Nicet Level 1 - Water Based Layout
2026 | Comprehensive Q&A For
Certification Success
Where the suction supply is under sufficient pressure to be of material value
without the pump, the pump shall be installed with a _________, which shall be
at least as large as the pipe size required for the discharge pipe. - correct-answer -
Bypass.
Reference NFPA 20 2016, Section 4.15.4.
What is the temp. class and color code for a sprinkler located at a ceiling w/ a max
temp of 150 degrees? - correct-answer -Intermediate, white.
Reference NFPA 13 2016, Table 6.2.5.1.
When conducting a hydrostatic flow test for a new fire sprinkler system, the test
pressure should be _______ psi for ________ hours. - correct-answer -200, 2.
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Reference NFPA 13 2016, Section 25.2.1.1.
Supplementary conditions of a contract contain which of the following: - correct-
answer -Delay agreements, Time and pay schedules, and Addendums. Reference
course content.
Copper tube that has the greatest (largest0 inside diameter for 1 inch. nominal
tube is: - correct-answer -Type M.
Reference NFPA 13 2016, Table A.6.3.5.
Calculate the equivalent length of 4 in. Schedule 40 Black steel pipe of a 90 degree
long turn elbow - correct-answer -6 ft.
Per NFPA 13 2016, Table 23.4.3.1.1, we find the equivalent length for a 4 in.
Schedule 40 Black steel pipe with a 90 0 long-turn elbow is 6 ft.
Determine the maximum spacing permitted for an Extra Hazard hydraulically
calculated system with a density less than 0.25 gpm/ft^2 - correct-answer -15 ft.
Reference NFPA 13 2016, Table 8.6.2.2.1(c)
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In water flow test using two hydrants, ______ pressure is the pressure at the
hydrant where the water is not flowing. - correct-answer -Residual pressure.
Reference NFPA 13 2016, Section A.24.2.2.
NFPA 13 permits branchline hangers to be attached to metal roof decks if the pipe
size doesnt exceed ____ inch(es) - correct-answer -1 in.
Reference NFPA 13 2016, Section 9.2.1.4.1.
How more water can a (17/32) sprinkler deliver than a (1/2) sprinkler? - correct-
answer -Solution #7:
k ½ = 5.6
k 17/32 = 8
Percentage increase: 8 - 5.6 = 43%