Finite Mathematics & Its Applications 13th Ed Goldstein Solution Manual (Chapters 1-12)

SOLUTION MANUAL C




Finite Mathematics & Its Applications
C C C C




13th Edition by Larry J. Goldstein,
C C C C C




Chapters 1 - 12, Complete
C C C C

, Contents
Chapter 1: Linear Equations and Straight Lines
C C C C C 1–1
Chapter 2: Matrices
C 2–1

Chapter 3: Linear Programming, A Geometric Approach
C C C C C 3–1

Chapter 4: The Simplex Method
C C C 4–1

Chapter 5: Sets and Counting
C C C 5–1

Chapter 6: Probability
C 6–1

Chapter 7: Probability and Statistics
C C C 7–1

Chapter 8: Markov Processes
C C 8–1

Chapter 9: The Theory of Games
C C C C 9–1

Chapter 10: The Mathematics of Finance
C C C C 10–1

Chapter 11: Logic
C 11–1

Chapter 12: Difference Equations and Mathematical Models
C C C C C 12–1

, Chapter 1 C



ExercisesC1.1 5
6.C LeftC1,CdownC
2
1. RightC2,CupC3 y
y


(2,C3
) x
x
(–1, – 2C


C
5
)C




7.C LeftC20,CupC40
2. LeftC1,CupC4 y
y

(–20,C40)
(–1,C4)
x
x




8.C RightC25,CupC30
3.C DownC2 y
y


(25,C30)
x
x
(0,C–2)




9. PointCQCisC2CunitsCtoCtheCleftCandC2CunitsCupCor
4. RightC2
y (—2,C2).

10. PointCPCisC3CunitsCtoCtheCrightCandC2CunitsCdownCor
(3,—2).
x
(2,C0 1C
) 11. —2(1)C+C (3)C=C—2C+1C=C—1soC yesC theC pointC is
3
onCtheCline.

5. LeftC2,CupC1 1C
y 12. —2(2)C+C (6)C=C—1CisC false,C soC noC theC pointC isC not
3
onCtheCline

(–2,C1)
x



CopyrightC©C2023CPearsonCEducation,CInc. 1-1

, ChapterC1:CLinearCEquationsCandCStraightCLine ISM:CFiniteCMat
s h

1C 24.C 0C=C5
13 —2xC+C yC =C—1C SubstituteC theC xC andC y noCsolution
3
. x-
coordinatesCofCtheCpointCintoCtheCequation:
f 1C hıC f h intercept:CnoneC
' ,C3 →C—2 ' 1 ı +C1C(3)C=C—1C→C—1+1C=C—1C is WhenCxC=C0,CyC=C5
y' ı 'C ı
Cy-intercept:C(0,C5)
2CCC J yC2J 3
aCfalseCstatement.CSoCnoCtheCpointCisCnotConCt 25.CWhenCyC=C0,CxC=C7C
heCline. x-
f 1h f1h intercept:C(7,C0)C0
14 —2 ' ı + ' ı (—1)C=C—1C isCtrueCsoCyesCtheCpointCis C=C7
.
noCsolution
'y3 ıJCCC'y3 ıJ y-intercept:Cnone
onCtheCline. 26.C 0C=C–8x
15.C mC=C5,CbC=C8 xC=C0
x-intercept:C(0,C0)
16.C mC=C–2CandCbC=C–6 yC=C–8(0)
yC=C0
17.C yC=C0xC+C3;CmC=C0,CbC=C3 y-intercept:C(0,C0)

2C 2C 1C
yC=C xC+C0;C mC=C ,C bC=C0 27 0C=C xC–C1
18 3
3 3 .
. xC=C3
19.C 14xC+C7CyC=C21 x-intercept:C(3,C0)
1C
7CyC=C—14xC+C21 yC =C (0)C–C1
3
yC =C—2xC+C3
yC=C–1
y-intercept:C(0,C–1)
20 xC—CyC =C3 y
. —yC =C—xC+C3
yC =CxC—C3
(3,C0) x
21.CCC 3xC=C5
5 (0,C–1)
xC=C
3
1 2
28. WhenCxC=C0,CyC=C0.
22 – xC+ yC =C10
. 2 3 WhenCxC=C1,CyC=C2.
2C 1C y
yC =C xC+10
3 2
3C
yC =C xC+15 (1,C2)
4 x
(0,C0)

23. 0C=C—4xC+C8
4xC =C8
xC=C2
x-intercept:C(2,C0)
yC=C–4(0)C+C8
yC=C8
y-intercept:C(0,C8)
1-2 CopyrightC©C2023CPearsonCEducation,CInc.