CM 2500 Exam 2 - Part 2 (Problems) Proctored
Through Examity | Practice Questions and Answers |
2026 Update | 100% Correct.
Module 5: Shear and Moment | Bending Stress / Exam 2 - Part 2
(Problems) Proctored Through Examity.
1. A simply supported beam of length 10 ft carries a concentrated load of
2000 lb at midspan. What is the maximum shear force?
CORRECT ANSWER: 1000 lb – Rationale: For a symmetric simply
supported beam with a midspan point load, each reaction = P/2 = 1000 lb.
Maximum shear occurs at the supports.
2. For the same beam (10 ft, 2000 lb midspan), what is the maximum
bending moment?
CORRECT ANSWER: 5000 lb-ft – Rationale: Mmax = P×L/4 = (2000×10)/4
= 5000 lb-ft.
3. A cantilever beam of length 6 ft has a point load of 300 lb at its free end.
What is the maximum shear?
CORRECT ANSWER: 300 lb – Rationale: In a cantilever with a free-end
point load, the shear is constant = P = 300 lb throughout.
4. For the same cantilever (6 ft, 300 lb at free end), what is the maximum
bending moment?
, CORRECT ANSWER: 1800 lb-ft – Rationale: Mmax at the fixed end = P×L
= 300×6 = 1800 lb-ft.
5. A simply supported beam of 8 ft carries a uniformly distributed load
(UDL) of 150 lb/ft. What is the maximum shear?
CORRECT ANSWER: 600 lb – Rationale: For UDL, reactions = wL/2 =
(150×8)/2 = 600 lb. Max shear at supports.
6. For the same UDL beam (8 ft, 150 lb/ft), what is the maximum bending
moment?
CORRECT ANSWER: 1200 lb-ft – Rationale: Mmax = wL²/8 = (150×64)/8 =
1200 lb-ft.
7. A beam has a shear diagram that jumps downward at a point load. What
does this indicate?
CORRECT ANSWER: A downward concentrated force – Rationale: The
magnitude of the shear jump equals the magnitude of the point load.
Upward jump = upward force.
8. On a bending moment diagram, where does the maximum moment
occur when shear changes sign?
CORRECT ANSWER: At the point where shear = 0 – Rationale: The slope
of the moment diagram equals the shear. Zero slope (shear=0) indicates a
maximum or minimum moment.
Through Examity | Practice Questions and Answers |
2026 Update | 100% Correct.
Module 5: Shear and Moment | Bending Stress / Exam 2 - Part 2
(Problems) Proctored Through Examity.
1. A simply supported beam of length 10 ft carries a concentrated load of
2000 lb at midspan. What is the maximum shear force?
CORRECT ANSWER: 1000 lb – Rationale: For a symmetric simply
supported beam with a midspan point load, each reaction = P/2 = 1000 lb.
Maximum shear occurs at the supports.
2. For the same beam (10 ft, 2000 lb midspan), what is the maximum
bending moment?
CORRECT ANSWER: 5000 lb-ft – Rationale: Mmax = P×L/4 = (2000×10)/4
= 5000 lb-ft.
3. A cantilever beam of length 6 ft has a point load of 300 lb at its free end.
What is the maximum shear?
CORRECT ANSWER: 300 lb – Rationale: In a cantilever with a free-end
point load, the shear is constant = P = 300 lb throughout.
4. For the same cantilever (6 ft, 300 lb at free end), what is the maximum
bending moment?
, CORRECT ANSWER: 1800 lb-ft – Rationale: Mmax at the fixed end = P×L
= 300×6 = 1800 lb-ft.
5. A simply supported beam of 8 ft carries a uniformly distributed load
(UDL) of 150 lb/ft. What is the maximum shear?
CORRECT ANSWER: 600 lb – Rationale: For UDL, reactions = wL/2 =
(150×8)/2 = 600 lb. Max shear at supports.
6. For the same UDL beam (8 ft, 150 lb/ft), what is the maximum bending
moment?
CORRECT ANSWER: 1200 lb-ft – Rationale: Mmax = wL²/8 = (150×64)/8 =
1200 lb-ft.
7. A beam has a shear diagram that jumps downward at a point load. What
does this indicate?
CORRECT ANSWER: A downward concentrated force – Rationale: The
magnitude of the shear jump equals the magnitude of the point load.
Upward jump = upward force.
8. On a bending moment diagram, where does the maximum moment
occur when shear changes sign?
CORRECT ANSWER: At the point where shear = 0 – Rationale: The slope
of the moment diagram equals the shear. Zero slope (shear=0) indicates a
maximum or minimum moment.
