Geschreven door studenten die geslaagd zijn Direct beschikbaar na je betaling Online lezen of als PDF Verkeerd document? Gratis ruilen 4,6 TrustPilot
logo-home
Tentamen (uitwerkingen)

Solution Manual For Introduction to Chemical Engineering Thermodynamics 9e J.M. Smith, Mark Swihart Hendrick C. Van Ness, Michael Abbott

Beoordeling
-
Verkocht
-
Pagina's
1643
Cijfer
A+
Geüpload op
27-04-2026
Geschreven in
2025/2026

This document provides a complete and well-structured Solution Manual for Introduction to Chemical Engineering Thermodynamics, 9th Edition by J.M. Smith, Mark Swihart, Hendrick C. Van Ness, and Michael Abbott. It includes accurate, step-by-step solutions designed to help students understand core thermodynamics concepts such as phase equilibria, energy balances, equations of state, and chemical processes. The content is organized chapter-by-chapter, making it easy to follow complex calculations and apply theoretical principles to real-world engineering problems. This resource is ideal for assignments, exam preparation, and in-depth revision. Perfect for students in chemical engineering seeking reliable academic support aligned with the latest edition.

Meer zien Lees minder
Instelling
Solution Manual For
Vak
Solution Manual For

Voorbeeld van de inhoud

Solution 1.1


Problem Statement



Electric current is the fundamental SI electrical dimension, with the ampere (A) as its unit. Determine units for the

following quantities as combinations of fundamental SI units.


(a) Electric power

(b) Electric charge

(c) Electric potential difference

(d) Electric resistance

(e) Electric capacitance



Solution



(a) Power is power, whether it is electrical, mechanical, or otherwise. Thus, electric power has the usual units of

power:

energy J N m kg m 2
power    
time s s s3

(b) Electric current is by definition the time rate of transfer of electrical charge. Thus

charge
current 
time

or charge  current*time  A s

(you probably recall that the Coulomb is the usual derived unit of charge, defined as 1 A s)



Solution continued on next page…




Copyright © McGraw Hill Education. All rights reserved. No reproduction or distribution without the prior written
consent of McGraw Hill Education.

,(c) Because power is given by the product of current and electric potential,

energy
power   current*electric potential
time

energy kg m2
or electrical potential  
current*time A s3

(you probably recall that this is defined as the volt)



(d) Because (by Ohm’s Law) current is electric potential divided by resistance,

electrical potential kg m2
or resistance   2 3
current A s

(this is defined as the ohm)



(e) Because electric potential is electric charge divided by electric capacitance,

charge
electrical potential 
electrical capacitance

charge As A 2 s4
or electrical capacitance   
electrical potential kg m 2 kg m2
3
As




Solution 1.2


Problem Statement

Liquid/vapor saturation pressure Psat is often represented as a function of temperature by the Antoine equation, which

can be written in the form:

b
log10 P sat / (torr )  a 
t / C  c




Copyright © McGraw Hill Education. All rights reserved. No reproduction or distribution without the prior written
consent of McGraw Hill Education.

,Here, parameters a, b, and c are substance-specific constants. Suppose this equation is to be rewritten in the equivalent

form:

B
ln P sat / kPa  A 
T / K C

Show how the parameters in the two equations are related.




Solution


We must convert both the units and the logarithm (between base 10 and natural logarithm). We know that t in

degrees Celsius is equal to T in Kelvins minus 273.15. Also 1 kPa is equal to 7.50 torr (we might have to look up this

conversion factor). So, we have

a b 
 t /C c   B 
P sat / torr  10  7.5 • P sat / kPa  7.5exp  A  
 T / K  C 
Next, we might recognize that 10 can be written as exp(ln(10)) or exp(2.303). That is how we convert from base 10 log
to natural log in general. So,
  b   B 
exp2.303a    7.5exp A  
  T / K  273.15  c   T / K  C 

Here, I have also substituted T 273.15 for t. Taking the natural log of both sides gives

 b  B
2.303a    ln7.5  A 
 T / K  273.15  c  T /K C

For the two functions to be equal for all values of T, each part of the functions must be the same, so we must have

A = 2.303a ln(7.5) or A = ln(10)*a ln(7.5)

B = 2.303b or B = ln(10)*b

C=c 273.15




Copyright © McGraw Hill Education. All rights reserved. No reproduction or distribution without the prior written
consent of McGraw Hill Education.

, Solution 1.3


Problem Statement



Table B.2 in Appendix B provides parameters for computing the vapor pressure of many substances by the Antoine
sat
equation (see Prob. 1.2). For one of these substances, prepare two plots of P versus T over the range of temperature

sat sat
for which the parameters are valid. One plot should present P on a linear scale and the other should present P on

a log scale.



Problem 1.2


Liquid/vapor saturation pressure Psat is often represented as a function of temperature by the Antoine equation, which

can be written in the form:

b
log10 P sat / (torr )  a 
t / C  c

Here, parameters a, b, and c are substance-specific constants. Suppose this equation is to be rewritten in the equivalent

form:

B
ln P sat / kPa  A 
T / K C

Show how the parameters in the two equations are related.



Solution


The point of this problem is just for you to practice evaluating and plotting a simple function. You will do many

problems over the course of the semester (and many more over the course of your career) in which the results are best

presented in graphical form. The only thing to be careful of in plotting the Antoine equation is to pay attention to the
sat
units of T and P and to whether the constants are given for use with the base 10 logarithm or the natural logarithm.


Solution continued on next page…



Copyright © McGraw Hill Education. All rights reserved. No reproduction or distribution without the prior written
consent of McGraw Hill Education.

Geschreven voor

Instelling
Solution Manual For
Vak
Solution Manual For

Documentinformatie

Geüpload op
27 april 2026
Aantal pagina's
1643
Geschreven in
2025/2026
Type
Tentamen (uitwerkingen)
Bevat
Vragen en antwoorden

Onderwerpen

$17.99
Krijg toegang tot het volledige document:

Verkeerd document? Gratis ruilen Binnen 14 dagen na aankoop en voor het downloaden kun je een ander document kiezen. Je kunt het bedrag gewoon opnieuw besteden.
Geschreven door studenten die geslaagd zijn
Direct beschikbaar na je betaling
Online lezen of als PDF

Maak kennis met de verkoper

Seller avatar
De reputatie van een verkoper is gebaseerd op het aantal documenten dat iemand tegen betaling verkocht heeft en de beoordelingen die voor die items ontvangen zijn. Er zijn drie niveau’s te onderscheiden: brons, zilver en goud. Hoe beter de reputatie, hoe meer de kwaliteit van zijn of haar werk te vertrouwen is.
StuviaGuides West Virgina University
Volgen Je moet ingelogd zijn om studenten of vakken te kunnen volgen
Verkocht
16182
Lid sinds
7 jaar
Aantal volgers
8362
Documenten
5972
Laatst verkocht
16 uur geleden
Accounting, Finance, Statistics, Computer Science, Nursing, Chemistry, Biology & More — A+ Test Banks, Study Guides & Solutions

As a Top 1st Seller on Stuvia and a nursing professional, my mission is to be your light in the dark during nursing school and beyond. I know how stressful exams and assignments can be, which is why I’ve created clear, reliable, and well-structured resources to help you succeed. I offer test banks, study guides, and solution manuals for all subjects — including specialized test banks and solution manuals for business books. My materials have already supported countless students in achieving higher grades, and I want them to be the guide that makes your academic journey easier too. I’m passionate, approachable, and always focused on quality — because I believe every student deserves the chance to excel.

Lees meer Lees minder
4.3

2292 beoordelingen

5
1569
4
305
3
183
2
74
1
161

Recent door jou bekeken

Waarom studenten kiezen voor Stuvia

Gemaakt door medestudenten, geverifieerd door reviews

Kwaliteit die je kunt vertrouwen: geschreven door studenten die slaagden en beoordeeld door anderen die dit document gebruikten.

Niet tevreden? Kies een ander document

Geen zorgen! Je kunt voor hetzelfde geld direct een ander document kiezen dat beter past bij wat je zoekt.

Betaal zoals je wilt, start meteen met leren

Geen abonnement, geen verplichtingen. Betaal zoals je gewend bent via iDeal of creditcard en download je PDF-document meteen.

Student with book image

“Gekocht, gedownload en geslaagd. Zo makkelijk kan het dus zijn.”

Alisha Student

Bezig met je bronvermelding?

Maak nauwkeurige citaten in APA, MLA en Harvard met onze gratis bronnengenerator.

Bezig met je bronvermelding?

Veelgestelde vragen