CHEM 101 General Chemistry Final Exam
2026/2027 | 109 Practice Questions with
Answers on Density, Stoichiometry, Gas
Laws, Titrations, Hydrates & Quantum
Numbers | University-Level Study Guide
Description:
Master CHEM 101 for 2026/2027 with 109 exam-style questions covering density,
significant figures, chromatography, hydrates, stoichiometry, gas laws, acid-base
titrations, thermochemistry, and quantum numbers. Each question includes a correct
answer and clear explanation. Perfect for final exam prep, study guides, and digital
learning.
Download the complete practice exam now and ace your chemistry final.
,CHEM 101 Final Exam 2026/2027: Practice Questions & Answers
Section 1: Density and Physical Properties
Question 1
Severus Snape determines that a powder has a density of 3.00 g/cm³. He requires 3.00 cm³ of
this powder for a potion. What mass in grams does he need?
A) 1.00 g
B) 3.00 g
C) 6.00 g
D) 9.00 g
E) 12.0 g
Answer: D) 9.00 g
Explanation: Mass = density × volume = 3.00 g/cm³ × 3.00 cm³ = 9.00 g.
Question 2
A rock weighs 14.5 kg and has a volume of 141 cm³. Calculate its density in g/cm³.
A) 0.103 g/cm³
B) 10.3 g/cm³
C) 103 g/cm³
D) 1.03 × 10³ g/cm³
E) 1.03 g/cm³
Answer: C) 103 g/cm³
Explanation: Convert mass to grams: 14.5 kg = 14,500 g. Density = 14,500 g / 141 cm³ =
102.8 g/cm³ ≈ 103 g/cm³.
Question 3
A toad with a mass of 13.6 kg is submerged in a large cylinder of water, causing the water
level to rise by 2.50 L. What is the density of the toad in kg/L?
A) 2.72 kg/L
B) 5.44 kg/L
C) 10.9 kg/L
,D) 13.6 kg/L
E) 34.0 kg/L
Answer: B) 5.44 kg/L
Explanation: Volume displaced = 2.50 L. Density = mass/volume = 13.6 kg / 2.50 L = 5.44
kg/L.
Question 4
An object weighing 43.2 g is placed in a graduated cylinder containing 63 mL of water. The
water level rises to 74 mL. What is the density of the object in g/mL?
A) 0.58 g/mL
B) 2.6 g/mL
C) 3.9 g/mL
D) 5.8 g/mL
E) 7.2 g/mL
Answer: C) 3.9 g/mL
Explanation: Volume of object = 74 mL − 63 mL = 11 mL. Density = 43.2 g / 11 mL =
3.927 g/mL ≈ 3.9 g/mL.
Question 5
A rectangular solid has dimensions 4.0 cm × 13 cm × 9.2 cm and a mass of 4.2 kg. What is its
density in g/cm³?
A) 0.88 g/cm³
B) 8.8 g/cm³
C) 88 g/cm³
D) 0.088 g/cm³
E) 880 g/cm³
Answer: B) 8.8 g/cm³
Explanation: Volume = 4.0 × 13 × 9.2 = 478.4 cm³. Mass = 4.2 kg = 4200 g. Density = 4200
g / 478.4 cm³ = 8.78 g/cm³ ≈ 8.8 g/cm³.
, Question 6
A spherical object has a radius of 3.10 cm and a density of 6.12 g/cm³. What is its mass in
grams? (Volume of a sphere = 4/3 π r³)
A) 382 g
B) 509 g
C) 637 g
D) 764 g
E) 891 g
Answer: D) 764 g
Explanation: Volume = (4/3)π(3.10)³ = (4/3)π(29.791) = 124.8 cm³. Mass = 6.12 g/cm³ ×
124.8 cm³ = 764 g.
Question 7
A right circular cylinder has a height of 12.0 cm and a radius of 11.6 cm. The density of a
powder is 8.41 g/cm³. How many grams of powder are needed to fill 14 such cylinders?
Express your answer in kg. (Volume of a cylinder = πr²h)
A) 59.8 kg
B) 149 kg
C) 299 kg
D) 598 kg
E) 1196 kg
Answer: D) 598 kg
Explanation: Volume of one cylinder = π(11.6)²(12.0) = π(134.56)(12.0) = 5071 cm³. Total
volume for 14 cylinders = 14 × 5071 = 70,994 cm³. Mass = 8.41 g/cm³ × 70,994 cm³ =
597,000 g = 597 kg ≈ 598 kg.
Question 8
An iceberg floats in ocean water. Given the density of water is 1.0 g/cm³ and the density of
ice is 0.92 g/cm³, what percentage of the iceberg is submerged?
A) 8%
B) 92%
C) 100%
2026/2027 | 109 Practice Questions with
Answers on Density, Stoichiometry, Gas
Laws, Titrations, Hydrates & Quantum
Numbers | University-Level Study Guide
Description:
Master CHEM 101 for 2026/2027 with 109 exam-style questions covering density,
significant figures, chromatography, hydrates, stoichiometry, gas laws, acid-base
titrations, thermochemistry, and quantum numbers. Each question includes a correct
answer and clear explanation. Perfect for final exam prep, study guides, and digital
learning.
Download the complete practice exam now and ace your chemistry final.
,CHEM 101 Final Exam 2026/2027: Practice Questions & Answers
Section 1: Density and Physical Properties
Question 1
Severus Snape determines that a powder has a density of 3.00 g/cm³. He requires 3.00 cm³ of
this powder for a potion. What mass in grams does he need?
A) 1.00 g
B) 3.00 g
C) 6.00 g
D) 9.00 g
E) 12.0 g
Answer: D) 9.00 g
Explanation: Mass = density × volume = 3.00 g/cm³ × 3.00 cm³ = 9.00 g.
Question 2
A rock weighs 14.5 kg and has a volume of 141 cm³. Calculate its density in g/cm³.
A) 0.103 g/cm³
B) 10.3 g/cm³
C) 103 g/cm³
D) 1.03 × 10³ g/cm³
E) 1.03 g/cm³
Answer: C) 103 g/cm³
Explanation: Convert mass to grams: 14.5 kg = 14,500 g. Density = 14,500 g / 141 cm³ =
102.8 g/cm³ ≈ 103 g/cm³.
Question 3
A toad with a mass of 13.6 kg is submerged in a large cylinder of water, causing the water
level to rise by 2.50 L. What is the density of the toad in kg/L?
A) 2.72 kg/L
B) 5.44 kg/L
C) 10.9 kg/L
,D) 13.6 kg/L
E) 34.0 kg/L
Answer: B) 5.44 kg/L
Explanation: Volume displaced = 2.50 L. Density = mass/volume = 13.6 kg / 2.50 L = 5.44
kg/L.
Question 4
An object weighing 43.2 g is placed in a graduated cylinder containing 63 mL of water. The
water level rises to 74 mL. What is the density of the object in g/mL?
A) 0.58 g/mL
B) 2.6 g/mL
C) 3.9 g/mL
D) 5.8 g/mL
E) 7.2 g/mL
Answer: C) 3.9 g/mL
Explanation: Volume of object = 74 mL − 63 mL = 11 mL. Density = 43.2 g / 11 mL =
3.927 g/mL ≈ 3.9 g/mL.
Question 5
A rectangular solid has dimensions 4.0 cm × 13 cm × 9.2 cm and a mass of 4.2 kg. What is its
density in g/cm³?
A) 0.88 g/cm³
B) 8.8 g/cm³
C) 88 g/cm³
D) 0.088 g/cm³
E) 880 g/cm³
Answer: B) 8.8 g/cm³
Explanation: Volume = 4.0 × 13 × 9.2 = 478.4 cm³. Mass = 4.2 kg = 4200 g. Density = 4200
g / 478.4 cm³ = 8.78 g/cm³ ≈ 8.8 g/cm³.
, Question 6
A spherical object has a radius of 3.10 cm and a density of 6.12 g/cm³. What is its mass in
grams? (Volume of a sphere = 4/3 π r³)
A) 382 g
B) 509 g
C) 637 g
D) 764 g
E) 891 g
Answer: D) 764 g
Explanation: Volume = (4/3)π(3.10)³ = (4/3)π(29.791) = 124.8 cm³. Mass = 6.12 g/cm³ ×
124.8 cm³ = 764 g.
Question 7
A right circular cylinder has a height of 12.0 cm and a radius of 11.6 cm. The density of a
powder is 8.41 g/cm³. How many grams of powder are needed to fill 14 such cylinders?
Express your answer in kg. (Volume of a cylinder = πr²h)
A) 59.8 kg
B) 149 kg
C) 299 kg
D) 598 kg
E) 1196 kg
Answer: D) 598 kg
Explanation: Volume of one cylinder = π(11.6)²(12.0) = π(134.56)(12.0) = 5071 cm³. Total
volume for 14 cylinders = 14 × 5071 = 70,994 cm³. Mass = 8.41 g/cm³ × 70,994 cm³ =
597,000 g = 597 kg ≈ 598 kg.
Question 8
An iceberg floats in ocean water. Given the density of water is 1.0 g/cm³ and the density of
ice is 0.92 g/cm³, what percentage of the iceberg is submerged?
A) 8%
B) 92%
C) 100%
