Indiana Master Electrician Exam Actual Test Questions and
Correct Answers With Rationales LATEST THIS YEAR
Indiana Master Electrician Exam
Exam Coverage Summary
The Indiana Master Electrician Exam is based on the National Electrical Code (NEC) and covers electrical
theory, calculations, and applications. The exam consists of 100 questions with a 5-hour time limit . Key
topic areas include: General Knowledge (Electrical Theory, Load Calculations, Code Definitions, Plan
Reading) – 12%; Services and Service Equipment (Fault Current, Load Calculations, Transformers,
Grounding/Bonding) – 16%; Feeders (Load Calculations, Equipment Grounding) – 4%; Branch Circuits
and Conductors (Overcurrent Protection, GFCI/AFCI, Equipment Grounding) – 16%; Wiring Methods and
Materials (Raceways, Underground, Boxes, Panelboards) – 19%; Equipment and Devices (Luminaires,
Appliances, HVAC) – 10%; Motors and Generators – 8%; and Special Occupancies, Equipment, and
Conditions (Pools, Emergency Systems) – 12% . The exam also tests knowledge of Indiana-specific
statutes (e.g., Mechanics' Lien Law) and local amendments .
Question 1
Ohm's Law is correctly defined by which formula?
A) V = I + R
B) V = I × R
C) V = I / R
D) V = R / I
Correct Answer: B
Summary Rationale: Ohm's Law states that voltage (V) across a resistor equals the current (I) through it
multiplied by the resistance (R), expressed as V = I × R .
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Question 2
A resistor of 100 ohms has 10 volts applied across it. What is the current through the resistor?
A) 0.1 A
B) 1 A
C) 10 A
D) 0.01 A
Correct Answer: A
*Summary Rationale: Using I = V/R, the current equals 10V ÷ 100Ω = 0.1 amperes .*
Question 3
If 2 amperes flows through a resistor with 12 volts across it, what is the resistance?
A) 6 Ω
B) 24 Ω
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C) 8 Ω
D) 10 Ω
Correct Answer: A
*Summary Rationale: Using R = V/I, the resistance equals 12V ÷ 2A = 6 ohms .*
Question 4
What is the voltage across a 50 Ω resistor when 0.5 A of current flows through it?
A) 25 V
B) 100 V
C) 0.25 V
D) 50 V
Correct Answer: A
*Summary Rationale: Using V = I × R, the voltage equals 0.5A × 50Ω = 25 volts .*
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Question 5
Kirchhoff's Voltage Law (KVL) states that:
A) The sum of currents at a node is zero
B) The sum of voltage drops in a closed circuit equals the sum of voltage sources
C) Power is conserved in a circuit
D) Voltage is the product of current and resistance
Correct Answer: B
Summary Rationale: KVL states that the total voltage around any closed loop in a circuit must equal zero,
meaning the sum of voltage drops equals the sum of voltage sources .
Question 6
Kirchhoff's Current Law (KCL) states that:
A) The sum of currents entering a junction equals the sum of currents leaving the junction
B) Voltage drops in a loop equal the supply voltage