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AIOU 4431 Solved Assignment 1 | Pre-Calculus / Business Mathematics (Updated 2026)

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This document contains complete and accurate solutions to all questions of Assignment 1, prepared according to the AIOU pattern. All questions solved step-by-step Clear explanations for better understanding Proper formulas and methods used Neatly organized and easy to follow Useful for both assignment submission and exam preparation Designed to help students save time and improve performance in AIOU 4431.

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Allama Iqbal Open University
Course Code: 4431
Pre-Calculus / Business Mathematics


Assignment 1 Solved examples for understanding
Or
“Solved Assignment for Study & Exam Preparation Purposes”




1

,Q No:1(a)
For every one of the accompanying assertions, either
demonstrate it is valid or give counter guide to show it is
misleading;
1. The result of two sane numbers is consistently judicious
2. The result of two sane numbers is consistently silly.
3. The result of a non-zero sane and an unreasonable is
dependably silly.
4. The result of two nonsensical numbers is consistently
judicious.

Answer:
Let's analyze each of the statements and determine if they are true or false.

1.The result of two reasonable numbers is dependably
levelheaded.
True.

Proof:
Let 𝑎 and 𝑏 be two rational numbers. By definition, a judicious number
𝑝
can be communicated as the proportion of two whole numbers. So 𝑎 = 𝑞 1 and
1
𝑝2
𝑏= 𝑑2
where 𝑎 and 𝑑 are integers, and 𝑞 ≠ 0 𝑎𝑛𝑑 𝑞 ≠ 0.

The product of 𝒂 and 𝒃 is:
𝑝1 𝑝2 𝑝 1 ×𝑝 2
𝑎×𝑏= × =
𝑞1 𝑞2 𝑞 1 ×𝑞 2

Since 𝑝1 × 𝑝2 and 𝑞1 × 𝑞2 are both integers, the product is a ratio of two
integers, hence rational.

2. The product of two rational numbers is always irrational.
False.

2

, Counterexample:
1 3
Consider the rational number 𝑎 = 2 and 𝑏 = 4.

Their product is:

1 3 3
𝑎×𝑏= × =
2 4 8
3/8 is a normal number, so the result of two levelheaded numbers isn't
unreasonable 100% of the time.

3. The product of a non-zero rational number and an irrational
number is always irrational.
True.

Proof:
Allow r to be a non-zero objective number and x be a silly number. Assume, for
the sake of contradiction, that their product 𝑟 × 𝑥 is rational. Then we can write:

𝑟×𝑥=𝑞

where q is a rational number. Since r is non-zero, we can partition the two sides
by r:
𝑞
𝑥=𝑟
𝑞
Since q and 𝑟 are both rational, 𝑟 is rational. This implies that xxx is rational,
contradicting the assumption that 𝑥 is irrational. In this manner, the result of a
non-zero normal number and an unreasonable number is generally silly.

4. The product of two irrational numbers is always rational.
False.

Counterexample:
Consider the irrational numbers √2 and √3 .

Their product is:

√2 × √3 = √6

3

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