AQA AS PHYSICS PAPER 2 EXAM SCRIPT 2026
TESTED QUESTIONS AND CORRECT ANSWERS
ALREADY PASSED
◉ velocity-time graphs. Answer: time is always on the x axis, velocity
on the y
an upwards/downwards line would show acceleration/deceleration,
and a horizontal line would show constant speed - you can work out
the acceleration/deceleration in different sections of a velocity-time
graph
◉ average velocity. Answer: = (v+u) ÷ 2
◉ acceleration. Answer: = force ÷ mass (can be rearranged so f=ma)
◉ acceleration (m/s²)
a. Answer: = (final velocity (m/s) - initial velocity (m/s)) ÷ time (s)
= (v-u)÷t
(this is over one stretch)
◉ distance travelled if velocity is changing (s). Answer: = ((v+u) ÷ 2)
Xt
,◉ when we combine the above two formulae:. Answer: 2as = v² - u²
◉ SUVAT. Answer: s, u, v, a, and t are the 5 different things in the 3
above formulae - in any given question, we will probably be given 3
of them, will be asked to find 1, and 1 will be left out - we have to
write down which ones we have and then figure out which equation
to use depending on what we have been given
◉ terminal velocity. Answer: when the weight going downwards is
equal to the air resistance going upwards
◉ a parachutists journey. Answer: as she jumps out of the plane, the
air resistance is little so the weight pulls her downwards, so she
starts to accelerate - as she accelerates the air resistance increases
until it is equal to her weight - this is when terminal velocity is
reached as the two forces are balanced - when she opens her
parachute, she decelerates as there is a much larger air resistance as
the surface area has increased - eventually, the air resistance on the
parachute decreases until it is the same as her weight - a new
terminal velocity has now been reached, just slower than the last
one - until she gets to the ground, where her weight is equal to the
upwards force from the ground
, ◉ Newton's first law of motion. Answer: an object at rest or moving
at a constant velocity will remain so unless acted on by an
unbalanced force
◉ Newton's second law of motion. Answer: the acceleration of an of
an object is due to an unbalanced force and its mass acting on it
◉ Newton's third law of motion. Answer: when two objects interact
with each other they exert equal and opposite forces on each other
◉ explaining law 3. Answer: for every action, there is an equal and
opposite reaction - for example, take the flying motion of birds - a
bird flies by use of its wings, and the wings push air downwards;
since forces result from mutual interactions, the air must also be
pushing the bird upwards - the size of the force on the air equals the
size of the force on the bird; the direction of the force on the air
(downwards) is opposite the direction of the force on the bird
(upwards), and thus action-reaction force pairs make it possible for
birds to fly
◉ inertia. Answer: the tendency of an object not to accelerate
◉ inertial mass. Answer: the mass that stops an object from
accelerating before enough force is applied to make it accelerate
TESTED QUESTIONS AND CORRECT ANSWERS
ALREADY PASSED
◉ velocity-time graphs. Answer: time is always on the x axis, velocity
on the y
an upwards/downwards line would show acceleration/deceleration,
and a horizontal line would show constant speed - you can work out
the acceleration/deceleration in different sections of a velocity-time
graph
◉ average velocity. Answer: = (v+u) ÷ 2
◉ acceleration. Answer: = force ÷ mass (can be rearranged so f=ma)
◉ acceleration (m/s²)
a. Answer: = (final velocity (m/s) - initial velocity (m/s)) ÷ time (s)
= (v-u)÷t
(this is over one stretch)
◉ distance travelled if velocity is changing (s). Answer: = ((v+u) ÷ 2)
Xt
,◉ when we combine the above two formulae:. Answer: 2as = v² - u²
◉ SUVAT. Answer: s, u, v, a, and t are the 5 different things in the 3
above formulae - in any given question, we will probably be given 3
of them, will be asked to find 1, and 1 will be left out - we have to
write down which ones we have and then figure out which equation
to use depending on what we have been given
◉ terminal velocity. Answer: when the weight going downwards is
equal to the air resistance going upwards
◉ a parachutists journey. Answer: as she jumps out of the plane, the
air resistance is little so the weight pulls her downwards, so she
starts to accelerate - as she accelerates the air resistance increases
until it is equal to her weight - this is when terminal velocity is
reached as the two forces are balanced - when she opens her
parachute, she decelerates as there is a much larger air resistance as
the surface area has increased - eventually, the air resistance on the
parachute decreases until it is the same as her weight - a new
terminal velocity has now been reached, just slower than the last
one - until she gets to the ground, where her weight is equal to the
upwards force from the ground
, ◉ Newton's first law of motion. Answer: an object at rest or moving
at a constant velocity will remain so unless acted on by an
unbalanced force
◉ Newton's second law of motion. Answer: the acceleration of an of
an object is due to an unbalanced force and its mass acting on it
◉ Newton's third law of motion. Answer: when two objects interact
with each other they exert equal and opposite forces on each other
◉ explaining law 3. Answer: for every action, there is an equal and
opposite reaction - for example, take the flying motion of birds - a
bird flies by use of its wings, and the wings push air downwards;
since forces result from mutual interactions, the air must also be
pushing the bird upwards - the size of the force on the air equals the
size of the force on the bird; the direction of the force on the air
(downwards) is opposite the direction of the force on the bird
(upwards), and thus action-reaction force pairs make it possible for
birds to fly
◉ inertia. Answer: the tendency of an object not to accelerate
◉ inertial mass. Answer: the mass that stops an object from
accelerating before enough force is applied to make it accelerate
