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FIRST ORDER DIFFERENTIAL EQUATIONS 1

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THIS COURSE, FIRST ORDER DIFFERENTIAL EQUATIONS 1 HELPS STUDENTS LEARN THE COURSE. IT INCLUDES THE COURSE CONTENTS, PERFOMANCE OBJECTIVES, EXAMPLES AND EXERCISE.

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February 14, 2026




First Order Differential Equations 1
Peter. J. Omale
Contents
 Order of differential equations
 Formation of differential equations
 Solution of differential equations by direct integration
 Variable separable form of differential equations
 Homogeneous differential equations

Performance objectives
At the end of this programme, students should be able to:
 State the order of differential equations.
 Form differential equations from given functions.
 Solve differential equations by direct integration.
 Solve differential equations by separating the variables.
 Identify homogeneous differential equations.
 Solve homogeneous differential equations.




Order of differential equations
Any equation which contains differential coefficient(derivative)is called
differential equation. Examples are given below. The order of a differential
equation is given by the highest derivative that is in the equation
For example
dy
+ 3y = 0 is an equation of order 1
dx
2
dy 3
5 2 - y cos x=0 is an equation of order 2
dx
2
3 dy 2
x y 2 + y tan x = 4x is an equation of order 2
dx


Redistribution of this material by photocopying or any other means is prohibited. 1
matrojek

, February 14, 2026



3 2
dy dy
sin x 3 - cos x 2 = 2y is an equation of order 3
dx dx


Formation of differential equations
We form differential equation by differentiating a given function and
eliminating the arbitrary constants.
Example1


Form differential equation from the function
2
y = 3x + 5x + c where c is an arbitrary constant.
Solution
2
y = 3x + 5x + c
Differentiating this, we get
dy
= 6x + 5
dx
Note that differentiating c gives 0, and so the arbitrary constant is
eliminated.
Example 2
Form the associated differential equation from the following function:
y = A cos x - Bsin x
We differentiate the function and eliminate the constants A and B
y = Acos x-Bsin x
dy
= -A sin x-Bcos x
dx
We differentiate again
2
dy
2 = -Acos x+Bsin x = -(Acos x-Bsin x)
dx
To eliminate A and B, we substitute y for the terms containing them.
2
dy
2 = -y
dx
2
dy
2 + y = 0
dx
Redistribution of this material by photocopying or any other means is prohibited. 2
matrojek

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Uploaded on
April 10, 2026
Number of pages
11
Written in
2025/2026
Type
Class notes
Professor(s)
Peter joe omale
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