Math 110 Exam 1
All polynomial functions are strength features... - ANS-however the opposite isn't always
genuine! Not all strength capabilities are polynomial capabilities
Avg. Cost - ANS-C(x) / x
Break Even Level - ANS-Where R(x) = C(x) or
Where P(x) = zero
CASE 1: limits with a 0/0 - ANS-This tells you to SIMPLIFY via both:
- factoring
- multiplying by means of the conjugate
- locating a common denominator
CASE 1: The powers are the identical - ANS-Rule: divide coefficients
CASE 2: limits with a #/0 - ANS-If you plug in and get a #/0 :
- The restriction *does now not exist*
- The solution can be infinity, bad infinity or DNE
- visually that is a vertical asymptote
CASE 2: The energy on bottom is larger - ANS-Rule: ZERO
CASE three: The energy on top is larger - ANS-Rule: DNE ( +- infinity)
Chain Rule
spinoff of (f(g(x)) - ANS-f'(g(x)) * g'(x)
Continuity - ANS-A feature is continuous at a factor, a, if it satisfies the subsequent:
1. F(a) exists
2. Lim x>a f(a) exists
3. The restriction = f(a)
Demand p(x) - ANS-p denotes rate and x is the amount produced
E= -p * f'(p) / f(p) - ANS-to find f(p), solve for x
to find f'(p), take spinoff
Elastic, inelastic, unitary - ANS-E > 1, demand is elastic
E < 1, demand is inelastic
All polynomial functions are strength features... - ANS-however the opposite isn't always
genuine! Not all strength capabilities are polynomial capabilities
Avg. Cost - ANS-C(x) / x
Break Even Level - ANS-Where R(x) = C(x) or
Where P(x) = zero
CASE 1: limits with a 0/0 - ANS-This tells you to SIMPLIFY via both:
- factoring
- multiplying by means of the conjugate
- locating a common denominator
CASE 1: The powers are the identical - ANS-Rule: divide coefficients
CASE 2: limits with a #/0 - ANS-If you plug in and get a #/0 :
- The restriction *does now not exist*
- The solution can be infinity, bad infinity or DNE
- visually that is a vertical asymptote
CASE 2: The energy on bottom is larger - ANS-Rule: ZERO
CASE three: The energy on top is larger - ANS-Rule: DNE ( +- infinity)
Chain Rule
spinoff of (f(g(x)) - ANS-f'(g(x)) * g'(x)
Continuity - ANS-A feature is continuous at a factor, a, if it satisfies the subsequent:
1. F(a) exists
2. Lim x>a f(a) exists
3. The restriction = f(a)
Demand p(x) - ANS-p denotes rate and x is the amount produced
E= -p * f'(p) / f(p) - ANS-to find f(p), solve for x
to find f'(p), take spinoff
Elastic, inelastic, unitary - ANS-E > 1, demand is elastic
E < 1, demand is inelastic
