Course Code: 4431
Pre-Calculus / Business Mathematics
Assignment 2 Solved examples for understanding
Or
“Solved Assignment for Study & Exam Preparation Purposes”
1
,Q No: 1(a)
Assuming the numbers 1, 4 and 3 are deducted from three
successive terms of a math movement, the subsequent numbers
are in mathematical movement. Track down the numbers on the
off chance that their aggregate is 21.
Answer:
Let's denote the three consecutive terms of the arithmetic progression
(AP) as and where is the middle term and is the common
difference.
According to the problem, subtracting 1, 4, and 3 from these three consecutive
terms results in a geometric progression (GP). So, the new numbers are:
( ) , ( )
These three terms are in geometric progression. For three terms x, y, and z to be
in geometric progression, the relationship must hold. Therefore, we
have:
( ) ( ) ( )
Simplifying the equation:
Expand the left-hand side:
( ) ( ) ( )( ) ( )
( ) ( )
( )
2
, Expand the right-hand side:
( )
Now, equate the expanded forms:
( )
Cancel out from both sides:
( )
Rearrange the terms:
( )
Factorize the equation:
( )
Find and by using a simpler calculation method.
We know the sum of the terms is 21:
( )
So,
Now, substitute into the previous GP equation:
( )( ) ( )
( )( )
Expand and solve:
Multiply the whole equation by -1:
3