AQA A LEVEL PHYSICS PAPER 2 EXAM SCRIPT
2026 TEST PAPER QUESTIONS AND
SOLUTIONS GRADED A+
◉ M (Nm). Answer: = F (N) X d (m) (the unit for moments is Nm and
not J as a moment is a turning effect, not an energy)
◉ gears. Answer: use the principle of moments to transmit a turning
effect - different sized gears can be used to change a moment - a gear
turns in the opposite direction to the gear it is attached to - gear =
cog
◉ centre of mass. Answer: the point in an object at which its mass
can be thought of as being concentrated
◉ pressure. Answer: the amount of force exerted per unit squared of
the area of the object
◉ fluids. Answer: substances that flow because their particles are
able to move around - fluids include liquids and gases
◉ fluid pressure. Answer: p = f ÷ a
,(pressure in Pa) = (force perp. to a surface in N) ÷ (area of that
surface in m²)
◉ 1 Pa. Answer: = 1N/m²
◉ liquid pressure. Answer: this depends also on depth and density,
as:
1. the more dense the liquid is, the more collisions happen
2. the more depth there is, the more particles there are above any
given point, so the pressure from above increases as we go deeper
so:
p=hXρXg
(pressure in Pa) = (depth/height in m) X (density in kg/m³) X
(gravitational field strength in N/kg (9.81 on Earth))
◉ atmosphere. Answer: the layer of gas surrounding the Earth
◉ atmospheric pressure. Answer: this decreases as altitude
increases as there are less particles at higher altitudes so the
pressure is less
◉ speed. Answer: the rate of change of position with time - scalar
, ◉ velocity. Answer: the rate of change of position with time in a
given direction (speed with direction) - vector
◉ speed (m/s). Answer: = distance (m) ÷ time (s)
◉ distance-time graphs. Answer: time is always on the x axis,
distance on the y
an upwards/downwards line shows distance being covered - you
can work out the speed from a distance-time graph
◉ velocity-time graphs. Answer: time is always on the x axis, velocity
on the y
an upwards/downwards line would show acceleration/deceleration,
and a horizontal line would show constant speed - you can work out
the acceleration/deceleration in different sections of a velocity-time
graph
◉ average velocity. Answer: = (v+u) ÷ 2
◉ acceleration. Answer: = force ÷ mass (can be rearranged so f=ma)
◉ acceleration (m/s²)
a. Answer: = (final velocity (m/s) - initial velocity (m/s)) ÷ time (s)
= (v-u)÷t
2026 TEST PAPER QUESTIONS AND
SOLUTIONS GRADED A+
◉ M (Nm). Answer: = F (N) X d (m) (the unit for moments is Nm and
not J as a moment is a turning effect, not an energy)
◉ gears. Answer: use the principle of moments to transmit a turning
effect - different sized gears can be used to change a moment - a gear
turns in the opposite direction to the gear it is attached to - gear =
cog
◉ centre of mass. Answer: the point in an object at which its mass
can be thought of as being concentrated
◉ pressure. Answer: the amount of force exerted per unit squared of
the area of the object
◉ fluids. Answer: substances that flow because their particles are
able to move around - fluids include liquids and gases
◉ fluid pressure. Answer: p = f ÷ a
,(pressure in Pa) = (force perp. to a surface in N) ÷ (area of that
surface in m²)
◉ 1 Pa. Answer: = 1N/m²
◉ liquid pressure. Answer: this depends also on depth and density,
as:
1. the more dense the liquid is, the more collisions happen
2. the more depth there is, the more particles there are above any
given point, so the pressure from above increases as we go deeper
so:
p=hXρXg
(pressure in Pa) = (depth/height in m) X (density in kg/m³) X
(gravitational field strength in N/kg (9.81 on Earth))
◉ atmosphere. Answer: the layer of gas surrounding the Earth
◉ atmospheric pressure. Answer: this decreases as altitude
increases as there are less particles at higher altitudes so the
pressure is less
◉ speed. Answer: the rate of change of position with time - scalar
, ◉ velocity. Answer: the rate of change of position with time in a
given direction (speed with direction) - vector
◉ speed (m/s). Answer: = distance (m) ÷ time (s)
◉ distance-time graphs. Answer: time is always on the x axis,
distance on the y
an upwards/downwards line shows distance being covered - you
can work out the speed from a distance-time graph
◉ velocity-time graphs. Answer: time is always on the x axis, velocity
on the y
an upwards/downwards line would show acceleration/deceleration,
and a horizontal line would show constant speed - you can work out
the acceleration/deceleration in different sections of a velocity-time
graph
◉ average velocity. Answer: = (v+u) ÷ 2
◉ acceleration. Answer: = force ÷ mass (can be rearranged so f=ma)
◉ acceleration (m/s²)
a. Answer: = (final velocity (m/s) - initial velocity (m/s)) ÷ time (s)
= (v-u)÷t
