WGU D115 Advanced Pathophysiology OA Exam
2026/2027 Actual Exam - 450 Questions with
Detailed Rationales | 100% Verified Graded A+
Pass Guaranteed - A+ Graded
Section 1: Cellular Biology/Genetics
Q1: A patient with chronic ischemia presents with shrunken, decreased cellular organelles in
heart muscle cells. Which cellular adaptation occurred?
A. Hypertrophy
B. Hyperplasia
C. Atrophy [CORRECT]
D. Metaplasia
Correct Answer: C
Rationale: Atrophy is a decrease in cell size due to reduced blood supply or workload.
Hypertrophy is an increase in size. Hyperplasia is an increase in number. Metaplasia is a change
in cell type.
Q2: A smoker's bronchial epithelium transforms from ciliated columnar to stratified squamous.
What is this process?
A. Dysplasia
B. Metaplasia [CORRECT]
C. Anaplasia
D. Hyperplasia
Correct Answer: B
Rationale: Metaplasia is a reversible change where one adult cell type replaces another to adapt
to stress, like tobacco smoke. Dysplasia is abnormal, pre-cancerous growth. Anaplasia is
undifferentiated cancer cells. Hyperplasia is increased cell number.
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Q3: A weightlifter develops enlarged left ventricular cardiac muscle cells without cell division.
Which mechanism?
A. Pathologic hyperplasia
B. Physiologic hypertrophy [CORRECT]
C. Pathologic atrophy
D. Physiologic metaplasia
Correct Answer: B
Rationale: Hypertrophy is increased cell size from increased workload; in a weightlifter, it is
physiologic. Hyperplasia requires mitosis. Atrophy is shrinkage. Metaplasia changes cell type.
Q4: A patient with elevated liver enzymes shows an increase in smooth endoplasmic reticulum in
hepatocytes after chronic alcohol use. What is the best explanation?
A. Cellular injury
B. Adaptation [CORRECT]
C. Neoplasia
D. Apoptosis
Correct Answer: B
Rationale: Hypertrophy of the SER is an adaptive mechanism to metabolize alcohol, though it
can lead to pathologic changes like enzyme induction. Neoplasia is tumor growth. Apoptosis is
programmed cell death.
Q5: An endometrial biopsy shows disordered, atypical cells with increased mitoses but no
invasion through the basement membrane. This describes:
A. Metaplasia
B. Hyperplasia
C. Dysplasia [CORRECT]
D. Carcinoma in situ
Correct Answer: C
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Rationale: Dysplia refers to abnormal maturation and atypical cells that remain bounded by the
basement membrane. Carcinoma in situ is severe dysplasia, but dysplasia is the broader term for
this pre-malignant change. Metaplasia is normal cell type change. Hyperplasia is increased
number without atypia.
Q6: A patient presents with severe crushing chest pain. Lab results show elevated cardiac
troponin. What type of cell death is occurring in the myocardium?
A. Coagulative necrosis [CORRECT]
B. Liquefactive necrosis
C. Caseous necrosis
D. Fat necrosis
Correct Answer: A
Rationale: Ischemia in most solid organs (like the heart) causes coagulative necrosis, where cell
architecture is preserved but proteins are denatured. Liquefactive is seen in brain infections.
Caseous is typical of TB. Fat necrosis occurs in pancreatic disease.
Q7: A brain biopsy after a stroke shows complete dissolution of neural tissue, leaving a cystic
space filled with fluid. What type of necrosis?
A. Coagulative
B. Liquefactive necrosis [CORRECT]
C. Gangrenous necrosis
D. Fibrinoid necrosis
Correct Answer: B
Rationale: The brain lacks firm stromal support, so ischemia leads to liquefactive necrosis, where
enzymes dissolve the tissue into a pus-like fluid. Coagulative preserves structure. Gangrene
affects limbs. Fibrinoid affects blood vessels.
Q8: A patient with a long-standing history of tuberculosis has a lung granuloma with a cheese-
like, granular center. What is the necrosis type?
A. Liquefactive
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B. Coagulative
C. Caseous necrosis [CORRECT]
D. Enzymatic fat necrosis
Correct Answer: C
Rationale: Caseous necrosis is a distinct form of coagulative necrosis characteristic of TB
granulomas, appearing cheese-like. Liquefactive is liquid. Enzymatic fat necrosis is from
pancreatic enzymes.
Q9: A patient with acute pancreatitis has saponification of peripancreatic fat. Which necrosis
type explains this finding?
A. Fat necrosis [CORRECT]
B. Coagulative necrosis
C. Caseous necrosis
D. Gangrene
Correct Answer: A
Rationale: Pancreatic lipases released in pancreatitis digest fat into glycerol and fatty acids,
which bind with calcium to form chalky white deposits (saponification), defining fat necrosis.
Caseous is TB. Coagulative is ischemic.
Q10: A diabetic patient presents with a dry, black, mummified toe. What is the
pathophysiological term for this?
A. Wet gangrene
B. Gas gangrene
C. Dry gangrene [CORRECT]
D. Liquefactive necrosis
Correct Answer: C
Rationale: Dry gangrene results from arterial occlusion (common in diabetes), causing
coagulative necrosis that dries out and becomes black without bacterial infection. Wet gangrene
has bacterial superinfection. Gas gangrene is from Clostridium.