Geschreven door studenten die geslaagd zijn Direct beschikbaar na je betaling Online lezen of als PDF Verkeerd document? Gratis ruilen 4,6 TrustPilot
logo-home
College aantekeningen

Nios + cbse , class 11 and 12 science - biology,chemistry ,physics topper notes. Im a topper who scores above 90, so these are topper notes. nothing is skipped, everything is correct. Just simplified and shortened.

Beoordeling
-
Verkocht
-
Pagina's
13
Geüpload op
15-03-2026
Geschreven in
2025/2026

Nios + cbse , class 11 and 12 science - biology,chemistry ,physics topper notes. Im a topper who scores above 90, so these are topper notes. nothing is skipped, everything is correct. Just simplified and shortened.

Instelling
Junior / 11th Grade
Vak
Chemistry

Voorbeeld van de inhoud

Chapter – Solutions ( 24 pgs shortened to 11pgs)
COMPONENTS OF A SOLUTION-
 Solute and solvent are the components of a solution .( solute + solvent →
solution)
 A solution is a homogeneous mixture of two or more substances . Solvent is
that component of a solution that has the same physical state as the solution
itself. Solute is the substance that is dissolved in a solvent to form a solution.
 Solution concentration: - It is the amount of solute present compared
to the amount of solvent (or solution).. There are several ways to
describe concentration of solution: molarity, molality, normality,
mole fraction, mass percentage. (Normality is extra one)
 1. Molarity: Molarity is the number of moles of solute dissolved per
litre of solution
- denoted by M




 .
 A 2.0 molar solution of sulphuric acid would be labelled as 2.0 M H2 SO4 .:
Prepared by: adding 2.0 mol H₂SO₄ to water to make 1 litre of a
solution.
 Molarity changes with temperature due to expansion or contraction of
solution.
2. Molality : number of moles of solute dissolved per kilogram of
solvent.
- represented by symbol m
So molarility is how many moles of solute in Solution finally, but
molality is number of moles of solute in solvent.
Example: 2.0 m H₂SO₄ means 2.0 mol of H₂SO₄ in 1 kg of solvent
(read as “2 molal sulphuric acid”).




 Normality is another concentration unit like molality,etc.. Normality- is the
number of gram equivalent weights of solute dissolved per litre of
solution.
 Equivalent Weight- The number of parts by weight of a substance that
will combine with or displace 1.08 parts hydrogen, 8 parts oxygen, or
35.5 parts chlorine is called its equivalent weight..
basically it is the mass of a substance that reacts with a fixed
amount of another substance, , so they are calculated from the reactions
they take part in. this "fixed amount" was defined as the mass that would

, combine with or displace: 1.008 grams of hydrogen, 8 grams of oxygen, 35.5
grams of chlorine.
 Equivalent weight is a number without units. when expressed in grams, it
is called gram equivalent weight.
 Oxidising and reducing agents may have different equivalent weights
under different reaction conditions.




3 options. – 3 ways to calculate formula.
0.5 N KMnO₄ is read as “0.5 normal”
→ it contains 0.5 gram equivalent of KMnO₄ per litre of solution.

2. Mole Fraction : it is the ratio of its number of moles to the total number of
moles of all the components in the solution.
 ex: If a solution contains 2 mol of alcohol and 3 mol of water, the mole
fraction of alcohol is 2 5 , and that of water 3 . 5 . Sum of mole fractions of
all components = 1




= so moles of solvent or
solute/total moles of component

Mass Percentage: It is the mass of solute present in 100 g of solution.
- Thus 5% solution of KMnO4 in water means that 5 g of KMnO4 is present in
100 g of the aqueous solution of KMnO4 .

Types of solutions :
Solutions can be gaseous,solid, liquid. Depending on the physical state of
solute and solvent, there are 9 possible types of binary solutions

Geschreven voor

Instelling
Junior / 11th grade
Vak
Chemistry
School jaar
3

Documentinformatie

Geüpload op
15 maart 2026
Aantal pagina's
13
Geschreven in
2025/2026
Type
College aantekeningen
Docent(en)
Prittu
Bevat
Alle colleges

Onderwerpen

$8.49
Krijg toegang tot het volledige document:

Verkeerd document? Gratis ruilen Binnen 14 dagen na aankoop en voor het downloaden kun je een ander document kiezen. Je kunt het bedrag gewoon opnieuw besteden.
Geschreven door studenten die geslaagd zijn
Direct beschikbaar na je betaling
Online lezen of als PDF

Maak kennis met de verkoper
Seller avatar
a.t1

Maak kennis met de verkoper

Seller avatar
a.t1
Volgen Je moet ingelogd zijn om studenten of vakken te kunnen volgen
Verkocht
-
Lid sinds
11 maanden
Aantal volgers
0
Documenten
11
Laatst verkocht
-

0.0

0 beoordelingen

5
0
4
0
3
0
2
0
1
0

Recent door jou bekeken

Waarom studenten kiezen voor Stuvia

Gemaakt door medestudenten, geverifieerd door reviews

Kwaliteit die je kunt vertrouwen: geschreven door studenten die slaagden en beoordeeld door anderen die dit document gebruikten.

Niet tevreden? Kies een ander document

Geen zorgen! Je kunt voor hetzelfde geld direct een ander document kiezen dat beter past bij wat je zoekt.

Betaal zoals je wilt, start meteen met leren

Geen abonnement, geen verplichtingen. Betaal zoals je gewend bent via iDeal of creditcard en download je PDF-document meteen.

Student with book image

“Gekocht, gedownload en geslaagd. Zo makkelijk kan het dus zijn.”

Alisha Student

Bezig met je bronvermelding?

Maak nauwkeurige citaten in APA, MLA en Harvard met onze gratis bronnengenerator.

Bezig met je bronvermelding?

Veelgestelde vragen