NURS 6501 ADVANCED PATHOPHYSIOLOGY MIDTERM
EXAM 2026/2027 | Latest Complete Guide | Questions and
Verified Answers | Pass Guaranteed - A+ Graded
Unit 1: Cellular Function, Genetics & Neoplasia (18 Questions)
Q1: A 58-year-old male with a 40-pack-year smoking history presents with a chronic
cough and hemoptysis. Bronchial biopsy reveals squamous metaplasia of the
respiratory epithelium. Which cellular adaptation is demonstrated, and what is the
primary stimulus driving this change?
A. Dysplasia in response to chronic hypoxia
B. Metaplasia in response to chronic irritation and inflammation
C. Hyperplasia due to increased cellular demand
D. Hypertrophy secondary to mechanical stress
Correct Answer: B
Rationale: Metaplasia is the reversible replacement of one differentiated cell type with
another mature differentiated cell type. In this case, the normal pseudostratified ciliated
columnar epithelium is replaced by squamous epithelium (squamous metaplasia) due
to chronic irritation from cigarette smoke. This represents an adaptive response to
better withstand the noxious environment, though it increases cancer risk.
Why other options are incorrect: Option A (dysplasia) describes disordered,
dysfunctional cell growth with loss of uniformity and architectural orientation—this is
pre-neoplastic, not the adaptive change described. Option C (hyperplasia) involves
increased cell number, not cell type replacement. Option D (hypertrophy) involves
increased cell size without cell division. The stimulus for metaplasia is chronic
,irritation/inflammation, not hypoxia, increased demand, or mechanical stress. While
metaplasia is reversible if the stimulus is removed, persistent metaplasia can progress
to dysplasia and carcinoma (squamous cell lung cancer).
Q2: A 45-year-old woman with chronic hypertension has left ventricular wall thickness of
15 mm (normal 8-11 mm) on echocardiogram. The cardiomyocytes demonstrate
enlarged cells with increased organelle content. Which cellular adaptation is present?
A. Hyperplasia of cardiac muscle cells
B. Hypertrophy of cardiomyocytes due to increased workload
C. Atrophy from chronic ischemia
D. Metaplasia to a more durable cell type
Correct Answer: B
Rationale: Hypertrophy is the increase in cell size resulting in increased tissue mass
without cell division. Cardiac muscle is permanent tissue (terminally differentiated cells
that rarely divide), so adaptation to increased afterload (hypertension) occurs through
cellular enlargement with increased sarcomeres, mitochondria, and endoplasmic
reticulum. This increases contractile force to overcome elevated systemic vascular
resistance.
Why other options are incorrect: Option A (hyperplasia) is impossible in adult cardiac
muscle cells; they cannot divide. Option C (atrophy) would show decreased cell size, not
increased wall thickness. Option D (metaplasia) does not occur in cardiac muscle;
metaplasia occurs in epithelial tissues. Concentric hypertrophy (increased wall
thickness with normal chamber size) is the typical response to pressure overload
(hypertension), while eccentric hypertrophy (dilated chamber) occurs with volume
overload. Prolonged hypertrophy can lead to cellular dysfunction, apoptosis, and heart
failure.
,Q3: A 28-year-old woman undergoes bilateral mastectomy and immediate
reconstruction. Six months later, histologic examination of the breast tissue reveals
lobular atrophy with decreased lobular-alveolar units and increased fibrous tissue.
Which mechanism explains these findings?
A. Apoptosis of glandular cells due to loss of hormonal stimulation and surgical
denervation
B. Necrosis from ischemic injury during surgery
C. Metaplasia to fibrous tissue
D. Hypertrophy of remaining tissue
Correct Answer: A
Rationale: Atrophy is the reduction in cell/tissue size due to decreased workload, loss of
innervation, diminished blood supply, inadequate nutrition, or loss of endocrine
stimulation. Post-mastectomy reconstruction without lactational demand demonstrates
disuse atrophy—the glandular tissue involutes due to absence of hormonal stimulation
(prolactin, placental lactogen, oxytocin) and surgical denervation of the nipple-areolar
complex. The remaining tissue is replaced by fibrous stroma.
Why other options are incorrect: Option B (necrosis) would show coagulative changes,
inflammatory infiltrate, and cell death—not organized atrophy. Option C (metaplasia)
involves cell type change, not tissue loss. Option D (hypertrophy) is the opposite
process. Atrophy can be physiologic (thymus involution, post-lactational breast
regression) or pathologic (denervation, ischemia, malnutrition). The cellular mechanism
involves decreased protein synthesis and increased protein degradation via
ubiquitin-proteasome pathway and autophagy.
, Q4: A liver biopsy from a chronic alcoholic shows hepatocytes with clear, discrete
vacuoles that displace the nucleus to the periphery, creating a "signet ring" appearance.
Which cellular injury is demonstrated?
A. Hydropic change due to impaired Na+/K+-ATPase
B. Fatty change (steatosis) due to impaired lipoprotein export
C. Glycogen accumulation from diabetes mellitus
D. Protein accumulation from alpha-1-antitrypsin deficiency
Correct Answer: B
Rationale: Fatty change (steatosis) is the accumulation of triglycerides within
parenchymal cells. In chronic alcoholism, ethanol metabolism creates excess NADH,
promoting fatty acid synthesis and inhibiting beta-oxidation. Additionally, alcohol
impairs apolipoprotein synthesis and VLDL export, trapping lipids in hepatocytes. The
large, clear vacuole pushing the nucleus peripherally is pathognomonic for
macrovesicular steatosis.
Why other options are incorrect: Option A (hydropic change) shows diffuse cytoplasmic
swelling from water accumulation, not discrete vacuoles. Option C (glycogen) appears
as diffuse, ground-glass cytoplasm (best seen in PAS stains), not clear vacuoles. Option
D (alpha-1-antitrypsin) shows PAS-positive, diastase-resistant globules in hepatocytes.
Steatosis is reversible with alcohol cessation. Persistent steatosis can progress to
steatohepatitis (NASH), fibrosis, and cirrhosis through mechanisms involving oxidative
stress, mitochondrial dysfunction, and cytokine activation.
Q5: A 65-year-old man with atherosclerosis suffers acute myocardial infarction.
Histology of the infarcted area 3 days post-MI shows neutrophilic infiltrate, coagulative
necrosis with preserved cell outlines, and loss of nuclei. Which type of necrosis is
present?
EXAM 2026/2027 | Latest Complete Guide | Questions and
Verified Answers | Pass Guaranteed - A+ Graded
Unit 1: Cellular Function, Genetics & Neoplasia (18 Questions)
Q1: A 58-year-old male with a 40-pack-year smoking history presents with a chronic
cough and hemoptysis. Bronchial biopsy reveals squamous metaplasia of the
respiratory epithelium. Which cellular adaptation is demonstrated, and what is the
primary stimulus driving this change?
A. Dysplasia in response to chronic hypoxia
B. Metaplasia in response to chronic irritation and inflammation
C. Hyperplasia due to increased cellular demand
D. Hypertrophy secondary to mechanical stress
Correct Answer: B
Rationale: Metaplasia is the reversible replacement of one differentiated cell type with
another mature differentiated cell type. In this case, the normal pseudostratified ciliated
columnar epithelium is replaced by squamous epithelium (squamous metaplasia) due
to chronic irritation from cigarette smoke. This represents an adaptive response to
better withstand the noxious environment, though it increases cancer risk.
Why other options are incorrect: Option A (dysplasia) describes disordered,
dysfunctional cell growth with loss of uniformity and architectural orientation—this is
pre-neoplastic, not the adaptive change described. Option C (hyperplasia) involves
increased cell number, not cell type replacement. Option D (hypertrophy) involves
increased cell size without cell division. The stimulus for metaplasia is chronic
,irritation/inflammation, not hypoxia, increased demand, or mechanical stress. While
metaplasia is reversible if the stimulus is removed, persistent metaplasia can progress
to dysplasia and carcinoma (squamous cell lung cancer).
Q2: A 45-year-old woman with chronic hypertension has left ventricular wall thickness of
15 mm (normal 8-11 mm) on echocardiogram. The cardiomyocytes demonstrate
enlarged cells with increased organelle content. Which cellular adaptation is present?
A. Hyperplasia of cardiac muscle cells
B. Hypertrophy of cardiomyocytes due to increased workload
C. Atrophy from chronic ischemia
D. Metaplasia to a more durable cell type
Correct Answer: B
Rationale: Hypertrophy is the increase in cell size resulting in increased tissue mass
without cell division. Cardiac muscle is permanent tissue (terminally differentiated cells
that rarely divide), so adaptation to increased afterload (hypertension) occurs through
cellular enlargement with increased sarcomeres, mitochondria, and endoplasmic
reticulum. This increases contractile force to overcome elevated systemic vascular
resistance.
Why other options are incorrect: Option A (hyperplasia) is impossible in adult cardiac
muscle cells; they cannot divide. Option C (atrophy) would show decreased cell size, not
increased wall thickness. Option D (metaplasia) does not occur in cardiac muscle;
metaplasia occurs in epithelial tissues. Concentric hypertrophy (increased wall
thickness with normal chamber size) is the typical response to pressure overload
(hypertension), while eccentric hypertrophy (dilated chamber) occurs with volume
overload. Prolonged hypertrophy can lead to cellular dysfunction, apoptosis, and heart
failure.
,Q3: A 28-year-old woman undergoes bilateral mastectomy and immediate
reconstruction. Six months later, histologic examination of the breast tissue reveals
lobular atrophy with decreased lobular-alveolar units and increased fibrous tissue.
Which mechanism explains these findings?
A. Apoptosis of glandular cells due to loss of hormonal stimulation and surgical
denervation
B. Necrosis from ischemic injury during surgery
C. Metaplasia to fibrous tissue
D. Hypertrophy of remaining tissue
Correct Answer: A
Rationale: Atrophy is the reduction in cell/tissue size due to decreased workload, loss of
innervation, diminished blood supply, inadequate nutrition, or loss of endocrine
stimulation. Post-mastectomy reconstruction without lactational demand demonstrates
disuse atrophy—the glandular tissue involutes due to absence of hormonal stimulation
(prolactin, placental lactogen, oxytocin) and surgical denervation of the nipple-areolar
complex. The remaining tissue is replaced by fibrous stroma.
Why other options are incorrect: Option B (necrosis) would show coagulative changes,
inflammatory infiltrate, and cell death—not organized atrophy. Option C (metaplasia)
involves cell type change, not tissue loss. Option D (hypertrophy) is the opposite
process. Atrophy can be physiologic (thymus involution, post-lactational breast
regression) or pathologic (denervation, ischemia, malnutrition). The cellular mechanism
involves decreased protein synthesis and increased protein degradation via
ubiquitin-proteasome pathway and autophagy.
, Q4: A liver biopsy from a chronic alcoholic shows hepatocytes with clear, discrete
vacuoles that displace the nucleus to the periphery, creating a "signet ring" appearance.
Which cellular injury is demonstrated?
A. Hydropic change due to impaired Na+/K+-ATPase
B. Fatty change (steatosis) due to impaired lipoprotein export
C. Glycogen accumulation from diabetes mellitus
D. Protein accumulation from alpha-1-antitrypsin deficiency
Correct Answer: B
Rationale: Fatty change (steatosis) is the accumulation of triglycerides within
parenchymal cells. In chronic alcoholism, ethanol metabolism creates excess NADH,
promoting fatty acid synthesis and inhibiting beta-oxidation. Additionally, alcohol
impairs apolipoprotein synthesis and VLDL export, trapping lipids in hepatocytes. The
large, clear vacuole pushing the nucleus peripherally is pathognomonic for
macrovesicular steatosis.
Why other options are incorrect: Option A (hydropic change) shows diffuse cytoplasmic
swelling from water accumulation, not discrete vacuoles. Option C (glycogen) appears
as diffuse, ground-glass cytoplasm (best seen in PAS stains), not clear vacuoles. Option
D (alpha-1-antitrypsin) shows PAS-positive, diastase-resistant globules in hepatocytes.
Steatosis is reversible with alcohol cessation. Persistent steatosis can progress to
steatohepatitis (NASH), fibrosis, and cirrhosis through mechanisms involving oxidative
stress, mitochondrial dysfunction, and cytokine activation.
Q5: A 65-year-old man with atherosclerosis suffers acute myocardial infarction.
Histology of the infarcted area 3 days post-MI shows neutrophilic infiltrate, coagulative
necrosis with preserved cell outlines, and loss of nuclei. Which type of necrosis is
present?
