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The bending or redirection of the travel of the wave when it passes a barrier
without changing the medium in which te wave is traveling is called: - ANSWER
✓ refraction
A patient comes in with a prescription requiring a large amount of plus (+12.50)
and with a notation of vertex distance 12 mm. you find that when fitted with a
frame, the lens will sit 14 mm from the eyes. What change will be necessary in the
lens to be ordered? - ANSWER ✓ Less plus sphere power
When a ray of light travels from one material to another, if its direction of travel is
perpendicular or normal to the interface or junction between the materials, it: -
ANSWER ✓ changes speed but not direction
When a ray of light travels from a less dense (faster) material to a more dense
(slower)material at an angle to the normal, it: - ANSWER ✓ will bend toward the
normal
When a ray of light travels from a more dense (slower) material to a less dense
(faster) material at an angle to the mormal, it" - ANSWER ✓ will bend away from
the normal
In the following prescription, indicate the amount of conventional slab-off needed
to neutralize the vertical prismatic imbalance, The reading level is 10 mm:
RX: OD -5.00 -0.50 x 180
OS -2.75 -0.50 x 180
Add+2.50 - ANSWER ✓ 2.0 prism diopters BU< OD
,The patient is looking 4mm below the distance optical center of the following RX.
What is the prismatic effect and direction?
RX +3.00 -1.00 x 180 - ANSWER ✓ 1.2 base up
Excessive base up prism: - ANSWER ✓ Makes people like they are walking
downhill
If a prism can deviate a ray of light 2 cm at a distance of 4m what would be its
power before - ANSWER ✓ 4 diopters
As the pantoscopic angle is increased: - ANSWER ✓ the optical center should be
raised
If the eyewires touch the patients eyebrows, the adjustment which would be best
take care of this condition would be? - ANSWER ✓ increase pantoscopic tilt
When adjusting the frame, the bifocal height can be lower by using the following
adjustment: - ANSWER ✓ using more pantoscopic tilt
To relieve the pressure causing soreness at the front edge of the nose pads, a good
adjustment would be: - ANSWER ✓ decrease the flare of the pads
If the pads are bent down and the pads are realigned, this adjustment will ; -
ANSWER ✓ raise the front
If the left temple is angled down, this adjustment will: - ANSWER ✓ raise the left
side of the front
If the pad arms are shortened, this adjustment will: - ANSWER ✓ bring the front
closer in
If the pads are brought closer together, this adjustment will: - ANSWER ✓ raise
the front
If the left temple is angled out, this adjustment will: - ANSWER ✓ push the left
side of the front away from the left eye
, To relieve tension on both ears, a good adjustment would be to: - ANSWER ✓
lengthen both temples
In the boxing system, the B measurement represents: - ANSWER ✓ Lens depth
(vertical)
The lower the Abbe number the ______ - ANSWER ✓ less the chromatic
aberration
The cylinder axis location tolerance for a 0.75Dcylinder prescription ophthalmic
lens is: - ANSWER ✓ 5 degrees
The cylinder axis location tolerance for a 1.00D cylinder for prescription
ophthalmic lenses is: - ANSWER ✓ 3 degrees
The cylinder axis location tolerance for a 2.00 D cylinder for prescription
opthalmic lens is: - ANSWER ✓ 2 degrees
The prism power tolerance for uncut multifocal and edged lenses for prescription
ophthalmic lenses is: - ANSWER ✓ + or - 1/3 prism diopter
The prism power tolerance for a mounted pair of eyeglasses in the vertical
meridian for prescription ophthalmic lenses is: - ANSWER ✓ 1/3 prism diopter
The prism tolerance for a mounted pair of eyeglasses in the horizontal meridian
for prescription ophthalmic lenses is: - ANSWER ✓ 2/3 prism diopter
The tolerance for lens thickness when specified for special prescription purposes
is: - ANSWER ✓ 0.3 mm
The correct transposed RX for -1.00-.50x37 is? - ANSWER ✓ -1.50 + 0.50 x 127
The correct transposition for +2.00 -2.00 x 060 is? - ANSWER ✓ Plano +2.00 x
150
An uncut lens must be at least _______ mm in diameter to allow the edging of a
54 mm round lens decentered 3 mm in: - ANSWER ✓ 60 mm