Accredited Test Bank Solution For
Algebra and Trigonometry, 12th Edition
Sullivan [All Lessons Included]
Complete Chapter Solution Manual
are Included (Ch.1 to Ch.12)
• Rapid Download
• Quick Turnaround
• Complete Chapters Provided
, Table of Contents are Given Below
The "Algebra and Trigonometry, 12th Edition" by Michael Sullivan comprises the following chapters:
1. Equations and Inequalities
2. Graphs
3. Functions and Their Graphs
4. Linear and Quadratic Functions
5. Polynomial and Rational Functions
6. Exponential and Logarithmic Functions
7. Trigonometric Functions
8. Analytic Trigonometry
9. Applications of Trigonometric Functions
10. Polar Coordinates; Vectors
11. Analytic Geometry
12. Systems of Equations and Inequalities
13. Sequences; Induction; the Binomial Theorem
14. Counting and Probability
Each chapter includes a review, test, cumulative review, and projects to reinforce learning.
1. Equations and Inequalities (33 Questions)
1.1 Linear and Quadratic Equations
1. What is the solution to the equation 2x+5=112x + 5 = 112x+5=11?
o a) x=3x = 3x=3
o b) x=−3x = -3x=−3
o c) x=6x = 6x=6
o d) x=5x = 5x=5
Answer: a) x=3x = 3x=3
Explanation: Subtract 5 from both sides: 2x=62x = 62x=6. Then divide by 2: x=3x = 3x=3.
PAGE 1
, 2. Solve for xxx: x2−4x−12=0x^2 - 4x - 12 = 0x2−4x−12=0.
o a) x=6x = 6x=6, x=−2x = -2x=−2
o b) x=4x = 4x=4, x=−3x = -3x=−3
o c) x=3x = 3x=3, x=−4x = -4x=−4
o d) x=2x = 2x=2, x=−6x = -6x=−6
Answer: a) x=6x = 6x=6, x=−2x = -2x=−2
Explanation: Factor the equation as (x−6)(x+2)=0(x - 6)(x + 2) = 0(x−6)(x+2)=0. So x=6x = 6x=6 or x=−2x = -
2x=−2.
3. Which of the following is a solution to the equation 3x2−5x+2=03x^2 - 5x + 2 = 03x2−5x+2=0?
o a) x=1x = 1x=1
o b) x=2x = 2x=2
o c) x=−1x = -1x=−1
o d) x=13x = \frac{1}{3}x=31
Answer: c) x=−1x = -1x=−1
Explanation: Use the quadratic formula to find the roots. The solution is x=−1x = -1x=−1.
4. The quadratic equation x2+5x+6=0x^2 + 5x + 6 = 0x2+5x+6=0 factors as:
o a) (x+2)(x+3)=0(x + 2)(x + 3) = 0(x+2)(x+3)=0
o b) (x−2)(x+3)=0(x - 2)(x + 3) = 0(x−2)(x+3)=0
o c) (x+1)(x+6)=0(x + 1)(x + 6) = 0(x+1)(x+6)=0
o d) (x+1)(x+5)=0(x + 1)(x + 5) = 0(x+1)(x+5)=0
Answer: a) (x+2)(x+3)=0(x + 2)(x + 3) = 0(x+2)(x+3)=0
Explanation: The quadratic factors as (x+2)(x+3)=0(x + 2)(x + 3) = 0(x+2)(x+3)=0, so x=−2x = -2x=−2, x=−3x = -
3x=−3.
5. What is the solution set for the inequality 3x−7>2x+13x - 7 > 2x + 13x−7>2x+1?
o a) x>−6x > -6x>−6
o b) x>6x > 6x>6
o c) x<−6x < -6x<−6
o d) x<6x < 6x<6
Answer: a) x>−6x > -6x>−6
Explanation: Subtract 2x2x2x from both sides: x−7>1x - 7 > 1x−7>1. Add 7 to both sides: x>8x > 8x>8.
PAGE 2
, 1.2 Rational Equations
6. Solve the equation 1x=3\frac{1}{x} = 3x1=3.
o a) x=1x = 1x=1
o b) x=3x = 3x=3
o c) x=13x = \frac{1}{3}x=31
o d) x=−3x = -3x=−3
Answer: c) x=13x = \frac{1}{3}x=31
Explanation: Multiply both sides by xxx: 1=3x1 = 3x1=3x. Then divide by 3: x=13x = \frac{1}{3}x=31.
7. Solve x+2x−3=4\frac{x + 2}{x - 3} = 4x−3x+2=4.
o a) x=6x = 6x=6
o b) x=5x = 5x=5
o c) x=3x = 3x=3
o d) x=−1x = -1x=−1
Answer: b) x=5x = 5x=5
Explanation: Multiply both sides by x−3x - 3x−3: x+2=4(x−3)x + 2 = 4(x - 3)x+2=4(x−3). Simplifying leads to x=5x
= 5x=5.
8. The solution to 1x+2+2x+2=3\frac{1}{x + 2} + \frac{2}{x + 2} = 3x+21+x+22=3 is:
o a) x=−1x = -1x=−1
o b) x=1x = 1x=1
o c) x=2x = 2x=2
o d) x=−3x = -3x=−3
Answer: a) x=−1x = -1x=−1
Explanation: Combine the fractions: 3x+2=3\frac{3}{x + 2} = 3x+23=3. Then multiply both sides by x+2x + 2x+2 to
get 3=3(x+2)3 = 3(x + 2)3=3(x+2), so x=−1x = -1x=−1.
9. Solve the rational equation 5x−2=1x+2\frac{5}{x - 2} = \frac{1}{x + 2}x−25=x+21.
o a) x=3x = 3x=3
o b) x=−3x = -3x=−3
o c) x=2x = 2x=2
o d) x=−2x = -2x=−2
PAGE 3
Algebra and Trigonometry, 12th Edition
Sullivan [All Lessons Included]
Complete Chapter Solution Manual
are Included (Ch.1 to Ch.12)
• Rapid Download
• Quick Turnaround
• Complete Chapters Provided
, Table of Contents are Given Below
The "Algebra and Trigonometry, 12th Edition" by Michael Sullivan comprises the following chapters:
1. Equations and Inequalities
2. Graphs
3. Functions and Their Graphs
4. Linear and Quadratic Functions
5. Polynomial and Rational Functions
6. Exponential and Logarithmic Functions
7. Trigonometric Functions
8. Analytic Trigonometry
9. Applications of Trigonometric Functions
10. Polar Coordinates; Vectors
11. Analytic Geometry
12. Systems of Equations and Inequalities
13. Sequences; Induction; the Binomial Theorem
14. Counting and Probability
Each chapter includes a review, test, cumulative review, and projects to reinforce learning.
1. Equations and Inequalities (33 Questions)
1.1 Linear and Quadratic Equations
1. What is the solution to the equation 2x+5=112x + 5 = 112x+5=11?
o a) x=3x = 3x=3
o b) x=−3x = -3x=−3
o c) x=6x = 6x=6
o d) x=5x = 5x=5
Answer: a) x=3x = 3x=3
Explanation: Subtract 5 from both sides: 2x=62x = 62x=6. Then divide by 2: x=3x = 3x=3.
PAGE 1
, 2. Solve for xxx: x2−4x−12=0x^2 - 4x - 12 = 0x2−4x−12=0.
o a) x=6x = 6x=6, x=−2x = -2x=−2
o b) x=4x = 4x=4, x=−3x = -3x=−3
o c) x=3x = 3x=3, x=−4x = -4x=−4
o d) x=2x = 2x=2, x=−6x = -6x=−6
Answer: a) x=6x = 6x=6, x=−2x = -2x=−2
Explanation: Factor the equation as (x−6)(x+2)=0(x - 6)(x + 2) = 0(x−6)(x+2)=0. So x=6x = 6x=6 or x=−2x = -
2x=−2.
3. Which of the following is a solution to the equation 3x2−5x+2=03x^2 - 5x + 2 = 03x2−5x+2=0?
o a) x=1x = 1x=1
o b) x=2x = 2x=2
o c) x=−1x = -1x=−1
o d) x=13x = \frac{1}{3}x=31
Answer: c) x=−1x = -1x=−1
Explanation: Use the quadratic formula to find the roots. The solution is x=−1x = -1x=−1.
4. The quadratic equation x2+5x+6=0x^2 + 5x + 6 = 0x2+5x+6=0 factors as:
o a) (x+2)(x+3)=0(x + 2)(x + 3) = 0(x+2)(x+3)=0
o b) (x−2)(x+3)=0(x - 2)(x + 3) = 0(x−2)(x+3)=0
o c) (x+1)(x+6)=0(x + 1)(x + 6) = 0(x+1)(x+6)=0
o d) (x+1)(x+5)=0(x + 1)(x + 5) = 0(x+1)(x+5)=0
Answer: a) (x+2)(x+3)=0(x + 2)(x + 3) = 0(x+2)(x+3)=0
Explanation: The quadratic factors as (x+2)(x+3)=0(x + 2)(x + 3) = 0(x+2)(x+3)=0, so x=−2x = -2x=−2, x=−3x = -
3x=−3.
5. What is the solution set for the inequality 3x−7>2x+13x - 7 > 2x + 13x−7>2x+1?
o a) x>−6x > -6x>−6
o b) x>6x > 6x>6
o c) x<−6x < -6x<−6
o d) x<6x < 6x<6
Answer: a) x>−6x > -6x>−6
Explanation: Subtract 2x2x2x from both sides: x−7>1x - 7 > 1x−7>1. Add 7 to both sides: x>8x > 8x>8.
PAGE 2
, 1.2 Rational Equations
6. Solve the equation 1x=3\frac{1}{x} = 3x1=3.
o a) x=1x = 1x=1
o b) x=3x = 3x=3
o c) x=13x = \frac{1}{3}x=31
o d) x=−3x = -3x=−3
Answer: c) x=13x = \frac{1}{3}x=31
Explanation: Multiply both sides by xxx: 1=3x1 = 3x1=3x. Then divide by 3: x=13x = \frac{1}{3}x=31.
7. Solve x+2x−3=4\frac{x + 2}{x - 3} = 4x−3x+2=4.
o a) x=6x = 6x=6
o b) x=5x = 5x=5
o c) x=3x = 3x=3
o d) x=−1x = -1x=−1
Answer: b) x=5x = 5x=5
Explanation: Multiply both sides by x−3x - 3x−3: x+2=4(x−3)x + 2 = 4(x - 3)x+2=4(x−3). Simplifying leads to x=5x
= 5x=5.
8. The solution to 1x+2+2x+2=3\frac{1}{x + 2} + \frac{2}{x + 2} = 3x+21+x+22=3 is:
o a) x=−1x = -1x=−1
o b) x=1x = 1x=1
o c) x=2x = 2x=2
o d) x=−3x = -3x=−3
Answer: a) x=−1x = -1x=−1
Explanation: Combine the fractions: 3x+2=3\frac{3}{x + 2} = 3x+23=3. Then multiply both sides by x+2x + 2x+2 to
get 3=3(x+2)3 = 3(x + 2)3=3(x+2), so x=−1x = -1x=−1.
9. Solve the rational equation 5x−2=1x+2\frac{5}{x - 2} = \frac{1}{x + 2}x−25=x+21.
o a) x=3x = 3x=3
o b) x=−3x = -3x=−3
o c) x=2x = 2x=2
o d) x=−2x = -2x=−2
PAGE 3
