Marking Scheme
Class X Session 2024-25
MATHEMATICS STANDARD (Code No.041)
TIME: 3 hours MAX.MARKS: 80
Q.No. Section A Marks
1. D) -6,6 1
2. B) -5 1
3. D) From a point inside a circle only two tangents can be drawn. 1
4. A) 7 1
5. B) 20 cm 1
6. 11 1
A)
9
7. C) 140𝑂 1
8. B) 8𝑥 2 - 20 1
9. C) 30 1
10. B) isosceles and similar 1
11. A) Irrational and distinct 1
12. 3 1
C)
√3
13. 594 1
B)
7
14. 3 1
B)
8
15. B) (-4, 0) 1
16. A) median 1
17. C) (3,0) 1
18. 3 1
D)
26
19. B) 1
20. D) 1
1
, Section B
21. (A) 480 = 25 x 3 x 5 ½
720 = 24 x 32 x 5 ½
LCM (480,720) = 25 x 32 x 5 = 1440 ½
HCF (480, 720) = 24 x 3x 5 = 240 ½
OR
85 = 5x17, 238 = 2x7x17
(B)
HCF( 85, 238) = 17 1
17 = 85xm -238
m=3 1
22.(A) Total number of possible outcomes = 6x6=36 ½
For a product to be odd, both the numbers should be odd.
Favourable outcomes are (7,7) (7,9) (7,11) (9,7) (9,9) (9, 11) (11,7) (11,9)
(11,11)
no. of favourable outcomes = 9
9 1 1
P (product is odd) = or ½
36 4
OR
(B) ½
Total number of three-digit numbers = 900.
Numbers with hundredth digit 8 & and unit’s digit 5 are 805,815,
1
825,....,895
Number of favourable outcomes = 10 ½
10 1
P(selecting one such number) = or
900 90
23. √3 2 1 2 1½
2 ( ) −( )
2 √3
2
(√2)
7 ½
=
12
24 Let the required point be (x,0) ½
√(8 − 𝑥)2 + 25 = √41 ½
=> (8 − 𝑥)2 = 16
=> 8 - x =土4
=> x = 4 , 12
Two points on the x-axis are (4,0) & (12,0). 1
2
Class X Session 2024-25
MATHEMATICS STANDARD (Code No.041)
TIME: 3 hours MAX.MARKS: 80
Q.No. Section A Marks
1. D) -6,6 1
2. B) -5 1
3. D) From a point inside a circle only two tangents can be drawn. 1
4. A) 7 1
5. B) 20 cm 1
6. 11 1
A)
9
7. C) 140𝑂 1
8. B) 8𝑥 2 - 20 1
9. C) 30 1
10. B) isosceles and similar 1
11. A) Irrational and distinct 1
12. 3 1
C)
√3
13. 594 1
B)
7
14. 3 1
B)
8
15. B) (-4, 0) 1
16. A) median 1
17. C) (3,0) 1
18. 3 1
D)
26
19. B) 1
20. D) 1
1
, Section B
21. (A) 480 = 25 x 3 x 5 ½
720 = 24 x 32 x 5 ½
LCM (480,720) = 25 x 32 x 5 = 1440 ½
HCF (480, 720) = 24 x 3x 5 = 240 ½
OR
85 = 5x17, 238 = 2x7x17
(B)
HCF( 85, 238) = 17 1
17 = 85xm -238
m=3 1
22.(A) Total number of possible outcomes = 6x6=36 ½
For a product to be odd, both the numbers should be odd.
Favourable outcomes are (7,7) (7,9) (7,11) (9,7) (9,9) (9, 11) (11,7) (11,9)
(11,11)
no. of favourable outcomes = 9
9 1 1
P (product is odd) = or ½
36 4
OR
(B) ½
Total number of three-digit numbers = 900.
Numbers with hundredth digit 8 & and unit’s digit 5 are 805,815,
1
825,....,895
Number of favourable outcomes = 10 ½
10 1
P(selecting one such number) = or
900 90
23. √3 2 1 2 1½
2 ( ) −( )
2 √3
2
(√2)
7 ½
=
12
24 Let the required point be (x,0) ½
√(8 − 𝑥)2 + 25 = √41 ½
=> (8 − 𝑥)2 = 16
=> 8 - x =土4
=> x = 4 , 12
Two points on the x-axis are (4,0) & (12,0). 1
2
