ANSWER Monthly Estimates


2. On Conventional jobs, concrete class IV (superstructure) methos of
measurement is? - ANSWER Plan Quantities


3. Using the Current Specifications and the attached Summary Tables what is
the pay quantity for the concrete production pile? (80' authorized pile length)
- ANSWER 80 ft


4. Determine the adjusted plan quantity tonnage and the maximum tonnage that
can be paid for Miscllaneous Asphalt based on the current Specifications,
which allows a maximum pay of 105% of the adjusted plan quantity tons. (
pay to the appropriate accuracy)
Plan Quantity Area (SY) =700 SY ( no revisions)
Plan Quantity Tons: 70.0 Tons based on 2" thick per specs
Adjusted PQ Tonnage Placed =75.2 Tons from report
Gmm fromSpecs = 2.540 and Target Spread Rate =220 Lbs/SY
Gmm from Mix 1: 2.522 and tonnage- weighted Gmm=2.55 Lbs/SY -
ANSWER 69.5 Tons and max pay 73.0 Tons

, 5. Find the total thickness on a composite base which includes 4 inches of
Limerock Base and 4 inches of type B (12.5) Asphalt Base given the
following information:
Limerock Base Thickness from Core Out Report =4.19"
Asphalt (12.5) Base: Gmm =2.365 from the design mix
Average Spread Rate from the roadway report= 429 Lbs/SY - ANSWER
Gmm x 43.3 =102.9
.4 = 4.19"
4.19" + 4.19" = Total 8.38 inches


6. On an open graded Friction Course (FC-5) Pavement, a straightedge
deficiency was left in place at no pay. Calculate the equivalent tonnage at no
pay. ( Pay to the appropriate accuracy)
Lane Width =12 ft
Location of Deficiency= STA 1+56 to STA 1+67 ( 167-156=11) - ANSWER Lx
Wx .0044
L=50'+11'+50' = 111'
111' X 12' X 0.0044 = 5.9 TNS


7. Lot 3 has a Tonnage of 2529.0 tons with a Composite Pay Factor of 1.04.
What would the calculated Composite Pay Factor adjustment amount be if
the unit price is $100.00 per ton? - ANSWER (CPF-1) = Unit price
(1.04-1) $100= 4
$4/ton x 2529 tn= $10,116


8. As items in the feild are completed,within 30 days, you will need to have the
supporting documentation available to support the pay item in the? -
ANSWER Plan Summary Boxes


9. Using the current Specifications and the attached Summary Tables, what is
the pay quantity for this steel test pile? ( 60' Authorized pipe length) -
ANSWER 60'

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