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Class 8 Physics – Forces and Pressure Numerical Problems (Part 3)

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This document contains Class 8 Physics Forces and Pressure numericals (Part 3) with step-by-step solutions. Prepared as clean typed notes for easy understanding and exam practice.

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Title: FORCE & PRESSURE – NUMERICALS (Part : 3)

Question: 9

How much thrust will be required to exert a pressure of 20,000 pa on an area of 1 cm²?

Solution:

Given:
Pressure, P = 20000 Pa
Area, A = 1 cm²
Thrust (Force), F = ?

Convert area to m² :
1 cm² = 0.0001 m²
So,
A = 0.0001 m²

Formula:
Pressure = Force / Area
P=F/A
Rearrange Formula :
F=P×A

Substitution:
F = 20,000 × 0.0001

Convert decimal to fraction:
0.0001 =
So,
F = 20,000 × (,000)
F = 20,,000
F=2N

Final Answer:
Thrust = 2 N

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