NEIEP 700 Exam ACTUAL EXAM
2026/2027 | Electrical Fundamentals &
Code Compliance | Verified Q&A |
Pass Guaranteed - A+ Graded
SECTION 1: Basic Electrical Theory (10 Questions)
Q1: A door operator circuit has a 120 VAC power supply. The coil of a door interlock relay has a
resistance of 240 ohms. What is the current flowing through the coil when energized?
A. 0.25 A
B. 0.5 A [CORRECT]
C. 2 A
D. 28,800 A
Solution: Using Ohm's Law, I = E/R = 120V ÷ 240Ω = 0.5 amperes (500 mA).
Distractor A (0.25A): Would result from 120/480 (doubled resistance).
Distractor C (2A): Would result from 240/120 (inverted formula).
Distractor D (28,800A): Incorrectly multiplies V × Ω instead of dividing.
Q2: An elevator car lighting circuit contains three 60-watt incandescent bulbs connected in parallel
across a 120V supply. What is the total current drawn from the supply?
A. 0.5 A
B. 1.0 A
C. 1.5 A [CORRECT]
D. 3.0 A
Solution: Each bulb draws I = P/E = 60W/120V = 0.5A. In parallel, currents add: 0.5A × 3 = 1.5A total.
Alternatively, total power = 180W, so I = 180W/120V = 1.5A.
Distractor A (0.5A): Current for only one bulb.
, Distractor B (1.0A): Incorrectly assumes series connection (120V/180Ω total).
Distractor D (3.0A): Incorrectly adds wattages then divides by voltage wrong (360W/120V) or
uses wrong formula.
Q3: A DC hoist motor armature has a resistance of 0.5 ohms. When connected to a 240V DC supply
during starting (before back-EMF develops), what is the approximate starting current?
A. 120 A
B. 240 A
C. 480 A [CORRECT]
D. 960 A
Solution: At startup, back-EMF = 0, so I = E/R = 240V/0.5Ω = 480A. This is why DC motors require
starting resistors or electronic current limiting.
Distractor A (120A): Incorrectly divides voltage by double the resistance.
Distractor B (240A): Assumes 1 ohm resistance.
Distractor D (960A): Incorrectly multiplies instead of divides.
Q4: Two resistors (10Ω and 40Ω) are connected in series across a 250V supply. What is the voltage drop
across the 40Ω resistor?
A. 50 V
B. 100 V
C. 200 V [CORRECT]
D. 250 V
Solution: Total resistance = 50Ω. Current I = 250V/50Ω = 5A. Voltage across 40Ω = 5A × 40Ω = 200V.
Alternatively, using voltage divider: V₄₀ = 250V × (40/50) = 200V.
Distractor A (50V): Voltage across 10Ω resistor (or 250 × 10/50).
Distractor B (100V): Incorrect average or wrong ratio calculation.
Distractor D (250V): Assumes all voltage drops across one resistor (impossible in series).
Q5: An elevator machine room has a 480V three-phase supply. The phase-to-neutral voltage for control
circuits is:
, A. 208 V
B. 277 V [CORRECT]
C. 347 V
D. 480 V
Solution: For three-phase wye systems, V_phase-neutral = V_line-line ÷ √3 = 480V ÷ 1.732 = 277V. This is
the standard voltage used for elevator control circuits and lighting on 480V systems.
Distractor A (208V): Phase-to-neutral voltage for 208Y/120V systems (208/√3 = 120V).
Distractor C (347V): Incorrectly multiplies 480 × 0.723 or uses wrong formula.
Distractor D (480V): Line-to-line voltage, not phase-to-neutral.
Q6: A capacitor in an elevator drive system has a capacitance of 100μF and is charged to 300V DC. How
much energy is stored in the capacitor?
A. 1.5 J
B. 3.0 J
C. 4.5 J [CORRECT]
D. 9.0 J
Solution: Energy stored in capacitor: E = ½CV² = 0.5 × (100 × 10⁻⁶ F) × (300V)² = 0.5 × 0.0001 × 90,000 =
4.5 joules.
Distractor A (1.5J): Omits the ½ factor or uses wrong voltage.
Distractor B (3.0J): Incorrect calculation using linear instead of squared voltage.
Distractor D (9.0J): Omits the ½ factor in energy formula (uses E = CV²).
Q7: An inductor in a door operator circuit has an inductance of 2H and carries 3A DC current. If the
current is reduced to zero in 0.1 seconds, what is the average induced voltage (EMF)?
A. 6 V
B. 30 V
C. 60 V [CORRECT]
D. 600 V
Solution: Using Faraday's Law: V = L × (ΔI/Δt) = 2H × (3A/0.1s) = 2 × 30 = 60V. The collapsing magnetic
field induces voltage opposing the change.
Distractor A (6V): Incorrectly divides by time twice or uses wrong formula.
2026/2027 | Electrical Fundamentals &
Code Compliance | Verified Q&A |
Pass Guaranteed - A+ Graded
SECTION 1: Basic Electrical Theory (10 Questions)
Q1: A door operator circuit has a 120 VAC power supply. The coil of a door interlock relay has a
resistance of 240 ohms. What is the current flowing through the coil when energized?
A. 0.25 A
B. 0.5 A [CORRECT]
C. 2 A
D. 28,800 A
Solution: Using Ohm's Law, I = E/R = 120V ÷ 240Ω = 0.5 amperes (500 mA).
Distractor A (0.25A): Would result from 120/480 (doubled resistance).
Distractor C (2A): Would result from 240/120 (inverted formula).
Distractor D (28,800A): Incorrectly multiplies V × Ω instead of dividing.
Q2: An elevator car lighting circuit contains three 60-watt incandescent bulbs connected in parallel
across a 120V supply. What is the total current drawn from the supply?
A. 0.5 A
B. 1.0 A
C. 1.5 A [CORRECT]
D. 3.0 A
Solution: Each bulb draws I = P/E = 60W/120V = 0.5A. In parallel, currents add: 0.5A × 3 = 1.5A total.
Alternatively, total power = 180W, so I = 180W/120V = 1.5A.
Distractor A (0.5A): Current for only one bulb.
, Distractor B (1.0A): Incorrectly assumes series connection (120V/180Ω total).
Distractor D (3.0A): Incorrectly adds wattages then divides by voltage wrong (360W/120V) or
uses wrong formula.
Q3: A DC hoist motor armature has a resistance of 0.5 ohms. When connected to a 240V DC supply
during starting (before back-EMF develops), what is the approximate starting current?
A. 120 A
B. 240 A
C. 480 A [CORRECT]
D. 960 A
Solution: At startup, back-EMF = 0, so I = E/R = 240V/0.5Ω = 480A. This is why DC motors require
starting resistors or electronic current limiting.
Distractor A (120A): Incorrectly divides voltage by double the resistance.
Distractor B (240A): Assumes 1 ohm resistance.
Distractor D (960A): Incorrectly multiplies instead of divides.
Q4: Two resistors (10Ω and 40Ω) are connected in series across a 250V supply. What is the voltage drop
across the 40Ω resistor?
A. 50 V
B. 100 V
C. 200 V [CORRECT]
D. 250 V
Solution: Total resistance = 50Ω. Current I = 250V/50Ω = 5A. Voltage across 40Ω = 5A × 40Ω = 200V.
Alternatively, using voltage divider: V₄₀ = 250V × (40/50) = 200V.
Distractor A (50V): Voltage across 10Ω resistor (or 250 × 10/50).
Distractor B (100V): Incorrect average or wrong ratio calculation.
Distractor D (250V): Assumes all voltage drops across one resistor (impossible in series).
Q5: An elevator machine room has a 480V three-phase supply. The phase-to-neutral voltage for control
circuits is:
, A. 208 V
B. 277 V [CORRECT]
C. 347 V
D. 480 V
Solution: For three-phase wye systems, V_phase-neutral = V_line-line ÷ √3 = 480V ÷ 1.732 = 277V. This is
the standard voltage used for elevator control circuits and lighting on 480V systems.
Distractor A (208V): Phase-to-neutral voltage for 208Y/120V systems (208/√3 = 120V).
Distractor C (347V): Incorrectly multiplies 480 × 0.723 or uses wrong formula.
Distractor D (480V): Line-to-line voltage, not phase-to-neutral.
Q6: A capacitor in an elevator drive system has a capacitance of 100μF and is charged to 300V DC. How
much energy is stored in the capacitor?
A. 1.5 J
B. 3.0 J
C. 4.5 J [CORRECT]
D. 9.0 J
Solution: Energy stored in capacitor: E = ½CV² = 0.5 × (100 × 10⁻⁶ F) × (300V)² = 0.5 × 0.0001 × 90,000 =
4.5 joules.
Distractor A (1.5J): Omits the ½ factor or uses wrong voltage.
Distractor B (3.0J): Incorrect calculation using linear instead of squared voltage.
Distractor D (9.0J): Omits the ½ factor in energy formula (uses E = CV²).
Q7: An inductor in a door operator circuit has an inductance of 2H and carries 3A DC current. If the
current is reduced to zero in 0.1 seconds, what is the average induced voltage (EMF)?
A. 6 V
B. 30 V
C. 60 V [CORRECT]
D. 600 V
Solution: Using Faraday's Law: V = L × (ΔI/Δt) = 2H × (3A/0.1s) = 2 × 30 = 60V. The collapsing magnetic
field induces voltage opposing the change.
Distractor A (6V): Incorrectly divides by time twice or uses wrong formula.
