13th edition larry j Goldstein complete solutions for 2026
update
, Contents
Chapter Linear Equations and Straight Lines 1–1
1:
Chapter Matrices 2–1
2:
Chapter Linear Programming, A Geometric 3–1
3: Approach
Chapter The Simplex Method 4–1
4:
Chapter Sets and Counting 5–1
5:
Chapter Probability 6–1
6:
Chapter Probability and Statistics 7–1
7:
Chapter Markov Processes 8–1
8:
Chapter The Theory of Games 9–1
9:
Chapter The Mathematics of Finance 10–
10: 1
Chapter Logic 11–
11: 1
Chapter Difference Equations and Mathematical 12–
12: Models 1
, Chapter 1
Exercises 1.1 5
6. Left 1, down
2
1. Right 2, up 3 y
y
(2, 3)
x
x
( )
–1, – 52
7. Left 20, up 40
2. Left 1, up 4 y
y
(–20, 40)
(–1, 4)
x
x
8. Right 25, up 30
3. Down 2 y
y
(25, 30)
x
x
(0, –2)
9. Point Q is 2 units to the left and 2 units up or
4. Right 2
y (—2, 2).
10. Point P is 3 units to the right and 2 units down or
(3,—2).
x
(2, 0) 1
11. —2(1) + (3) = —2 +1 = —1so yes the point is
3
on the line.
5. Left 2, up 1 1
y 12. —2(2) + (6) = —1 is false, so no the point is not
3
on the line
(–2, 1)
x
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Chapter 1: Linear Equations and Straight Lines ISM: Finite Math
1 24. 0 = 5
13 —2x + y = —1 Substitute the x and y no solution
3
. x-intercept: none
coordinates of the point into the equation:
f 1 hı f h When x = 0, y = 5
' , 3 → —2 ' 1 ı + 1 (3) = —1 → —1+1 = —1 is y-intercept: (0, 5)
y' ı 'y ıJ
2 J 2 3
a false statement. So no the point is not on 25. When y = 0, x = 7
theline. x-intercept: (7, 0)
f 1h f1h 0=7
14 —2 ' ı + ' ı (—1) = —1 is true so yes the point is no solution
.
'y3 ıJ 'y3 ıJ y-intercept: none
on the line. 26. 0 = –8x
15. m = 5, b = 8 x=0
x-intercept: (0, 0)
16. m = –2 and b = –6 y = –8(0)
y=0
17. y = 0x + 3; m = 0, b = 3 y-intercept: (0, 0)
2 2 1
y = x + 0; m = , b = 0 27 0 = x –1
18 3
3 3 .
. x=3
19. 14x + 7 y = 21 x-intercept: (3, 0)
1
7 y = —14x + 21 y = (0) – 1
3
y = —2x + 3
y = –1
y-intercept: (0, –1)
20 x— y =3 y
. —y = —x + 3
y = x —3
(3, 0)
21. 3x = 5 x
5 (0, –1)
x=
3
1 2
28. When x = 0, y = 0.
22 – x+ y = 10
. 2 3 When x = 1, y = 2.
2 1 y
y= x +10
3 2
3
y = x +15 (1, 2)
4 x
(0, 0)
23. 0 = —4x + 8
4x = 8
x=2
x-intercept: (2, 0)
y = –4(0) + 8
y=8
y-intercept: (0, 8)
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