Usable power depends on project conditions—primarily, haul-road surface condition, altitude, and
temperature. Underfoot conditions determine how much of the available power can be transferred to
the surface to propel the machine. - Answers true
The coefficient of traction can be defined as the factor by which the total weight of the equipment
should be multiplied to determine the maximum possible tractive force between the wheels or tracks
and the surface just before slipping will occur. - Answers false
Assume that a rubber-tired tractor has a total weight of 25,000 lb on its driving wheels. The maximum
rimpull in low gear is 9,000 lb. If the tractor is operating in wet sand, with a coefficient of traction of
0.30, what is the maximum possible rimpull prior to slippage of the tires? (See Example 6.5 in the
textbook for reference) - Answers 7500 lb
Continue with the previous question, will this tractor slip on this surface? - Answers yes
Assume that a rubber-tired tractor has a total weight of 25,000 lb on its driving wheels. The maximum
rimpull in low gear is 9,000 lb. If the tractor is operating in wet sand, with a coefficient of traction of
0.60, what is the maximum possible rimpull prior to slippage of the tires? - Answers 15000 lb
Continue with the previous question, will this tractor slip on this surface? - Answers no
A wheel tractor scraper is used on a road project. When the project begins, the scraper will
experience high rolling and grade resistance at one work area. The rimpull required to maneuver in
this work area is 65,000 lb. In the fully loaded condition, 48% of the total vehicle weight is on the
drive wheels. The fully loaded vehicle weight is 189,360 lb. Please calculate how much weight is on
the drive wheels. (See Example 6.6 in the textbook for reference) - Answers 90,893 lb
Continue with the previous question, what minimum value of coefficient of traction between the
scraper wheels and the traveling surface is needed to maintain maximum possible travel speed? -
Answers .72
Dozer is good for applications of less than 300ft short haul, and scraper is good for applications of up
to 3,000ft medium haul. - Answers true
An advantage of a crawler dozer as compared with a wheel-type dozer is higher speed. - Answers
false
Which of the following work tasks can be performed by a dozer? - Answers all of the above
The ________________ is very effective for side-casting material, particularly for backfilling or making
sidehill cuts. - Answers angle blade
______________ is a technique whereby the blade end spillage from the first pass or the sidewalls
from previous cuts are used to hold the material in front of the dozer blade on subsequent passes. -
Answers slot dozing
Which of the following factors need to be considered when selecting a proper scraper for your
project? - Answers all of the above
Please match the following three methods of pushing loading scrapers with their corresponding
diagrams? - Answers back-track loading
shuttle loading
chain loading
Articulated trucks consist of two individual frames joined by pin, and can be easily operated over soft
ground. - Answers true
A contractor wants to investigate the production and cost differences of using a 4S blade on a
crawler-type dozer (D4H-4S). The material is dry clay and is to be moved a distance of 150 ft from the
beginning of the cut. The dozing is uphill on a 20% grade. The operator will have average skill. The site
conditions will be dark for visibility. The material weighs 108 pcf in the bank state. Job efficiency is
assumed to be equivalent to a 50-min hour. What is the operator correction factor? - Answers .75
A contractor wants to investigate the production and cost differences of using a 4S blade on a
crawler-type dozer (D4H-4S). The material is dry clay and is to be moved a distance of 150 ft from the
beginning of the cut. The dozing is uphill on a 20% grade. The operator will have average skill. The site
conditions will be dark for visibility. The material weighs 108 pcf in the bank state. Job efficiency is
assumed to be equivalent to a 50-min hour. What is the material-weight correction factor? Assume
the percent swell is 12%. - Answers .88