Nicet Level 1 - Water Based Layout
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Nicet Level 1 water based systems NICET Level 1 ITM Of Water-Based S... NICET Water-Based Systems Layout ... NICET
50 terms 104 terms 111 terms 176 term
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Toggle hangers shall be permitted only for the support 1 2/2 in. (ref. NFPA 13 2016 Sec. 9.2.1.1.2.
of pipe __________ inches or smaller in size under ceilings of
hollow tile or metal lath and plaster.
While conducting a flow test, the chosen hydrant should As close to the property where the sprinkler system is being installed. (Ref, NFPA
be ______ 13 Sec. A.24.2.2. or NFPA 291)
What formula is used to determine the discharge K = Q / (Square root of P)
coefficiant relating pressure and flow rate?
What best describes a tree system? Cross mains and the branch lines are not tied together, providing only one path of
water flow.
Factors that define Occupancy Group Hazard 2 include: Quantity and combustibility of contents are moderate to high.
Stockpiles of contents with moderate rates of heat release do not exceed 12 ft
and stockpiles with high heat release do not exceed 8 ft
(Ref NFPA 13 Sec. 5.3.2)
Which of the following standards contain reqs. pertaining NFPA 13 & 24 (Both in Chapter 10)
to the installation of underground piping?
Which of the following should you inspect on an The grounding prong & the insulation for nicks, cuts, or damage
extension cord before each use?
________ indicates a mandatory req. according to NFPA Shall.
definitions.
(Ref. NFPA 13 2016, Sec. 3.2.4.)
, 100 GPM is flowing through 100' of 1 1/4 in. Sch. 40 pipe. Assume this is Schedule 40 pipe, C = 120. Use the Hazen-Williams formula to
How many feet of 1 1/2 in. pipe will produce the same calculate the friction loss for the 1 ¼ in. pipe and the 1 ½ in. pipe.
friction loss?
For 1 ¼ in. pipe (ID = 1.38):
P friction loss = 4.52 x Q 1.85
c 1.85 x d 4.87
P friction loss = 4.52 x 100 1.85
120 1.85 x 1.38 4.87
P friction loss = 0.672 psi/ft
For 1 ½ in. pipe (ID = 1.61):
P friction loss = 4.52 x Q 1.85
c 1.85 x d 4.87
P friction loss = 4.52 x 100 1.85
120 1.85 x 1.61 4.87
P friction loss = 0.317 psi/ft
Step #2: Determine the total friction loss for 100 gpm flowing through 100 ft. of 1 ¼
in. Schedule 40 black steel pipe: 100 ft. x 0.672 psi/ft = 67.2 psi
Step #3: Determine the pipe length to produce the same friction loss in the 1 ½ in.
pipe:
y ft. x 0.317 psi/ft = 67.2 psi
y = 67.2 ÷ 0.317
y = 212 ft.
A basic contract: (choose all that apply) Contains the names of the parties involved, References the contract documents,
Discusses the work that is to be done, and Discusses start and completion dates.
Save
Students also studied
Nicet Level 1 water based systems NICET Level 1 ITM Of Water-Based S... NICET Water-Based Systems Layout ... NICET
50 terms 104 terms 111 terms 176 term
Valdez4142 Preview dillon_buckles Preview lakain Preview cold
Toggle hangers shall be permitted only for the support 1 2/2 in. (ref. NFPA 13 2016 Sec. 9.2.1.1.2.
of pipe __________ inches or smaller in size under ceilings of
hollow tile or metal lath and plaster.
While conducting a flow test, the chosen hydrant should As close to the property where the sprinkler system is being installed. (Ref, NFPA
be ______ 13 Sec. A.24.2.2. or NFPA 291)
What formula is used to determine the discharge K = Q / (Square root of P)
coefficiant relating pressure and flow rate?
What best describes a tree system? Cross mains and the branch lines are not tied together, providing only one path of
water flow.
Factors that define Occupancy Group Hazard 2 include: Quantity and combustibility of contents are moderate to high.
Stockpiles of contents with moderate rates of heat release do not exceed 12 ft
and stockpiles with high heat release do not exceed 8 ft
(Ref NFPA 13 Sec. 5.3.2)
Which of the following standards contain reqs. pertaining NFPA 13 & 24 (Both in Chapter 10)
to the installation of underground piping?
Which of the following should you inspect on an The grounding prong & the insulation for nicks, cuts, or damage
extension cord before each use?
________ indicates a mandatory req. according to NFPA Shall.
definitions.
(Ref. NFPA 13 2016, Sec. 3.2.4.)
, 100 GPM is flowing through 100' of 1 1/4 in. Sch. 40 pipe. Assume this is Schedule 40 pipe, C = 120. Use the Hazen-Williams formula to
How many feet of 1 1/2 in. pipe will produce the same calculate the friction loss for the 1 ¼ in. pipe and the 1 ½ in. pipe.
friction loss?
For 1 ¼ in. pipe (ID = 1.38):
P friction loss = 4.52 x Q 1.85
c 1.85 x d 4.87
P friction loss = 4.52 x 100 1.85
120 1.85 x 1.38 4.87
P friction loss = 0.672 psi/ft
For 1 ½ in. pipe (ID = 1.61):
P friction loss = 4.52 x Q 1.85
c 1.85 x d 4.87
P friction loss = 4.52 x 100 1.85
120 1.85 x 1.61 4.87
P friction loss = 0.317 psi/ft
Step #2: Determine the total friction loss for 100 gpm flowing through 100 ft. of 1 ¼
in. Schedule 40 black steel pipe: 100 ft. x 0.672 psi/ft = 67.2 psi
Step #3: Determine the pipe length to produce the same friction loss in the 1 ½ in.
pipe:
y ft. x 0.317 psi/ft = 67.2 psi
y = 67.2 ÷ 0.317
y = 212 ft.
A basic contract: (choose all that apply) Contains the names of the parties involved, References the contract documents,
Discusses the work that is to be done, and Discusses start and completion dates.
