1 | P a g e
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www.PlusBay.Plus
,Chapter 1: Arithmetic Needed for Dosage
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MULTIPLE CHOICE am
1. A patient/client was instructed to drink 25 oz of water within 2 hours but was only able to drink 15
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oz. What portion of the water remained?
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a. 2/5
b. 3/5
c. 2/25
d. 25/25
ANS: A a m
Feedback: Subtract the quantity of water the client drank (15 oz) from the total available quantity (
am am am am am am am am am am am am am am am am
25 oz): 10 oz remain. To determine the portion of the water that remains, create a fraction by dividi
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ng 10 oz (remaining portion) by 25 oz (total portion). Therefore, 10 divided by 25 = 10/25. To red
am am am am am am am am am am am am am am am am am am
uce fractions, find the largest number that can be divided evenly into the numerator and the denom
am am am am am am am am am am am am am am am am
inator
(5). Ten divided by 5 (10/5) = 2; 25/5 = 5. The fraction 10/25 can be reduced to its lowest terms of
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2/5.
Format: Multiple Choice Chapt am am am
er: 1 am
Client Needs: Physiological Integrity: Basic Care and Comfort C
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ognitive Level: Apply am am
Difficulty: Moderate am
Page and Header: 2, Dividing Whole Numbers; 3, Fractions Inte
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grated Process: Teaching/Learning
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Objective: 1, 2 am am
2. A patient/client was prescribed 240 W
am mWLWo.
f ETnB
suSreMb.yWmSouth as a supplement but consumed only 1
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00 mL. What portion of the Ensure remained?
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a. 5/12
b. 7/12
c. 100/240
d. 240/240
ANS: B a m
Feedback: Subtract the quantity of Ensure the client consumed (100 mL) from the total available q
am am am am am am am am am am am am am am am
uantity (240 mL): 140 mL remain. To determine the portion of the Ensure that remains, create a fr
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action by dividing 140 mL (remaining portion) by 240 mL (total portion). Therefore, 140 divided b
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y 240 = 7/12. To reduce fractions, find the largest number that can be divided evenly into the nume
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rator and the denominator (20); 140 divided by 20 (140/20) = 7; 240/20 = 12. The fraction 140/240
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can be reduced to its lowest terms of 7/12.
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Format: Multiple Choice Chapt am am am
er: 1 am
Client Needs: Physiological Integrity: Basic Care and Comfort C
am am am am am am am am
ognitive Level: Apply am am
Difficulty: Moderate am
Page and Header: 2, Dividing Whole Numbers; 3, Fractions Inte
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grated Process: Teaching/Learning
am am
Objective: 1, 2 am am
2 | P a g e
am am am am am
www.PlusBay.Plus
,3. A patient/client consumed
am oz. of coffee, 2/3 oz. of ice cream, and am a m a m am am am am am am am am a m
oz. of beef broth. What is the total number of ounces consumed that should be documented for th
a m am am am am am am am am am am am am am am am am am
e patient/client?
am
a. 3 3/4 am
b. 4 5/12 am
c. 4 2/3 am
d. 4 4/9 am
ANS: B a m
Feedback: Add the amount of ounces consumed. First, change any mixed number to a fraction by m
am am am am am am am am am am am am am am am am
ultiplying the whole number by the denominator and then adding that total to the numerator. For the
am am am am am am am am am am am am am am am am am
coffee, 4 2 = 8 + 1 = 9/4; for the beef broth, 2 1
am am am am am am am am am am am am am am am am
= 2 + 1 = 3/2. Then add: 9/4 + 2/3 (ice cream) + 3/2. When fractions have different denominators, fi
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nd the least common denominator (LCD). For 2, 3, and 4, the LCD =
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12. Rewrite each fraction using the LCD; divide the LCD by the denominator of each fraction and th
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en multiply that result by the numerator of the fraction. The new fractions to be added are 27/12 (co
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ffee), 8/12 (ice cream), and 18/12 (beef broth). After conversion of the fractions, the numerators are
am am am am am am am am am am am am am am am am
added together and the fraction is reduced to the lowest terms.
am am am am am am am am am am
Format: Multiple Choice Chapt am am am
er: 1 am
Client Needs: Physiological Integrity: Basic Care and Comfort C
am am am am am am am am
ognitive Level: Analyze am am
Difficulty: Difficult am
Page and Header: 2, Multiplying Whole Numbers; 3, Fractions I
am am am am am am am am am
ntegrated Process: Communication and Documentation Objectiv
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e: 1, 2am am
4. A coffee cup holds 180 mL. The patient/client drank 2? cups of coffee. How many milliliters would
am am am am am am am am am am am am am am am am
the am nurse document as consumed am am am
WWW.TBSM.WS
?
a. 360
b. 420
c. 510
d. 600
ANS: B a m
Feedback: The coffee cup holds 180 mL. The client drank 2? cups. To estimate the total number of
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milliliters consumed, multiply 180 7/3 ( am am am am am am
). When a mixed number is present, change it to an improper fraction by multiplying the whole num
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ber by the denominator and then adding that total to
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the numerator: 2 3 = 6 + 1 = 7/3. Therefore, 180 mL × 7/3 = 420 mL (180 ÷ 3 = 60 × 7 = 420).
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Format: Multiple Choice Chapt am am am
er: 1 am
Client Needs: Physiological Integrity: Basic Care and Comfort C
am am am am am am am am
ognitive Level: Analyze am am
Difficulty: Difficult am
Page and Header: 2, Multiplying Whole Numbers; 3, Fractions I
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ntegrated Process: Communication and Documentation Objectiv
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e: 1, 2am am
5. A patient/client weighed 48.52 kg on admission and now weighs 50.4 kg. How many kilograms w
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ere gained since admission?
am am am
a. 0.78
b. 0.88
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am am am am am
www.PlusBay.Plus
, c. 1.88
d. 1.98
ANS: C a m
Feedback: To estimate the amount of kilograms gained, subtract weight on admission (48.52) from
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current weight (50.4 kg) = 1.88 kg (weight gained). To subtract decimals, decimals are stacked line
am am am am am am am am am am am am am am am
d up. Starting at the far right of the stack, the numbers are subtracted. In the answer, make sure the
am am am am am am am am am am am am am am am am am am am
decimal point lines up exactly with the points above it.
am am am am am am am am am am
Format: Multiple Choice Chapt am am am
er: 1 am
Client Needs: Physiological Integrity: Physiological Adaptation
am am am am am am
Cognitive Level: Apply am am
Difficulty: Moderate am
Page and Header: 10, Decimals Integr
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ated Process: Nursing Process Objectiv
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e: 3, 5
am am
6. A patient/client's sodium intake for one meal was 0.004 g and 0.152 g. How many grams, to
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the nearest hundredths, of sodium were consumed?
am am am am am am
a. 0.15
b. 0.156
c. 0.16
d. 0.166
ANS: C a m
Feedback: To add decimals, stack vertically, making sure that all of the decimal points exactly line
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up. Starting at the far right of the stack, add each vertical column of numbers. In the answer, make
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sure the decimal point lines up exactly with the points above it. To round off a decimal, the final n
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umber is
dropped. Add 0.004 g + 0.152 g = 0W. 1W
5 6Wg.(Tt hBo uSs M
a n.d tWh sSp l a c e ) to determine the total number of grams
am
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the client consumed. When the final number (6) is 5 or greater, drop that number and increase the
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adjacent number (5) by 1. When you want a number rounded off to the nearest hundredth, look at t
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he number in the thousandth place and follow the rounding off rule. Therefore, 0.156 = 0.16 g.
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Format: Multiple Choice Chapt am am am
er: 1 am
Client Needs: Physiological Integrity: Physiological Adaptation
am am am am am am
Cognitive Level: Apply am am
Difficulty: Moderate am
Page and Header: 10, Decimals Integr
am am am am am
ated Process: Teaching/Learning Objec
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tive: 3, 5, 6 am am am
7. A patient/client reports drinking 30% of a 16-
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oz bottle of orange juice. How many ounces did the patient/client drink?
am am am am am am am am am am am
a. 0.18
b. 3.2
c. 4.8
d. 5.3 am
ANS: a m
C
4 | P a g e
am am am am am
www.PlusBay.Plus
am am am am am
www.PlusBay.Plus
,Chapter 1: Arithmetic Needed for Dosage
am am am am am
MULTIPLE CHOICE am
1. A patient/client was instructed to drink 25 oz of water within 2 hours but was only able to drink 15
am am am am am am am am am am am am am am am am am am am a
oz. What portion of the water remained?
m am am am am am am
a. 2/5
b. 3/5
c. 2/25
d. 25/25
ANS: A a m
Feedback: Subtract the quantity of water the client drank (15 oz) from the total available quantity (
am am am am am am am am am am am am am am am am
25 oz): 10 oz remain. To determine the portion of the water that remains, create a fraction by dividi
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ng 10 oz (remaining portion) by 25 oz (total portion). Therefore, 10 divided by 25 = 10/25. To red
am am am am am am am am am am am am am am am am am am
uce fractions, find the largest number that can be divided evenly into the numerator and the denom
am am am am am am am am am am am am am am am am
inator
(5). Ten divided by 5 (10/5) = 2; 25/5 = 5. The fraction 10/25 can be reduced to its lowest terms of
am am am am am am am am am am am am am am am am am am am am am am
2/5.
Format: Multiple Choice Chapt am am am
er: 1 am
Client Needs: Physiological Integrity: Basic Care and Comfort C
am am am am am am am am
ognitive Level: Apply am am
Difficulty: Moderate am
Page and Header: 2, Dividing Whole Numbers; 3, Fractions Inte
am am am am am am am am am
grated Process: Teaching/Learning
am am
Objective: 1, 2 am am
2. A patient/client was prescribed 240 W
am mWLWo.
f ETnB
suSreMb.yWmSouth as a supplement but consumed only 1
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00 mL. What portion of the Ensure remained?
am am am am am am am
a. 5/12
b. 7/12
c. 100/240
d. 240/240
ANS: B a m
Feedback: Subtract the quantity of Ensure the client consumed (100 mL) from the total available q
am am am am am am am am am am am am am am am
uantity (240 mL): 140 mL remain. To determine the portion of the Ensure that remains, create a fr
am am am am am am am am am am am am am am am am am
action by dividing 140 mL (remaining portion) by 240 mL (total portion). Therefore, 140 divided b
am am am am am am am am am am am am am am am
y 240 = 7/12. To reduce fractions, find the largest number that can be divided evenly into the nume
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rator and the denominator (20); 140 divided by 20 (140/20) = 7; 240/20 = 12. The fraction 140/240
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can be reduced to its lowest terms of 7/12.
am am am am am am am am am
Format: Multiple Choice Chapt am am am
er: 1 am
Client Needs: Physiological Integrity: Basic Care and Comfort C
am am am am am am am am
ognitive Level: Apply am am
Difficulty: Moderate am
Page and Header: 2, Dividing Whole Numbers; 3, Fractions Inte
am am am am am am am am am
grated Process: Teaching/Learning
am am
Objective: 1, 2 am am
2 | P a g e
am am am am am
www.PlusBay.Plus
,3. A patient/client consumed
am oz. of coffee, 2/3 oz. of ice cream, and am a m a m am am am am am am am am a m
oz. of beef broth. What is the total number of ounces consumed that should be documented for th
a m am am am am am am am am am am am am am am am am am
e patient/client?
am
a. 3 3/4 am
b. 4 5/12 am
c. 4 2/3 am
d. 4 4/9 am
ANS: B a m
Feedback: Add the amount of ounces consumed. First, change any mixed number to a fraction by m
am am am am am am am am am am am am am am am am
ultiplying the whole number by the denominator and then adding that total to the numerator. For the
am am am am am am am am am am am am am am am am am
coffee, 4 2 = 8 + 1 = 9/4; for the beef broth, 2 1
am am am am am am am am am am am am am am am am
= 2 + 1 = 3/2. Then add: 9/4 + 2/3 (ice cream) + 3/2. When fractions have different denominators, fi
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nd the least common denominator (LCD). For 2, 3, and 4, the LCD =
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12. Rewrite each fraction using the LCD; divide the LCD by the denominator of each fraction and th
am am am am am am am am am am am am am am am am am
en multiply that result by the numerator of the fraction. The new fractions to be added are 27/12 (co
am am am am am am am am am am am am am am am am am am
ffee), 8/12 (ice cream), and 18/12 (beef broth). After conversion of the fractions, the numerators are
am am am am am am am am am am am am am am am am
added together and the fraction is reduced to the lowest terms.
am am am am am am am am am am
Format: Multiple Choice Chapt am am am
er: 1 am
Client Needs: Physiological Integrity: Basic Care and Comfort C
am am am am am am am am
ognitive Level: Analyze am am
Difficulty: Difficult am
Page and Header: 2, Multiplying Whole Numbers; 3, Fractions I
am am am am am am am am am
ntegrated Process: Communication and Documentation Objectiv
am am am am am
e: 1, 2am am
4. A coffee cup holds 180 mL. The patient/client drank 2? cups of coffee. How many milliliters would
am am am am am am am am am am am am am am am am
the am nurse document as consumed am am am
WWW.TBSM.WS
?
a. 360
b. 420
c. 510
d. 600
ANS: B a m
Feedback: The coffee cup holds 180 mL. The client drank 2? cups. To estimate the total number of
am am am am am am am am am am am am am am am am am am
milliliters consumed, multiply 180 7/3 ( am am am am am am
). When a mixed number is present, change it to an improper fraction by multiplying the whole num
am am am am am am am am am am am am am am am am am
ber by the denominator and then adding that total to
am am am am am am am am am
the numerator: 2 3 = 6 + 1 = 7/3. Therefore, 180 mL × 7/3 = 420 mL (180 ÷ 3 = 60 × 7 = 420).
am am am am am am am am am am am am am am am am am am am am am am am am am am am
Format: Multiple Choice Chapt am am am
er: 1 am
Client Needs: Physiological Integrity: Basic Care and Comfort C
am am am am am am am am
ognitive Level: Analyze am am
Difficulty: Difficult am
Page and Header: 2, Multiplying Whole Numbers; 3, Fractions I
am am am am am am am am am
ntegrated Process: Communication and Documentation Objectiv
am am am am am
e: 1, 2am am
5. A patient/client weighed 48.52 kg on admission and now weighs 50.4 kg. How many kilograms w
am am am am am am am am am am am am am am am
ere gained since admission?
am am am
a. 0.78
b. 0.88
3 | P a g e
am am am am am
www.PlusBay.Plus
, c. 1.88
d. 1.98
ANS: C a m
Feedback: To estimate the amount of kilograms gained, subtract weight on admission (48.52) from
am am am am am am am am am am am am am am
current weight (50.4 kg) = 1.88 kg (weight gained). To subtract decimals, decimals are stacked line
am am am am am am am am am am am am am am am
d up. Starting at the far right of the stack, the numbers are subtracted. In the answer, make sure the
am am am am am am am am am am am am am am am am am am am
decimal point lines up exactly with the points above it.
am am am am am am am am am am
Format: Multiple Choice Chapt am am am
er: 1 am
Client Needs: Physiological Integrity: Physiological Adaptation
am am am am am am
Cognitive Level: Apply am am
Difficulty: Moderate am
Page and Header: 10, Decimals Integr
am am am am am
ated Process: Nursing Process Objectiv
am am am am
e: 3, 5
am am
6. A patient/client's sodium intake for one meal was 0.004 g and 0.152 g. How many grams, to
am am am am am am am am am am am am am am am am am
the nearest hundredths, of sodium were consumed?
am am am am am am
a. 0.15
b. 0.156
c. 0.16
d. 0.166
ANS: C a m
Feedback: To add decimals, stack vertically, making sure that all of the decimal points exactly line
am am am am am am am am am am am am am am am am
up. Starting at the far right of the stack, add each vertical column of numbers. In the answer, make
am am am am am am am am am am am am am am am am am am am
sure the decimal point lines up exactly with the points above it. To round off a decimal, the final n
am am am am am am am am am am am am am am am am am am am
umber is
dropped. Add 0.004 g + 0.152 g = 0W. 1W
5 6Wg.(Tt hBo uSs M
a n.d tWh sSp l a c e ) to determine the total number of grams
am
am am am am am am am am am am am am am am am
the client consumed. When the final number (6) is 5 or greater, drop that number and increase the
am am am am am am am am am am am am am am am am am am
adjacent number (5) by 1. When you want a number rounded off to the nearest hundredth, look at t
am am am am am am am am am am am am am am am am am am
he number in the thousandth place and follow the rounding off rule. Therefore, 0.156 = 0.16 g.
am am am am am am am am am am am am am am am am
Format: Multiple Choice Chapt am am am
er: 1 am
Client Needs: Physiological Integrity: Physiological Adaptation
am am am am am am
Cognitive Level: Apply am am
Difficulty: Moderate am
Page and Header: 10, Decimals Integr
am am am am am
ated Process: Teaching/Learning Objec
am am am
tive: 3, 5, 6 am am am
7. A patient/client reports drinking 30% of a 16-
am am am am am am am
oz bottle of orange juice. How many ounces did the patient/client drink?
am am am am am am am am am am am
a. 0.18
b. 3.2
c. 4.8
d. 5.3 am
ANS: a m
C
4 | P a g e
am am am am am
www.PlusBay.Plus
