QUESTIONS WITH SOLUTIONS GRADED A+
● If the PM output voltage is 5v and the measured lead resistance is 330
ohms, then the current that flows out of the pacemaker into the heart is?
Answer: 15.15
I=V/R=5V/.33 k ohm
● If a unipolar lead wire has an insulation break one would expect the
resistance to? Answer: decrease
● for a wire fracture the resistance? Answer: increases
● if the output vlotage of the pacemaker is programmed from 5 volts to
2.5 volts, the energy delivered to the heart is? Answer: quartered
● Which of the following affect the longevity of the PM? Answer:
output voltage, resistance of lead and amount % pacing
● Which Pt's PM will last longer? Answer: #1: AMP=5V, L.R.=90,
resistance 500ohms, PW=.5ms, 100%pacing
#2: AMP=5V, L.R.=60, resistance 500ohms, PW=.5ms, 100%pacing
#3: AMP=2.5V, L.R.=60, resistance 330ohms, PW=.5ms, 100% pacing
, (#4: AMP=2.5v, L.R.=60, resistance 500ohms, PW=.5ms, 50%pacing)
● The strength duration curve is dependent on the? Answer: Cell's
membrane capacitance, intracellular and extracellular resistance and
threshold voltage.
● A patient on flecainide should? Answer: Have their threshold checked
● The acute threshold peaking is due to? Answer: Trauma and
inflammation
● An advantage of bipolar leads is? Answer: They are less susceptible to
EMI
● The two parameters that are important for ventricular sensing and
should be measured are? Answer: R-wave amplitude and slew rate
● If an external PM is set to a sensitivity setting of 5mV and some R-
waves go unsensed, then you should do the following Answer: Increase
sensing by lowering sensitivity to 2.5mV.
● Typical acceptable R-wave amplitude values for an acute ventricular
lead is? Answer: 7-15mV