Addressing & Services Test. Latest
2026-2027. Questions & Correct
Answers. Graded A
A host has an address of 100.55.177.99/16. Which of the following is the
broadcast address for the subnet?
A. 255.255.0.0
B. 100.255.255.255
C. 100.55.255.255
D. 255.255.255.0 - AnsC. 100.55.255.255
A user reports that they cannot browse to a specific website on the internet.
From the user's computer, a computer tech finds that a ping test to the web
server succeeds. A traceroute test shows 17 hops to the destination web
server.
What is the MOST likely cause of the problem?
A. Incorrect default gateway address
B. Duplicate IP addresses
C. Incorrect DNS server address
D. Incorrect subnet mask value - AnsC. Incorrect DNS server address
1
,After you install a new DHCP server on your network, you need to verify
that the network devices are receiving IP addressing via DHCP. You reboot
a Windows 10 client system and, using the ipconfig /all command, receive
the following information:
Ethernet adapter Local Area Connection 1:
Description . . . . . . . . . . . : Intel(R) Ethernet Connection
Physical Address. . . . . . . . . : 02-00-4C-4F-3F-50DHCP Enabled. . . . . . . . .
. . : Yes
Autoconfiguration Enabled . . . . : Yes
Autoconfiguration IPv4 Address. . : 169.254.25.129
Subnet Mask . . . . . . . . . . . : 255.255.0.0
Default Gateway . . . . . . . . . :
DNS Servers . . . . . . . . . . . :
Which of the following statements are true? (Select two).
A. The client system is unable to reach the DHCP server.
B. DHCP is disabled on the client system.
C. The network subnet mask is incorrect.
D. The network is configured to use static IP addressing.
E. The default g - AnsA. The client system is unable to reach the DHCP
server.
F. The client system is configured to use DHCP.
Based on the address prefix for each IPv6 address on the right, identify the
address type from the list on the left. (Addresses may not represent actual
addresses used in production.)
2
,Drag:
A. Global unicast
B. Unique local
C. Link-local
D. Multicast
Drop:
1. 2001:6789:9078::ABCE:AFFF:FE98:0001
2. FD00::8907:FF:FE76:ABC
3. FEA0::AB89:9FF:FE77:1234
4. FF00:98BD:6532::1
5. FF02::1:2 - AnsA-1
B-2
C-3
D-4
D-5
Consider the following IPv6 address: FD01:0001:0001:005::7/64
Drag the component parts of this address on the left to the corresponding
descriptions on the right. (Not all descriptions on the right have
corresponding components on the left.)
Drag:
A. FD01:0001:0001:005
B. :005
C. ::7
D. /64
3
, E.
F. FD
Drop:
1. Global routing prefix
2 Subnet ID
3 Interface ID
4. Prefix length
5. Global ID
6. Unique local unicast prefix - AnsA-1
B-2
C-3
D-4
E-5
F-6
Consider the following output from a dig command run on a Linux system.
; <<>> DiG 8.2 <<>> westsim111.com
;;res options:init recurs defnam dnsrch
;;got answer:
;;->>HEADER<<-opcode:QUERY, status: NOERROR, id:4
;;flags: qr rd ra; QUERY:1, ANSWER:1, AUTHORITY:2, ADDITIONAL:0
;;QUERY SECTION:
;; westsim111.com, type = A, class = IN
;;ANSWER SECTION:
westsim111.com. 7h33m IN A 76.141.43.129
;;AUTHORITY SECTION:
4