Title: FORCE & PRESSURE – NUMERICALS Class 8 - Part 1
Question: 1
Find the moment of force of 20 N about an axis of rotation at a distance of 0.5 m from
the force.
Solution:
Given:
Force, F = 20 N
Distance d = 0.5 m
Formula:
Moment of Force (τ) = Force (F) × Distance (d)
Substitution:
τ = 20 × 0.5 = 10
Final Answer:
Moment of force, τ = 10 N·m
Question: 2
The moment of a force of 25 N about a point is 2.5 N·m. Find the perpendicular distance
of the force from that point.
Solution:
Given:
Moment of force, τ = 2.5 N·m
Force, F = 25 N
Perpendicular distance, d = ?
Formula:
τ= F x d
Rearrange Formula: d = τ / F
Substitution:
Question: 1
Find the moment of force of 20 N about an axis of rotation at a distance of 0.5 m from
the force.
Solution:
Given:
Force, F = 20 N
Distance d = 0.5 m
Formula:
Moment of Force (τ) = Force (F) × Distance (d)
Substitution:
τ = 20 × 0.5 = 10
Final Answer:
Moment of force, τ = 10 N·m
Question: 2
The moment of a force of 25 N about a point is 2.5 N·m. Find the perpendicular distance
of the force from that point.
Solution:
Given:
Moment of force, τ = 2.5 N·m
Force, F = 25 N
Perpendicular distance, d = ?
Formula:
τ= F x d
Rearrange Formula: d = τ / F
Substitution:
