Solution Manual For
Fundamentals and Design of Drug Delivery Systems, A Textbook with Lab Activities Edition 1
By Wujie Zhang
Chapters 1-16
Answers for selected questions
Chapter 1
Q2: 1. Interact with nucleic acids through ionic interactions (forming lipid-nucleic acid complex
plus protection); 2. Promote cellular uptake (e.g., cell membrane fusion/destabilization and
endocytosis).
Chapter 2
Q2: Because of the acidic or alkaline end groups, they are pH-responsive. For example, at low
pH conditions, -COOH groups are protonated (no charge) and are more hydrophobic (less
soluble); while at high pH conditions, -COOH groups are deprotonated, becoming -COO- groups,
which is more hydrophilic (more soluble).
Chapter 3
Q3: a. For IV injection, Cp0 = Cmax = 7.5 mg/L (y-axis intercept of the Cp vs time curve).
b. Vd = dose/ Cp0 = 200 mg / 7.5 mg/L = 26.7 L (remains constant for the same drug)
when Cp0 = 10 mg/L
dose = Vd × Cp0 = 26.7 L × 10 mg/L = 267 mg
Q5: carbonyl group – H-bond;
positively-charged N – ionic interactions;
methyl groups – VDW.
Q6: a. E = F – R + S
S = 0 (100 % inhibition)
R = 71 mg/min
E = Cu × Vu = 1 mg/mL × 1 mL/min = 1 mg/min
ClR = E/Cp = 1 mg/min / 0.6 mg/mL = 1.67 mL/min
b. F = E + R = 72 mg/min
1
, GFR = F/Cp = 72 mg/min / 0.6 mg/mL = 120 mL/min
c. E = 15 mg/mL × 1 mL/min = 15 mg/min
S = E – F + R = (15 -72 +71) = 14 mg/min
d. ClR = E/Cp = 15 mg/mL / 0.6 mg/mL = 25 mL/min
* Change of S doesn’t affect F and R.
Q8:
Q9:
Q10: drug - nicotinamide
Q12: a. Ct = C0 ‒ kt
Ct @5days = 100 mg/mL ‒ 0.1 mg/(mL×hr) × 24 hrs/day × 5days = (100 – 0.1× 24×5) mg/mL
= 88 mg/mL
b. Ct = 0.9C0 = C0 – kt = (100 – 0.1×t) mg/mL = 90 mg/mL
t = 100 hrs
or use the equation: t90 = 0.1C0/k = 0.1× .1 = 100 hrs
Chapter 4
Q1: Gap junctions and desmosomes.
2
Fundamentals and Design of Drug Delivery Systems, A Textbook with Lab Activities Edition 1
By Wujie Zhang
Chapters 1-16
Answers for selected questions
Chapter 1
Q2: 1. Interact with nucleic acids through ionic interactions (forming lipid-nucleic acid complex
plus protection); 2. Promote cellular uptake (e.g., cell membrane fusion/destabilization and
endocytosis).
Chapter 2
Q2: Because of the acidic or alkaline end groups, they are pH-responsive. For example, at low
pH conditions, -COOH groups are protonated (no charge) and are more hydrophobic (less
soluble); while at high pH conditions, -COOH groups are deprotonated, becoming -COO- groups,
which is more hydrophilic (more soluble).
Chapter 3
Q3: a. For IV injection, Cp0 = Cmax = 7.5 mg/L (y-axis intercept of the Cp vs time curve).
b. Vd = dose/ Cp0 = 200 mg / 7.5 mg/L = 26.7 L (remains constant for the same drug)
when Cp0 = 10 mg/L
dose = Vd × Cp0 = 26.7 L × 10 mg/L = 267 mg
Q5: carbonyl group – H-bond;
positively-charged N – ionic interactions;
methyl groups – VDW.
Q6: a. E = F – R + S
S = 0 (100 % inhibition)
R = 71 mg/min
E = Cu × Vu = 1 mg/mL × 1 mL/min = 1 mg/min
ClR = E/Cp = 1 mg/min / 0.6 mg/mL = 1.67 mL/min
b. F = E + R = 72 mg/min
1
, GFR = F/Cp = 72 mg/min / 0.6 mg/mL = 120 mL/min
c. E = 15 mg/mL × 1 mL/min = 15 mg/min
S = E – F + R = (15 -72 +71) = 14 mg/min
d. ClR = E/Cp = 15 mg/mL / 0.6 mg/mL = 25 mL/min
* Change of S doesn’t affect F and R.
Q8:
Q9:
Q10: drug - nicotinamide
Q12: a. Ct = C0 ‒ kt
Ct @5days = 100 mg/mL ‒ 0.1 mg/(mL×hr) × 24 hrs/day × 5days = (100 – 0.1× 24×5) mg/mL
= 88 mg/mL
b. Ct = 0.9C0 = C0 – kt = (100 – 0.1×t) mg/mL = 90 mg/mL
t = 100 hrs
or use the equation: t90 = 0.1C0/k = 0.1× .1 = 100 hrs
Chapter 4
Q1: Gap junctions and desmosomes.
2
